blocks|key|1559243|text|您可以使用keyboard模块并将键按事件绑定到一个函数：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1559244|import+keyboard++#+using+module+keyboard

def+myonkeypress(event):
++++if+event.name.isnumeric()+:
+++++++print('User+pressed+numeric+key')

#+hook+event+handler
keyboard.on_press(myonkeypress)|code-block|syntax|javascript|1559245|entityMap^0|5|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can use the <code>keyboard</code> module and bind the key press event to a function:
<pre><code>import keyboard # using module keyboard

def myonkeypress(event):
 if event.name.isnumeric() :
 print('User pressed numeric key')

# hook event handler
keyboard.on_press(myonkeypress)
</code></pre>

blocks|key|3105479|text|您可以将键码转换为它所表示的字符，然后检查它是否是带有is位()的数字。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3105480|if+event.type+==+pygame.KEYDOWN:
++++if+pygame.key.name(event.key).isdigit():
++++++++pass+#+Do+stuff|code-block|syntax|javascript|3105481|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could convert the keycode to it's representing character, then check if it is a digit with isdigit().
<pre class="lang-py prettyprint-override"><code>if event.type == pygame.KEYDOWN:
 if pygame.key.name(event.key).isdigit():
 pass # Do stuff
</code></pre>

blocks|key|3105537|text|我从来没有使用过Python，但是有一个内置函数可以帮助您：isinstance()。(文档：https://docs.python.org/3.9/library/functions.html#isinstance)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3105538|它检查给定对象是str、int等，返回True或False。它的工作方式如下：|3105539|x+=+5
if+isinstance(x,+int):
++++do_this()|code-block|syntax|javascript|3105540|这就是说，有一个问题:虽然我从来没有使用过游戏，但我读过它的docs+(http://www.pygame.org/docs/ref/key.html)。它规定如下：|3105541|3105542|键常量的整数在py对策1和2之间有所不同。请始终使用键常量(K_a)而不是直接(97)整数，这样您的密钥处理代码就可以很好地在py对策1和pygame+2上工作。|blockquote|3105543|3105544|3105545|所以我想你最好使用与isinstance()不同的东西。类似于：|3105546|[...]
def+welcome_screen(run):
++++clock.tick(fps)+
++++gameWindow.fill(grey)
++++while+not+run:
++++++++for+event+in+pygame.event.get():
++++++++++++if+event.type+==+pygame.QUIT:
+++++++++++++++++run+=+True
++++++++++++if+event.type+==+pygame.KEYDOWN:
++++++++++++++++if+event.key+in+[pygame.K_1,+pygame.K_2]:
+++++++++++++++++++++pass
++++++++pygame.display.update()|3105547|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3.9/library/functions.html#isinstance|1|http://www.pygame.org/docs/ref/key.html^0|U|C|1B|1P|0|0|8|3|C|3|J|4|O|5|0|0|10|13|1|0|0|0|0|0|A|C|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@$9|1B|A|1C|1|1D]]|E|$]]|$1|F|3|G|5|6|7|1E|8|@$9|1F|A|1G|B|C]|$9|1H|A|1I|B|C]|$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|1N|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1O|8|@]|D|@$9|1P|A|1Q|1|1R]]|E|$]]|$1|O|3|-4|5|6|7|1S|8|@]|D|@]|E|$]]|$1|P|3|Q|5|R|7|1T|8|@]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1U|8|@]|D|@]|E|$]]|$1|T|3|-4|5|6|7|1V|8|@]|D|@]|E|$]]|$1|U|3|V|5|6|7|1W|8|@$9|1X|A|1Y|B|C]]|D|@]|E|$]]|$1|W|3|X|5|J|7|1Z|8|@]|D|@]|E|$K|L]]|$1|Y|3|-4|5|6|7|20|8|@]|D|@]|E|$]]]|Z|$10|$5|11|12|13|E|$14|15]]|16|$5|11|12|13|E|$14|17]]]]

I've never worked with pygame, but there is a Python built-in function that may help you: <code>isinstance()</code>. (Docs: <a href="https://docs.python.org/3.9/library/functions.html#isinstance" rel="nofollow noreferrer">https://docs.python.org/3.9/library/functions.html#isinstance</a>)
It checks if a given object is <code>str</code>, <code>int</code> etc. Returns <code>True</code> or <code>False</code>. It works like this:
<pre class="lang-py prettyprint-override"><code>x = 5
if isinstance(x, int):
 do_this()
</code></pre>
That said, there is a catch: although I have never used pygame, I read its docs (<a href="http://www.pygame.org/docs/ref/key.html" rel="nofollow noreferrer">http://www.pygame.org/docs/ref/key.html</a>). It states the following:
<blockquote>
The integers for key constants differ between pygame 1 and 2. Always use key constants (K_a) rather than integers directly (97) so that your key handling code works well on both pygame 1 and pygame 2.
</blockquote>
So I guess you'd better use something different from <code>isinstance()</code>. Something like:
<pre class="lang-py prettyprint-override"><code>[...]
def welcome_screen(run):
 clock.tick(fps) 
 gameWindow.fill(grey)
 while not run:
 for event in pygame.event.get():
 if event.type == pygame.QUIT:
 run = True
 if event.type == pygame.KEYDOWN:
 if event.key in [pygame.K_1, pygame.K_2]:
 pass
 pygame.display.update()

