必须为客户端注册指定提供者ID“azure”？
必须为客户端注册指定提供者ID“azure”？
提问于 2022-04-07 11:38:46
当我升级到SpringBoot2.6.6时，这个应用程序显示了如下错误:我的pom.xml有这个依赖项
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-security</artifactId>
</dependency>
<dependency>
<groupId>com.azure.spring</groupId>
<artifactId>spring-cloud-azure-starter-active-directory</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-oauth2-client</artifactId>
</dependency>
</dependencies>
<dependencyManagement>
<dependencies>
<dependency>
<groupId>com.azure.spring</groupId>
<artifactId>spring-cloud-azure-dependencies</artifactId>
<version>${spring-cloud-azure.version}</version>
<type>pom</type>
<scope>import</scope>
</dependency>
</dependencies>
</dependencyManagement>在我的application.properties上的这个配置：
azure.activedirectory.tenant-id=*******.
spring.security.oauth2.client.registration.azure.client-id=*********.
azure.activedirectory.client-id=************.
spring.security.oauth2.client.registration.azure.client-secret=*************.
azure.activedirectory.client-secret=*************.安全配置类是
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests().antMatchers("/**").authenticated();
http.authorizeRequests().anyRequest().permitAll();
http.addFilterBefore(jwtTokenFilterBean(),UsernamePasswordAuthenticationFilter.class);
http.addFilterBefore(aadAuthFilter, UsernamePasswordAuthenticationFilter.class);
http.csrf().disable() ;
}这是bean类
@Bean
public FilterRegistrationBean<CorsFilter> simpleCorsFilter() {
UrlBasedCorsConfigurationSource source = new UrlBasedCorsConfigurationSource();
CorsConfiguration config = new CorsConfiguration();
config.setAllowCredentials(true);
config.setAllowedOrigins(Collections.singletonList("*"));
config.setAllowedMethods(Collections.singletonList("*"));
config.setAllowedHeaders(Collections.singletonList("*"));
source.registerCorsConfiguration("/**", config);
FilterRegistrationBean<CorsFilter> bean = new FilterRegistrationBean<>(new
CorsFilter(source));
bean.setOrder(Ordered.HIGHEST_PRECEDENCE);
return bean;
} 当我试图运行应用程序时，请给我以下错误：
Caused by: java.lang.IllegalStateException: Provider ID must be specified for client registration 'azure'
at org.springframework.boot.autoconfigure.security.oauth2.client.OAuth2ClientPropertiesRegistrationAdapter.getBuilder(OAuth2ClientPropertiesRegistrationAdapter.java:95) ~[spring-boot-autoconfigure-2.6.6.jar:2.6.6]
at org.springframework.boot.autoconfigure.security.oauth2.client.OAuth2ClientPropertiesRegistrationAdapter.getClientRegistration(OAuth2ClientPropertiesRegistrationAdapter.java:61) ~[spring-boot-autoconfigure-2.6.6.jar:2.6.6]
at org.springframework.boot.autoconfigure.security.oauth2.client.OAuth2ClientPropertiesRegistrationAdapter.lambda$getClientRegistrations$0(OAuth2ClientPropertiesRegistrationAdapter.java:53) ~[spring-boot-autoconfigure-2.6.6.jar:2.6.6]
at java.util.HashMap.forEach(Unknown Source) ~[?:1.8.0_65]为什么会发生这种事？我该怎么做才能解决这个问题？
提前谢谢。
回答 1
Stack Overflow用户
发布于 2022-04-07 20:11:01
请检查应用程序属性是否配置了提供程序并为所需的api具有正确的范围。
下面提供了一些应用程序properties.Please，检查缺少的应用程序，或者是否一切都是正确的。
ex:application.properties
spring.security.oauth2.client.registration.azure.client-id=XXXXXXXXXX
spring.security.oauth2.client.registration.azure.client-secret=XXXXXXXXXX
spring.security.oauth2.client.registration.azure.scope=openid,profile,email,offline_access //here provide required scopes ex:
spring.security.oauth2.client.registration.azure.redirect-uri-template=’{baseUrl}/login/oauth2/code/{registrationId}’
spring.security.oauth2.client.registration.azure.client-name=xxxxxxxxx
spring.security.oauth2.client.registration.azure.provider=xxxxxxxxx
spring.security.oauth2.client.registration.azure.client-authentication-method=basic
spring.security.oauth2.client.registration. azure.authorization-grant-type=authorization_code
spring.security.oauth2.client.provider. azure.authorization-uri=https://login.microsoftonline.com/<tenantid>/oauth2/v2/authorize
spring.security.oauth2.client.provider. azure.token-uri= https://login.microsoftonline.com/xxxxxxxxxxxxxx/oauth2/v2/token
spring.security.oauth2.client.provider.xxxxxxxxx.user-info-uri=https://login.microsoftonline.com/xxxxxxxxxxxxxx/openid/userinfo
spring.security.oauth2.client.provider. azure.user-name-attribute=name
spring.security.oauth2.client.provider. azure.user-info-authentication-method=header
spring.security.oauth2.client.provider. azure.jwk-set-uri=https://login.microsoftonline.com/xxxxxxxxxxxxxx/discovery/v2/keys如果api是图api，则作用域可以是https://graph.microsoft.com/user.read，如果不是图形api，请确保公开api并给予适当的权限，并授予管理员对相同的权限。
另外，请检查清单以查看accesstokenacceptedversion，如果清单为null或1，则tr将其更改为2，反之亦然，并进行相同的配置，即；
如果v2属性spring.security.oauth2.client.provider. azure.authorization-uri=https://login.microsoftonline.com/<tenantid>/oauth2/v2/authorize或
if v1 spring.security.oauth2.client.provider.azure.authorization-uri=https://login.microsoftonline.com/<tenantid>/oauth2/authorize
参考资料：
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/71781499
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