程序输入4个科目的5个学生分数，并输出学生和科目的最高平均分数。
程序输入4个科目的5个学生分数，并输出学生和科目的最高平均分数。
提问于 2022-04-26 04:05:14
我试图写一个程序，我需要能够输入5个学生的分数，跨越4个不同的科目，然后输出最高的平均分数的学生和科目。
所需的输入和输出是：
Student 1 (courses 1-4): 50 60 70 60
Student 2 (courses 1-4): 100 90 87 90
Student 3 (courses 1-4): 70 100 90 90
Student 4 (courses 1-4): 30 65 50 50
Student 5 (courses 1-4): 58 50 74 43
The highest average mark of students: 91.75
The highest average mark of courses: 74.2目前的代码，我有计算为一个科目，而不是4。我如何能够进入4个年级的每个学生，以获得我想要的输出。
请参阅下面的代码：
m1 = int(input("Student 1 (courses 1-4): "))
m2 = int(input("Student 2 (courses 1-4): "))
m3 = int(input("Student 3 (courses 1-4): "))
m4 = int(input("Student 4 (courses 1-4): "))
m5 = int(input("Student 5 (courses 1-4): "))
avg = (m1 + m2+ m3+ m4 + m5) / 5;
avg1 =(m1 + m2+ m3+ m4 + m5) / 20;
print("The Highest average mark of students =", avg)
print("The Highest average mark of courses =", avg1)回答 2
Stack Overflow用户
回答已采纳
发布于 2022-04-26 05:09:21
首先，创建一本字典，为每个学生输入分数。让我们称它为d_marks。创建一本字典，以获得所有学生的平均水平。我们叫它avg_marks吧。创建一本字典，以获得所有课程的总分。我们叫它avg_course吧。在那之后得到他们的max。以下是你如何做到的：
d_marks = {}
avg_marks = {}
avg_course = {}
for i in range(1,6): # We loop for 5 students
d_marks[f'Student {i} (courses 1-4)'] = list(map(int, input(f"Student {i} (courses 1-4): ").split())) # Split the string and creates an integer list
avg_marks[f'Average of Student {i}'] = sum(d_marks[f'Student {i} (courses 1-4)']) / len(d_marks[f'Student {i} (courses 1-4)']) #Create average dictionary for Students
for j in range(1, len(d_marks[f'Student {i} (courses 1-4)'])+1):
if f'Course {j} sum' in avg_course: # if course sum already in dictionary then add it to previous.
avg_course[f'Course {j} sum'] += d_marks[f'Student {i} (courses 1-4)'][j-1]
else:
avg_course[f'Course {j} sum'] = d_marks[f'Student {i} (courses 1-4)'][j-1] # if course sum not in dictionary then create one.
print("The Highest average mark of students =", max(avg_marks.values()))
print("The Highest average mark of courses =", max(avg_course.values())/ len(d_marks))输出：
Student 1 (courses 1-4): 50 60 70 60
Student 2 (courses 1-4): 100 90 87 90
Student 3 (courses 1-4): 70 100 90 90
Student 4 (courses 1-4): 30 65 50 50
Student 5 (courses 1-4): 58 50 74 43
The Highest average mark of students = 91.75
The Highest average mark of courses = 74.2Stack Overflow用户
发布于 2022-04-26 04:19:59
这段代码起作用，
import pandas as pd
import numpy as np
# Part 1
student_num = 5
all_marks = []
for i in range(student_num):
marks = input(f"Student {i + 1} (courses 1-4): ")
all_marks.append(list(map(float, marks.split(" "))))
# Part 2
df = pd.DataFrame(all_marks, columns = ['Marks'])
course_avg = df.Marks.apply(np.mean)
student_avg = df.Marks.apply(np.mean, axis = 1)代码的第一部分将输入转换为数字，并将它们存储到列表中。在第2部分中，这个列表被转换成一个数据框架。我首先在列上应用np.mean来查找每门课程的平均值，然后在行上找到每个学生的平均值。
您可以使用idxmax()在course_avg和student_avg上查找最大平均值的索引，并相应地找到平均水平最高的课程/学生。
(最好直接将值存储在.xlsx或.csv文件中，而不是以这种方式通过.csv输入它们。拥有这些文件后，只需根据文件的格式以 pd.read_csv() 或pd.read_csv()传递文件路径。)。
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原文链接：
https://stackoverflow.com/questions/72008244
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