我对python中的wget模块有问题。
我对python中的wget模块有问题。
提问于 2022-01-16 18:25:33
有人能破解我的密码吗？我也太乞丐了，如果你告诉我如何更有效率地做这件事，而不必为每种文件类型创建不同的函数，我会很高兴的。
(你可以把这段代码看作是上世纪90年代一个研究机构的终端，当时互联网还不太好，所以我想放慢下载速度，让人感觉它真的是90年代了。)
import wget
x = ""
def png_download():
print("this code is can only download png btw")
time.sleep(1)
print("enter url")
command = input('Terminal: ').strip()
command = x
# file url
remote_url = ("'"+x+"'")
#
local_file = 'file.png'
# aksiyon
wget.download(remote_url, local_file)
while True: #Terminal
print ("")
command = input('Terminal: ').strip()
if command == 'Download_png':
png_download()
else:
print("") 如果运行代码并输入url，就会发生这样的情况：
File "c:\Dosyalar\Yazılım\Python\Foundation Terminal 14\Terminal Downloader Extension ENG .py", line 28, in <module>
png_download()
File "c:\Dosyalar\Yazılım\Python\Foundation Terminal 14\Terminal Downloader Extension ENG .py", line 22, in png_download
wget.download(remote_url, local_file)
File "C:\Users\hp\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.9_qbz5n2kfra8p0\LocalCache\local-packages\Python39\site-packages\wget.py", line 526, in download
(tmpfile, headers) = ulib.urlretrieve(binurl, tmpfile, callback)
File "C:\Program Files\WindowsApps\PythonSoftwareFoundation.Python.3.9_3.9.2544.0_x64__qbz5n2kfra8p0\lib\urllib\request.py", line 239, in urlretrieve
with contextlib.closing(urlopen(url, data)) as fp:
File "C:\Program Files\WindowsApps\PythonSoftwareFoundation.Python.3.9_3.9.2544.0_x64__qbz5n2kfra8p0\lib\urllib\request.py", line 214, in urlopen
return opener.open(url, data, timeout)
File "C:\Program Files\WindowsApps\PythonSoftwareFoundation.Python.3.9_3.9.2544.0_x64__qbz5n2kfra8p0\lib\urllib\request.py", line 501, in open
req = Request(fullurl, data)
File "C:\Program Files\WindowsApps\PythonSoftwareFoundation.Python.3.9_3.9.2544.0_x64__qbz5n2kfra8p0\lib\urllib\request.py", line 320, in __init__
self.full_url = url
File "C:\Program Files\WindowsApps\PythonSoftwareFoundation.Python.3.9_3.9.2544.0_x64__qbz5n2kfra8p0\lib\urllib\request.py", line 346, in full_url
self._parse()
File "C:\Program Files\WindowsApps\PythonSoftwareFoundation.Python.3.9_3.9.2544.0_x64__qbz5n2kfra8p0\lib\urllib\request.py", line 375, in _parse
raise ValueError("unknown url type: %r" % self.full_url)
ValueError: unknown url type: '%27%27' ```回答 2
Stack Overflow用户
回答已采纳
发布于 2022-01-17 08:31:43
ValueError:未知url类型：'%27%27‘
27是'字符的(十六进制)代码，这意味着您为wget.download提供的第一个参数是''，这显然不是合法地址。这是因为您将x设置为空字符串(x = "")，但没有对其进行任何更改，然后执行了。
remote_url = ("'"+x+"'")和
wget.download(remote_url, local_file)假设用户总是提供合法的URL，那么您的png_download应该修改为
def png_download():
print("this code is can only download png btw")
time.sleep(1)
print("enter url")
remote_url = input('Terminal: ').strip()
#
local_file = 'file.png'
# aksiyon
wget.download(remote_url, local_file)Stack Overflow用户
发布于 2022-01-16 18:35:27
用Python下载文件的方法要简单得多：
import os
import requests
def download_file_to(file_url, destination_folder, new_file_name=None):
if new_file_name:
file_name = new_file_name
else:
file_name = file_url.split("/")[-1]
r = requests.get(file_url)
file_path = os.path.join(destination_folder, file_name)
with open(file_path, "wb") as code:
code.write(r.content)此方法将从web (使用requests库)将任何文件下载到指定的文件夹中，如果愿意，可以重命名该文件。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/70732934
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