shell脚本:返回错误的输出
shell脚本:返回错误的输出
提问于 2022-04-06 19:12:40
在给定的脚本中，嵌套的键不会被附加到值中。我不知道剧本哪里出错了。
#!/bin/bash
echo "Add the figma json file path"
read path
figma_json="$(echo -e "${path}" | tr -d '[:space:]')"
echo $(cat $figma_json | jq -r '.color | to_entries[] | "\(.key):\(.value| if .value == null then .[] | .value else .value end)"')样本输入：
{
"color": {
"white": {
"description": "this is just plain white color",
"type": "color",
"value": "#ffffffff",
"extensions": {
"org.lukasoppermann.figmaDesignTokens": {
"styleId": "S:40940df38088633aa746892469dd674de8b147eb,",
"exportKey": "color"
}
}
},
"gray": {
"50": {
"description": "",
"type": "color",
"value": "#fafafaff",
"extensions": {
"org.lukasoppermann.figmaDesignTokens": {
"styleId": "S:748a0078c39ca645fbcb4b2a5585e5b0d84e5fd7,",
"exportKey": "color"
}
}
}
}
}
}实际产出：
white:#ffffffff gray:#fafafaff 例外产出：
white:#ffffffff gray:50:#fafafaff回答 2
Stack Overflow用户
回答已采纳
发布于 2022-04-06 20:04:15
下面是一种使用tostream而不是to_entries来同时访问完整路径及其值的解决方案：
jq -r '
.color | tostream | select(.[0][-1] == "value" and has(1)) | .[0][:-1]+.[1:] | join(":")
' "$figma_json"white:#ffffffff
gray:50:#fafafaffStack Overflow用户
发布于 2022-04-06 20:09:12
一种试图演示bash最佳实践的方法：
#!/bin/bash
figma_json=$1 # prefer command-line arguments to prompts
[[ $figma_json ]] || {
read -r -p 'Figma JSON file path: ' path # read -r means backslashes not munged
figma_json=${path//[[:space:]]/} # parameter expansion is more efficient than tr
}
jq -r '
def recurse_for_value($prefix):
to_entries[]
| .key as $current_key
| .value?.value? as $immediate_value
| if $immediate_value == null then
.value | recurse_for_value(
if $prefix != "" then
$prefix + ":" + $current_key
else
$current_key
end
)
else
if $prefix == "" then
"\($current_key):\($immediate_value)"
else
"\($prefix):\($current_key):\($immediate_value)"
end
end
;
.color |
recurse_for_value("")
' "$figma_json"页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/71772406
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