问Usign :给出了公司管理字典，使用递归生成一个函数以获得输出，如下所示

EN

function* levels({ name, manages = [] }, level = 1) {
  yield [name, level]
  for (const m of manages)
    yield *levels(m, level + 1)
}

const company = {"name":"George", "manages":[{"name":"James", "manages":[{"name":"Jill"},{"name":"Jenny"}]}, {"name":"Jamila", "manages":[{"name":"Jewel"}, {"name":"Jasmine"}, {"name":"Jeremey"}]}]}

for (const [name, level] of levels(company))
  console.log(`${name} is at level ${level}`)

George is at level 1
James is at level 2
Jill is at level 3
Jenny is at level 3
Jamila is at level 2
Jewel is at level 3
Jasmine is at level 3
Jeremey is at level 3

from json import loads

def levels(node, level = 1):
  yield (node['name'], level)
  try:
    for m in node['manages']:
      yield from levels(m, level + 1)
  except KeyError:
    return

company = loads('{"name":"George", "manages":[{"name":"James", "manages":[{"name":"Jill"},{"name":"Jenny"}]}, {"name":"Jamila", "manages":[{"name":"Jewel"}, {"name":"Jasmine"}, {"name":"Jeremey"}]}]}')

for (name, level) in levels(company):
  print(f"{name} is at level {level}")

George is at level 1
James is at level 2
Jill is at level 3
Jenny is at level 3
Jamila is at level 2
Jewel is at level 3
Jasmine is at level 3
Jeremey is at level 3