想和推特机器人玩得开心。
这个想法是:根据芝加哥API艺术学院的说法,在Tweet上发布信息(艺术家,日期,地点.)和媒体(图片)。
我不能在这里上传媒体,你可以看到我试图修复的回溯。
我会感激的!B
import tweepy
import requests
import random
import time
import io
############################# My logs ######################################
def twitter_api():
consumer_key = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxx'
consumer_secret = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxx'
access_token = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxx'
access_token_secret = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxx'
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
api = tweepy.API(auth)
return api
############################# My fonctions #################################
############################# The Loop ######################################
while True:
get_number()
r = requests.get(f"https://api.artic.edu/api/v1/artworks/{get_number()}")
a = r.json()
get_Titre(),get_Artist(),get_Date(),get_Place(),get_Im()
requests2 = (f"https://www.artic.edu/iiif/2/{get_Im()}/full/843,/0/default.jpg")
print("Imge ok:....................", requests2)
print(type(requests2))
message = (get_Titre()+ get_Artist()+str(get_Date())+get_Place())
print("La tête du tweet sera:", message)
twitter_api().update_status_with_media(message,requests2)
time.sleep(14400)
这是回溯:
Traceback (most recent call last):
File "C:\PycharmProjects\TwitterBot\main.py", line 76, in <module>
twitter_api().update_status_with_media(message,requests2)
File "C:\PycharmProjects\TwitterBot\venv\lib\site-packages\tweepy\api.py", line 46, in wrapper
return method(*args, **kwargs)
File "C:\PycharmProjects\TwitterBot\venv\lib\site-packages\tweepy\api.py", line 1181, in update_status_with_media
files = {'media[]': stack.enter_context(open(filename, 'rb'))}
OSError: [Errno 22] Invalid argument: 'https://www.artic.edu/iiif/2/904ea189-c852-5f84-c614-a26a851f9b74/full/843,/0/default.jpg'
发布于 2022-04-02 04:01:53
参见媒体文档-第二个参数必须是文件名。
update_status_with_media(text, filename, file, ...)
但是第三个参数可以是file-like object
,这意味着具有函数.read()
的对象。
如果您要使用urllib.request
,那么它就会给出具有.read()
的对象,并且它可以工作。
顺便说一句:你必须使用任何文本作为第二个参数--可以是假的文件名,但函数需要它。
import os
import urllib.request
import tweepy
url = "https://www.iheartradio.ca/image/policy:1.15731844:1627581512/rick.jpg?f=default&$p$f=20c1bb3"
text = "Testing module tweepy"
# --- create file_like_object ---
file_like_object = urllib.request.urlopen(url)
# --- send tweet ---
consumer_key = os.getenv('TWITTER_CONSUMER_KEY')
consumer_secret = os.getenv('TWITTER_CONSUMER_SECRET')
access_token = os.getenv('TWITTER_ACCESS_TOKEN')
access_token_secret = os.getenv('TWITTER_ACCESS_TOKEN_SECRET')
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
twitter_api = tweepy.API(auth)
# use any filename as second argument, and file-like object as third argument
twitter_api.update_status_with_media(text, 'fake_name.jpg', file=file_like_object)
使用requests
,您必须使用io.BytesIO
来创建file-like object
import os
import io
import requests
import tweepy
url = "https://www.iheartradio.ca/image/policy:1.15731844:1627581512/rick.jpg?f=default&$p$f=20c1bb3"
text = "Testing module tweepy"
# --- create file_like_object ---
response = requests.get(url)
file_like_object = io.BytesIO(response.content)
# --- send tweet ---
consumer_key = os.getenv('TWITTER_CONSUMER_KEY')
consumer_secret = os.getenv('TWITTER_CONSUMER_SECRET')
access_token = os.getenv('TWITTER_ACCESS_TOKEN')
access_token_secret = os.getenv('TWITTER_ACCESS_TOKEN_SECRET')
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
twitter_api = tweepy.API(auth)
# use any filename as second argument, and file-like object as third argument
twitter_api.update_status_with_media(text, 'fake_name.jpg', file=file_like_object)
编辑:
最终,您可以使用stream=True
,然后response.raw
提供file-like object
,但这并不流行。
# --- create file_like_object ---
response = requests.get(url, stream=True)
file_like_object = response.raw
https://stackoverflow.com/questions/71714657
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