blocks|key|551689|text|这就是你要找的吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|551690|dct_mapper+=+dict(a=1,+b=2)
s+=+'{{key1:+value2,+key1:+value2;+attrib1={a};+attrib2={b}}}'.format(**dct_mapper)|code-block|syntax|javascript|551691|输出：{key1:+value2，key1:+value2；attrib1=1；attrib2=2}|551692|dct_mapper+=+dict(a=1,+b=1)
s+=+'{{key1:+value2,+key1:+value2;+attrib1={a};+attrib2={b}}}'.format(**dct_mapper)|551693|输出：{key1:+value2，key1:+value2；attrib1=1；attrib2=1}|551694|但是，如果您只试图传递一个值，比如"a"，它将抛出一个错误，因为format()将填充给字符串中所有{}的值。|551695|dct_mapper+=+dict(a=1)
s+=+'{{key1:+value2,+key1:+value2;+attrib1={a};+attrib2={b}}}'.format(**dct_mapper)|551696|输出:+KeyError：'b‘|551697|希望这能有所帮助！|551698|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|14|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

Is this what you are looking for?
<pre><code>dct_mapper = dict(a=1, b=2)
s = '{{key1: value2, key1: value2; attrib1={a}; attrib2={b}}}'.format(**dct_mapper)
</code></pre>
Output:
{key1: value2, key1: value2; attrib1=1; attrib2=2}
<pre><code>dct_mapper = dict(a=1, b=1)
s = '{{key1: value2, key1: value2; attrib1={a}; attrib2={b}}}'.format(**dct_mapper)
</code></pre>
Output:
{key1: value2, key1: value2; attrib1=1; attrib2=1}
But if you try to pass only 1 value, say for just &quot;a&quot;, it will throw an error because format() is going to fill in the values given to all the {} in the string.
<pre><code>dct_mapper = dict(a=1)
s = '{{key1: value2, key1: value2; attrib1={a}; attrib2={b}}}'.format(**dct_mapper)
</code></pre>
Output:
KeyError: 'b'
Hope this helps!

blocks|key|1107979|text|如果您不想将{}转换为{{}}，我建议您使用string中的Template。它的接口允许您像下面所做的那样自定义格式选项：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1107980|from+string+import+Template


class+MyTemplate(Template):
++++delimiter+=+""


dct_mapper+=+dict(a=1)
s+=+MyTemplate('{key1:+value2,+key1:+value2};+attrib1={a};+attrib2={b}')
print(s.safe_substitute(**dct_mapper))|code-block|syntax|javascript|1107981|输出是，如您所愿：{key1:+value2,+key1:+value2};+attrib1=1;+attrib2={b}|1107982|说明:默认情况下，我Template使用$var而不是{var}格式化字符串，因此我将变量名($之后)的模式更改为${var}，分隔符本身改为""，所以{var}就足够了，而不是${var}。|1107983|此外，模板有safe_substitute，它允许您格式化整个字符串中的几个变量，并且它不会对不存在的变量格式产生错误。|1107984|此外，如果您喜欢这样做，那么可以将s.safe_substitute(**dct_mapper)更改为s.safe_substitute(dct_mapper)。|1107985|entityMap^0|6|2|B|4|M|6|U|8|0|0|9|1G|0|A|8|K|4|R|5|1B|1|1L|6|24|5|2H|6|0|6|F|0|H|V|1F|T|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|1M|8|@$9|1N|A|1O|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1P|8|@$9|1Q|A|1R|B|C]|$9|1S|A|1T|B|C]]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1U|8|@]|D|@]|E|$]]]|T|$]]

In case you don't want to convert <code>{}</code> to <code>{{}}</code>, I suggest you using <code>Template</code> from <code>string</code>. Its interface allows you to custom the formatting options as I did below:
<pre class="lang-py prettyprint-override"><code>from string import Template


class MyTemplate(Template):
 delimiter = &quot;&quot;


dct_mapper = dict(a=1)
s = MyTemplate('{key1: value2, key1: value2}; attrib1={a}; attrib2={b}')
print(s.safe_substitute(**dct_mapper))
</code></pre>
The output is, as you wanted:
<code>{key1: value2, key1: value2}; attrib1=1; attrib2={b}</code>
Explanation:
By default i <code>Template</code> you format strings using <code>$var</code> instead of <code>{var}</code> so I changed the pattern of the variable name (after the <code>$</code>) to be <code>${var}</code> and the delimiter itself to be &quot;&quot;, so <code>{var}</code> is enough instead of <code>${var}</code>.
Moreover, templates have <code>safe_substitute</code> which allows you to format only few variables in the entire string and it doesn't raise an error for non-existing variable formats.
Also, <code>s.safe_substitute(**dct_mapper)</code> can be changed into <code>s.safe_substitute(dct_mapper)</code> if you prefer this over that.

