如何编辑函数中的全局变量
如何编辑函数中的全局变量
提问于 2022-03-26 12:44:30
我刚接触python，我试着制作一个基于文本的小游戏，我列出了玩家的健康状况，当我试图在函数中编辑变量时，它不会改变全局变量，当我尝试使用全局命令将它定义为全局变量时，它说参数已经是一个全局变量，而返回也不起作用？
import random
health = 100
dHealth = 1000
def attack(dHealth):
attack = random.randint(5,50)
dHealth = dHealth - attack
print("You dealth", attack,"damage, the dragon has", dHealth,"health left!")
attack(dHealth)
print(dHealth) 我希望变量从1000变为995到950之间的数字。
回答 2
Stack Overflow用户
发布于 2022-03-26 12:51:41
最好的解决方案是不要将其用作全局变量。attack应该取一个值并返回更新的值。
import random
health = 100
dHealth = 1000
def attack(monster, health):
attack = random.randint(5,50)
health = health - attack
print("You dealt", attack,"damage, the ", monster, " has", health,"health left!")
return health
dHealth = attack("dragon", dHealth)
print(dHealth) 因为从理论上讲，attack不再是专门针对龙的健康的，所以它需要一个额外的参数来命名为调用print而受到攻击的怪物。
Stack Overflow用户
发布于 2022-03-26 12:49:22
因此，您需要指定inside函数，即它是要更改的全局变量。代码如下所示：
import random
health = 100
dHealth = 1000
def attack(): # If you pass dHealth here, it only changes the local instance and not
# the global one
global dHealth
attack = random.randint(5,50)
dHealth = dHealth - attack
print("You dealth", attack,"damage, the dragon has", dHealth,"health left!")
attack()
print(dHealth)但是还有另一种方法，那就是用函数返回一个值并将其赋值给dHealth。
代码：
import random
health = 100
dHealth = 1000
def attack(dHealth):
attack = random.randint(5,50)
dHealth = dHealth - attack
print("You dealth", attack,"damage, the dragon has", dHealth,"health left!")
return dHealth
dHealth = attack(dHealth) # Here, the returned value of dHealth after
# reduction is assigned to the global variable
# so no need to use global variables
print(dHealth) 页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/71628164
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