</code></pre>

blocks|key|1559377|text|为了获得数字键，我建议首先检查，如果没有按下修改键。例如，如果按SHIFT+%2B+1，取决于您的键盘，您可能会得到一个感叹号(!)，而不是1的实际数字。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1559378|为了做到这一点，并得到按下的键的整数值，我们可以执行以下操作：|1559379|if+event.type+==+pygame.KEYDOWN:
++++#+Check+if+no+modifier+keys+are+pressed+(for+example:+SHIFT):
++++if+event.mod+==+pygame.KMOD_NONE:
++++++++#+event.key+returns+the+ASCII+code+of+the+key,+we+can+find+out+if+it+is+numeric+by+checking+if
++++++++#+the+ASCII+value+of+the+key+is+between+the+ASCII+value+of+'0'+and+'9'
++++++++if+pygame.K_0+<=+event.key+<=+pygame.K_9:
++++++++++++#+Store+the+pressed+key+into+a+variable
++++++++++++pressed_digit+=+event.key+-+pygame.K_0
++++++++++++#+Do+something+with+it
++++++++++++print(f'Key+pressed:+{pressed_digit}')|code-block|syntax|javascript|1559380|entityMap^0|W|5|14|1|1Q|1|1W|1|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|N|$]]

In order to get the numeric key, I suggest to check first, if no modifying key was pressed. For example, if we press <code>SHIFT</code> + <code>1</code>, depending on your keyboard, you probably will get an exclamation mark (<code>!</code>), not the actual digit of <code>1</code>.
In order to do this, and also get the integer value of the pressed key, we can do the following:
<pre><code>if event.type == pygame.KEYDOWN:
 # Check if no modifier keys are pressed (for example: SHIFT):
 if event.mod == pygame.KMOD_NONE:
 # event.key returns the ASCII code of the key, we can find out if it is numeric by checking if
 # the ASCII value of the key is between the ASCII value of '0' and '9'
 if pygame.K_0 &lt;= event.key &lt;= pygame.K_9:
 # Store the pressed key into a variable
 pressed_digit = event.key - pygame.K_0
 # Do something with it
 print(f'Key pressed: {pressed_digit}')
</code></pre>

I am making a Calculator with Pygame and I want to check if the user has pressed a key which is an integer. If the key is an integer like 1 or 2 then blit the number onto the screen.
I have tried but many times but failed
Here's my code
<pre><code>import pygame, math

pygame.init()
screen_width = 1200
screen_height = 500
gameWindow = pygame.display.set_mode((screen_width, screen_height))
pygame.display.set_caption('Calculator')
red = (255, 0, 0)
green = (0, 255, 0)
blue = (0, 0, 255)
white = (255, 255, 255)
black = (0, 0, 0)
grey = (128, 128, 128)
font = pygame.font.SysFont('comicsans', 40)
fps = 60
clock = pygame.time.Clock()

def text_screen(text, color, x, y):
 screen_text = font.render(text, True, color)
 gameWindow.blit(screen_text, [x ,y])

def welcome_screen(run):
 clock.tick(fps) 
 gameWindow.fill(grey)
 while not run:
 for event in pygame.event.get():
 if event.type == pygame.QUIT:
 run = True
 if event.type == pygame.KEYDOWN:
 if event.key == # Code to check whether the key is integer or not:
 pass
 pygame.display.update()

def gameLoop(run):
 clock.tick(fps)
 gameWindow.fill(grey)
 while not run:
 for event in pygame.event.get():
 if event.type == pygame.QUIT:
 run = True
 pygame.display.update()

if __name__ == &quot;__main__&quot;:
 welcome_screen(False)
</code></pre>

How to detect if a user has typed an integer on their keyboard in pygame?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在用Pygame制作一个计算器，我想检查用户是否按下了一个整数键。如果键是像1或2这样的整数，那么将这个数字放到屏幕上。我试过很多次，但都失败了这是我的密码import pygame, mathpygame.init()screen_width = 1200screen_height = 500gameWindow...

问如何检测用户是否在电子游戏中在键盘上键入了整数？
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问如何检测用户是否在电子游戏中在键盘上键入了整数？EN