blocks|key|1342135|text|您可以使用一个循环：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1342136|for+d+in+lst:
++++for+v+in+d.values():
++++++++for+i,+num+in+enumerate(v):
++++++++++++v[i]+=+int(float(num))

print(lst)|code-block|syntax|javascript|1342137|输出：|1342138|[{'point1':+[20,+15,+20],
++'point2':+[0,+34,+8],
++'point3':+[12,+15,+2],
++'point4':+[15,+5,+16]}]|1342139|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You could use a loop:
<pre><code>for d in lst:
 for v in d.values():
 for i, num in enumerate(v):
 v[i] = int(float(num))

print(lst)
</code></pre>
Output:
<pre><code>[{'point1': [20, 15, 20],
 'point2': [0, 34, 8],
 'point3': [12, 15, 2],
 'point4': [15, 5, 16]}]
</code></pre>

blocks|key|632256|text|在一行中尝试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|632257|l+=+[{'point1':+['20.900',+'15.300',+'20.400'],+'point2':+['0.600',+'34.700',+'8.100'],+'point3':+['12.100',+'15.800',+'2.300'],+'point4':+['15.000',+'5.800',+'16.900']}]

result+=+[{k:+[int(float(i))+for+i+in+v]+for+k,+v+in+l[0].items()}]|code-block|syntax|javascript|632258|其结果将是：|632259|[{'point1':+[20,+15,+20],
++'point2':+[0,+34,+8],
++'point3':+[12,+15,+2],
++'point4':+[15,+5,+16]}]|632260|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Try this in one line:
<pre><code>l = [{'point1': ['20.900', '15.300', '20.400'], 'point2': ['0.600', '34.700', '8.100'], 'point3': ['12.100', '15.800', '2.300'], 'point4': ['15.000', '5.800', '16.900']}]

result = [{k: [int(float(i)) for i in v] for k, v in l[0].items()}]
</code></pre>
The result will be:
<pre><code>[{'point1': [20, 15, 20],
 'point2': [0, 34, 8],
 'point3': [12, 15, 2],
 'point4': [15, 5, 16]}]
</code></pre>

blocks|key|628368|text|array=[{'point1':+['20.900',+'15.300',+'20.400'],+'point2':+['0.600',+'34.700',+'8.100'],+'point3':+['12.100',+'15.800',+'2.300'],+'point4':+['15.000',+'5.800',+'16.900']}]
new_array=array[0]

for+i+in+new_array.values():
++++k=0
++++for+j+in+i:
++++++++i[k]=int(float(j))
++++++++k=k%2B1
++++++++
print(new_array)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|628369|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>array=[{'point1': ['20.900', '15.300', '20.400'], 'point2': ['0.600', '34.700', '8.100'], 'point3': ['12.100', '15.800', '2.300'], 'point4': ['15.000', '5.800', '16.900']}]
new_array=array[0]

for i in new_array.values():
 k=0
 for j in i:
 i[k]=int(float(j))
 k=k+1
 
print(new_array)
</code></pre>

blocks|key|1029016|text|一个similar+question已经问过了，也检查过了！你也可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1029017|arr+=+[{
++++'point1':+['20.900',+'15.300',+'20.400'],+
++++'point2':+['0.600',+'34.700',+'8.100'],+
++++'point3':+['12.100',+'15.800',+'2.300'],+
++++'point4':+['15.000',+'5.800',+'16.900'],
++++}]

[{k+:+list(map(float,+v))++for+k,+v+in+point.items()+}+for+point+in+arr]|code-block|syntax|javascript|1029018|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/7368789/convert-all-strings-in-a-list-to-int^0|2|G|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

a <a href="https://stackoverflow.com/questions/7368789/convert-all-strings-in-a-list-to-int">similar question</a> asked already check that too!
you can do this also:
<pre class="lang-py prettyprint-override"><code>arr = [{
 'point1': ['20.900', '15.300', '20.400'], 
 'point2': ['0.600', '34.700', '8.100'], 
 'point3': ['12.100', '15.800', '2.300'], 
 'point4': ['15.000', '5.800', '16.900'],
 }]

[{k : list(map(float, v)) for k, v in point.items() } for point in arr]
</code></pre>

I have a data like that
<pre><code>[{'point1': ['20.900', '15.300', '20.400'], 
 'point2': ['0.600', '34.700', '8.100'], 
 'point3': ['12.100', '15.800', '2.300'], 
 'point4': ['15.000', '5.800', '16.900']}]
</code></pre>
How can I convert the numbers into integers?

convert Element of list value in Dictionary Python

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有这样的数据[{'point1': ['20.900', '15.300', '20.400'],   'point2': ['0.600', '34.700', '8.100'],   'point3': ['12.100', '15.800', '2.300'],   'point4': ['15.000', '...

问在字典Python中转换列表值元素
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问在字典Python中转换列表值元素EN