在不同条件下打印一个变量的两个值
在不同条件下打印一个变量的两个值
提问于 2022-02-09 15:49:40
请考虑以下声明：
sum_value = fixed_value - current_value，
其中fixed_value是常数，current_value是thresholds的函数；
thresholds有两个threshold_level值：thresholds = [10, 20]；
我需要找到一个sim_value的rato，对应于threshold_level = 10到sim_value，对应于threshold_level = 20，即final_sim_value = sim_value_at_10/sim_value_at_20。
代码部分是
thresholds = [10, 20]
fixed_value = 100
for threshold_level in thresholds:
current_value = 5 - threshold_level
sim_value = fixed_value - current_value
def sim_value_multi(threshold_level):
if threshold_level == 10:
sim_value_at_10 = sim_value
return sim_value_at_10
if threshold_level == 20:
sim_value_at_20 = sim_value
return sim_value_at_20
final_sim_value = sim_value_multi(10)/sim_value_multi(20)
print('sim_value_multi(10) is ', sim_value_multi(10))
print('sim_value_multi(20) is ', sim_value_multi(20))
print('final_sim_value is ', final_sim_value)
print('--------------------')
final_sim_value = sim_value_multi(10)/sim_value_multi(20)
print('sim_value_multi(10) is ', sim_value_multi(10))
print('sim_value_multi(20) is ', sim_value_multi(20))
print('final_sim_value is ', final_sim_value)它提供了这样的输出：
sim_value_multi(10) is 105
sim_value_multi(20) is 105
final_sim_value is 1.0
sim_value_multi(10) is 115
sim_value_multi(20) is 115
final_sim_value is 1.0
--------------------
sim_value_multi(10) is 115
sim_value_multi(20) is 115
final_sim_value is 1.0请你纠正我或提出适当的解决办法好吗？
回答 1
Stack Overflow用户
回答已采纳
发布于 2022-02-09 16:51:51
你想得到这个结果吗？
thresholds = [10, 20]
fixed_value = 100
current_values = []
for threshold_value in thresholds:
current_values.append(fixed_value + threshold_value - 5)
print('sim_value_multi(10) is ', current_values[0])
print('sim_value_multi(20) is ', current_values[1])
print('final_sim_value is ', current_values[0]/current_values[1])输出
sim_value_multi(10) is 105
sim_value_multi(20) is 115
final_sim_value is 0.9130434782608695页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/71052668
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