blocks|key|546210|text|您的格式字符串无效，但假设您希望在这种情况下实际打印大括号。双倍的大括号打印一个文字大括号。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|546211|如果键不存在，您可以子类dict返回带括号的格式键。这填补了{a}的空白，但使{b}不受影响：|offset|length|style|CODE|546212|class+MyDict(dict):

++++#+"magic"+method+called+when+a+key+is+missing+from+the+dict
++++def+__missing__(self,+key):
++++++++return+f'{{{key}}}'

dct_mapper+=+MyDict(a=1)
s+=+'{{key1:+value2,+key1:+value2}};+attrib1={a};+attrib2={b}'
#+Must+use+format_map.++format(**dct_mapper)+doesn't+work
print(s.format_map(dct_mapper))|code-block|syntax|javascript|546213|输出：|546214|{key1:+value2,+key1:+value2};+attrib1=1;+attrib2={b}|546215|entityMap^0|0|C|4|U|3|13|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@$D|U|E|V|F|G]|$D|W|E|X|F|G]|$D|Y|E|Z|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|10|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|Q|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|R|$]]

Your format string was invalid but assume you wanted to actually print the braces in that case. Double the braces to print one literal brace.
You can subclass <code>dict</code> to just return the braced format key if the key isn't present. This fills out <code>{a}</code> but leaves <code>{b}</code> alone:
<pre class="lang-py prettyprint-override"><code>class MyDict(dict):

 # &quot;magic&quot; method called when a key is missing from the dict
 def __missing__(self, key):
 return f'{{{key}}}'

dct_mapper = MyDict(a=1)
s = '{{key1: value2, key1: value2}}; attrib1={a}; attrib2={b}'
# Must use format_map. format(**dct_mapper) doesn't work
print(s.format_map(dct_mapper))
</code></pre>
Output:
<pre class="lang-none prettyprint-override"><code>{key1: value2, key1: value2}; attrib1=1; attrib2={b}
</code></pre>

I try to format a string with curly brackets like this:
<pre><code>dct_mapper = dict(a=1)
s = '{key1: value2, key1: value2}; attrib1={a}; attrib2={b}'
s.format(**dct_mapper)

Results in:
# KeyError: 'key1'

Expected:
# '{key1: value2, key1: value2}; attrib1=1; attrib2={b}'
</code></pre>
An additional constrainment is that I need to use <code>.format_map()</code> later on the output again, this screws up solutions which use .format() because the out curly brackets will disappear.
I tried <a href="https://www.geeksforgeeks.org/defaultdict-in-python/" rel="nofollow noreferrer">defaultdict from the collections</a> package and also into <a href="https://www.programiz.com/python-programming/methods/string/format_map" rel="nofollow noreferrer">.format_map()</a>, then plaed around with regex trying to replace the <a href="https://stackoverflow.com/questions/5466451/how-can-i-print-literal-curly-brace-characters-in-a-string-and-also-use-format">brackets with additional ones</a>, which feels less like a solution and more like a hack and also doesn't work if you have multiple repeating brackets in the string to begin with.
It is not a json string, because then I could have used the json library to map the values.
Does anyone have an idea how to solve this?
I currently consider using a loop and <code>str.replace('{a}', 1)</code> but this feels clunky as well.

.format() string, keep curly brackets if no match available

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我尝试用如下的花括号格式化字符串：dct_mapper = dict(a=1)s = '{key1: value2, key1: value2}; attrib1={a}; attrib2={b}'s.format(**dct_mapper)Results in:# KeyError: 'key1'Expected:#...

问.format()字符串，如果没有匹配，则保留花括号
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问.format()字符串，如果没有匹配，则保留花括号EN