Pyrogram:为游戏提供的回复标记为空(由“messages.SendMedia”引起)
Pyrogram:为游戏提供的回复标记为空(由“messages.SendMedia”引起)
提问于 2022-02-22 06:26:43
我正在用热图把一个html 5游戏发给我的朋友们。我创建了一个名为"popspike“的游戏，它来自@botfather，这是我的html 5游戏链接。下图是没有内联按钮的游戏示例。该按钮是自动生成的电报和按钮不是工作启动我的html 5游戏。
根据关于堆栈溢出的讨论和提供文件手册，我们需要使用callback_query.answer(url="your website")来打开html 5游戏(popspike)，所以我创建了一个内联按钮来调用查询数据。
@app.on_message(filters.command("popspike"))
async def start_command(client, message): #send game to user & inline button send callback query
await message.reply_game('popspike'
,reply_markup=InlineKeyboardMarkup([[InlineKeyboardButton("Play popspike",callback_data='test',callback_game=CallbackGame())]])) #reply markup is the error
@app.on_callback_query()
async def openquery(client, callback_query): #show text "hello" and open my html 5 game through `url` para
await callback_query.answer("Hello", show_alert=True, url='https://lmjaedentai.github.io/popspike')但是当我想调用这个命令/popspike将我的游戏发送给用户时，我遇到了这个错误，所以我没有将游戏发送给用户。
Telegram says: [400 REPLY_MARKUP_GAME_EMPTY] - The provided reply markup for the game is empty (caused by "messages.SendMedia")
Traceback (most recent call last):
File "D:\Desktop\coding\discordpy\env\lib\site-packages\pyrogram\dispatcher.py", line 222, in handler_worker
await handler.callback(self.client, *args)
File "D:\Desktop\coding\discordpy\env\lib\site-packages\pyromod\listen\listen.py", line 93, in resolve_listener
await self.user_callback(client, message, *args)
File "d:\Desktop\coding\discordpy\telegram\main.py", line 118, in start_command
await message.reply_game('popspike',reply_markup=InlineKeyboardMarkup([[InlineKeyboardButton("Play poxpspike",callback_data='test',callback_game=CallbackGame())]]))
File "D:\Desktop\coding\discordpy\env\lib\site-packages\pyrogram\types\messages_and_media\message.py", line 1633, in reply_game
return await self._client.send_game(
File "D:\Desktop\coding\discordpy\env\lib\site-packages\pyrogram\methods\bots\send_game.py", line 74, in send_game
r = await self.send(
File "D:\Desktop\coding\discordpy\env\lib\site-packages\pyrogram\methods\advanced\send.py", line 77, in send
r = await self.session.send(
File "D:\Desktop\coding\discordpy\env\lib\site-packages\pyrogram\session\session.py", line 362, in send
return await self._send(data, timeout=timeout)
File "D:\Desktop\coding\discordpy\env\lib\site-packages\pyrogram\session\session.py", line 332, in _send
RPCError.raise_it(result, type(data))
File "D:\Desktop\coding\discordpy\env\lib\site-packages\pyrogram\errors\rpc_error.py", line 91, in raise_it
raise getattr(
pyrogram.errors.exceptions.bad_request_400.ReplyMarkupGameEmpty: Telegram says: [400 REPLY_MARKUP_GAME_EMPTY] - The provided reply markup for the game is empty (caused by "messages.SendMedia")我确实在send_game中提供了send_game，但是为什么电报说“游戏的回复标记是空的”？
我为这个漫长的问题道歉，因为我恐怕你无法理解我想问的问题。
希望你能帮我。谢谢。
Stack Overflow用户
回答已采纳
发布于 2022-05-16 12:11:19
在第二段中这样做：
@app.on_callback_query(filters.regex('test'))
async def openquery(client, callback_query): #show text "hello" and open my html 5 game through `url` para
await callback_query.answer("Hello", show_alert=True, url='https://lmjaedentai.github.io/popspike')在filters.regex('test')中给出参数@app.on_callback_query()
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原文链接：
https://stackoverflow.com/questions/71216766
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