blocks|key|529600|text|在追加新元素之前清除#liked中的thr内容|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|529601|伪码|BOLD|529602|const+displayLikedPosts+=+()+=>+{
++++const+likedPosts+=+getLikedPosts();
++++document.getElementById("liked")innerHTML+=+"";
++++likedPosts.forEach((post)+=>+{
++++++++const+div+=+createPost(post);
++++++++document.getElementById("liked").appendChild(div);
++++});
};|code-block|syntax|javascript|529603|entityMap^0|A|6|0|0|2|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@$9|T|A|U|B|H]]|D|@]|E|$]]|$1|I|3|J|5|K|7|V|8|@]|D|@]|E|$L|M]]|$1|N|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|O|$]]

Clear thr content inside <code>#liked</code> before appending new elements
Pseudo Code
<pre><code>const displayLikedPosts = () =&gt; {
 const likedPosts = getLikedPosts();
 document.getElementById(&quot;liked&quot;)innerHTML = &quot;&quot;;
 likedPosts.forEach((post) =&gt; {
 const div = createPost(post);
 document.getElementById(&quot;liked&quot;).appendChild(div);
 });
};
</code></pre>

blocks|key|842568|text|必须首先删除父DOM节点的子节点，然后再次添加元素。删除孩子的方法有很多，这在this+thread中有讨论。您可能会发现，有些选项比其他选项更好(和/或更现代)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|842569|下面是用例的一个很小的示例，它使用setInterval()来证明列表不包含重复项。|style|CODE|842570|​|842571|/**
+*+Display+posts
+*+@param+{string[]}+posts+posts+to+display
+*/
function+displayPosts(posts)+{
++const+parent+=+document.getElementById("liked");

++//+delete+children
++deleteChildren(parent);
++
++//+add+items+to+the+list
++posts.forEach((post)+=>+{
++++const+listItem+=+document.createElement("li");
++++listItem.textContent+=+post;
++++parent.appendChild(listItem);
++});
++console.log("rendered")
}

/**
+*+Deletes+all+children+of+a+DOM+node.
+*+@param+{HTMLElement}+parent+parent+element
+*/
function+deleteChildren(parent)+{
++while+(parent.firstChild)+{
++++parent.firstChild.remove();
++}
}

window.addEventListener("DOMContentLoaded",+(event)+=>+{
++//+posts+to+display
++const+posts+=+["post+1",+"post+2",+"post+3",+"post+4"];

++displayPosts(posts)
++//+call+method+every+3+seconds+to+demonstrate+it+works
++setInterval(()+=>+displayPosts(posts),+3+*+1000);
});|code-block|syntax|javascript|842572|<ul+id="liked">

</ul>|842573|842574|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/3955229/remove-all-child-elements-of-a-dom-node-in-javascript^0|13|B|0|0|H|D|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|D|3|E|5|6|7|13|8|@$A|14|B|15|F|G]]|9|@]|C|$]]|$1|H|3|I|5|6|7|16|8|@]|9|@]|C|$]]|$1|J|3|K|5|L|7|17|8|@]|9|@]|C|$M|N]]|$1|O|3|P|5|L|7|18|8|@]|9|@]|C|$M|N]]|$1|Q|3|I|5|6|7|19|8|@]|9|@]|C|$]]|$1|R|3|-4|5|6|7|1A|8|@]|9|@]|C|$]]]|S|$T|$5|U|V|W|C|$X|Y]]]]

You must first delete the children of your parent DOM node, then add the
elements again.
There are many ways to delete the children, which are discussed in <a href="https://stackoverflow.com/questions/3955229/remove-all-child-elements-of-a-dom-node-in-javascript">this thread</a>. You may find that some options are better (and/ or more modern) than others.
Here is a small minimal example for your use case using <code>setInterval()</code> to prove that the list does not contain duplicates.
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>/**
 * Display posts
 * @param {string[]} posts posts to display
 */
function displayPosts(posts) {
 const parent = document.getElementById("liked");

 // delete children
 deleteChildren(parent);
 
 // add items to the list
 posts.forEach((post) =&gt; {
 const listItem = document.createElement("li");
 listItem.textContent = post;
 parent.appendChild(listItem);
 });
 console.log("rendered")
}

/**
 * Deletes all children of a DOM node.
 * @param {HTMLElement} parent parent element
 */
function deleteChildren(parent) {
 while (parent.firstChild) {
 parent.firstChild.remove();
 }
}

window.addEventListener("DOMContentLoaded", (event) =&gt; {
 // posts to display
 const posts = ["post 1", "post 2", "post 3", "post 4"];

 displayPosts(posts)
 // call method every 3 seconds to demonstrate it works
 setInterval(() =&gt; displayPosts(posts), 3 * 1000);
});</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;ul id="liked"&gt;

&lt;/ul&gt;</code></pre>
</div>
</div>

In the displayLikedPosts there is a function called getLikedPosts. this getLikedPosts function filter the posts ID and insert posts into an array. Now after running forEach loop inside the displayLikedPosts ---first time it adds a new and single post(ex:post-1) but second time it displays the previous post twice and the new post (ex: post-1,post-1,newpost). But my purpose is to display only the previous one and the new posts(ex:post-1,newpost,newpost2,newpost4)
<pre><code>code

 const displayLikedPosts = () =&gt; {
 const likedPosts = getLikedPosts();
 
 likedPosts.forEach((post) =&gt; {
 const div = createPost(post);
 document.getElementById(&quot;liked&quot;).appendChild(div);

 });
 };
</code></pre>

how to stop repetition of previous post

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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在displayLikedPosts中有一个名为getLikedPosts的函数。这个getLikedPosts函数过滤posts并将posts插入到数组中。现在，在运行post(ex:post-1)内部的forEach循环之后--第一次添加一个新的和单个的，但是第二次它会显示前一个帖子两次和新的帖子(ex: post...

问如何停止重复上一篇文章
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