blocks|key|2663640|text|受this的启发(它似乎只适用于Unix系统)，您可以通过signal.alarm()超时函数调用。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2663641|import+getpass
import+signal


def+timeout(signum,+frame):
++++print('Timeout!')
++++exit()


def+get_user_password():
++++upass+=+getpass.getpass()
++++return+upass


if+__name__+==+"__main__":
++++signal.signal(signal.SIGALRM,+timeout)
++++timeout_in_s+=+10

++++signal.alarm(timeout_in_s)
++++upass+=+get_user_password()
++++signal.alarm(0)++#+Stop+alarm|code-block|syntax|javascript|2663642|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/492519/timeout-on-a-function-call^0|T|E|1|4|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

Inspired by <a href="https://stackoverflow.com/questions/492519/timeout-on-a-function-call">this</a> (which only seems to only work on Unix systems), you can timeout a function call by <code>signal.alarm()</code>
<pre><code>import getpass
import signal


def timeout(signum, frame):
 print('Timeout!')
 exit()


def get_user_password():
 upass = getpass.getpass()
 return upass


if __name__ == &quot;__main__&quot;:
 signal.signal(signal.SIGALRM, timeout)
 timeout_in_s = 10

 signal.alarm(timeout_in_s)
 upass = get_user_password()
 signal.alarm(0) # Stop alarm
</code></pre>

blocks|key|2354967|text|这不是一个完美的解决方案，但您可以尝试使用多处理：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2354968|import+multiprocessing
import+queue


def+take_input(q):
++++stdin+=+open(0)
++++print("Enter+your+input:+(y/n)+>>+",+end="",+flush=True)
++++user_input+=+stdin.readline()
++++q.put(user_input)


def+confirm_user_input():
++++value+=+''
++++if+__name__+==+"__main__":
++++++++q+=+multiprocessing.Queue()
++++++++process+=+multiprocessing.Process(target=take_input,+args=(q,))
++++++++process.start()
++++++++try:
++++++++++++value+=+q.get(timeout=10)
++++++++except+queue.Empty:
++++++++++++print("no+input...")
++++++++process.terminate()
++++++++process.join()

++++++++if+value.strip()+==+'y':
++++++++++++print("confirmed:+do+something+in+this+case...")
++++++++else:
++++++++++++print("not+confirmed:+do+something+else+in+that+case...")


confirm_user_input()|code-block|syntax|javascript|2354969|它不使用input()，但它等待响应n秒钟，如果没有输入，则继续使用其他的内容，并且不需要Unix系统。请记住，它需要在main中。否则，您应该从主程序中调用它，如下所示：|offset|length|style|BOLD|2354970|if+__name__+==+'__main__':
+++++freeze_support()
+++++confirm_user_input()|2354971|在这种情况下，从函数中删除if+__name__+==+"__main__":。也许您可以在代码中实现它。|CODE|2354972|entityMap^0|0|0|1O|4|0|0|D|Q|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|V|8|@$I|W|J|X|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Z|8|@$I|10|J|11|K|Q]]|9|@]|A|$]]|$1|R|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|S|$]]

It's not a perfect solution, but you could try using multiprocessing:
<pre><code>import multiprocessing
import queue


def take_input(q):
 stdin = open(0)
 print(&quot;Enter your input: (y/n) &gt;&gt; &quot;, end=&quot;&quot;, flush=True)
 user_input = stdin.readline()
 q.put(user_input)


def confirm_user_input():
 value = ''
 if __name__ == &quot;__main__&quot;:
 q = multiprocessing.Queue()
 process = multiprocessing.Process(target=take_input, args=(q,))
 process.start()
 try:
 value = q.get(timeout=10)
 except queue.Empty:
 print(&quot;no input...&quot;)
 process.terminate()
 process.join()

 if value.strip() == 'y':
 print(&quot;confirmed: do something in this case...&quot;)
 else:
 print(&quot;not confirmed: do something else in that case...&quot;)


confirm_user_input()

</code></pre>
This doesn't use input(), but it waits for response for n seconds and if there's no input, continues with something else and it doesn't require Unix system. Keep in mind it needs to be in main. Otherwise you should call it from the main with something like this:
<pre><code>if __name__ == '__main__':
 freeze_support()
 confirm_user_input()
</code></pre>
In that case remove <code>if __name__ == &quot;__main__&quot;:</code> from the function.
May be you could implement it in your code.

I'm writing a Python application and would like to prompt a user for their password. If they do not enter it within 60 seconds, the program should exit. If they do enter it, their password should be hidden in the terminal.
How do I do this?
Context
I've seen posts like this <a href="https://stackoverflow.com/questions/1335507/keyboard-input-with-timeout">one</a> that suggest methods to input some user input with a timeout. However, these solutions don't hide input like <code>getpass</code> does. I'm wondering if there's some functionality that could use <code>getpass</code> or something like it.

Python get user input password with timeout

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在编写Python应用程序，并希望提示用户输入他们的密码。如果他们没有在60秒内输入，程序应该退出。如果他们输入了密码，他们的密码应该隐藏在终端中。我该怎么做？上下文我见过像这个这样的帖子，它建议用超时来输入一些用户输入的方法。然而，这些解决方案并不像getpass那样隐藏输入。我想知道是否有一些功能可以使用get...

问Python获取带有超时的用户输入密码
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