blocks|key|3005707|text|我认为z不应该在while循环中增加，否则您将永远不会结束while循环。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3005708|palavra+=+input('Digite+a+palavra:').upper()
lista+=+list(palavra)
x+=+0+#ímpares
y+=+0+#contador
z+=+len(palavra)+#conta+o+numero+de+letras+mais+o+add

while+y+<+z:
++++if+(x%252)+==+0:
++++++++x+%2B=+1
++++else:
++++++++p+=+lista[y]*x
++++++++print(p.rjust(z))
++++++++x+%2B=+1
++++++++y+%2B=+1
++++++++#+z+%2B=+1++++|code-block|syntax|javascript|3005709|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I think z shouldn't be increased in the while loop other wise you will never end the while loop
<pre><code>palavra = input('Digite a palavra:').upper()
lista = list(palavra)
x = 0 #ímpares
y = 0 #contador
z = len(palavra) #conta o numero de letras mais o add

while y &lt; z:
 if (x%2) == 0:
 x += 1
 else:
 p = lista[y]*x
 print(p.rjust(z))
 x += 1
 y += 1
 # z += 1 
</code></pre>

blocks|key|3005790|text|，这将修复您的错误。试试这个，|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3005791|palavra+=+input('Digite+a+palavra:').upper()
lista+=+list(palavra)
print(lista)
x+=+0+#ímpares
y+=+0+#contador
z+=+len(palavra)+#conta+o+numero+de+letras+mais+o+add

while+y+<+z:
++++if+(x%252)+==+0:
++++++++x+%2B=+1
++++else:
++++++++if(len(palavra)-1+<+y):++#Check+the+length+of+string+and+y+value+to+end+the+loop
++++++++++++break
++++
++++++++p+=+lista[y]*x
++++++++print(p.rjust(z))
++++++++x+%2B=+1
++++++++y+%2B=+1
++++++++z+%2B=+1|code-block|syntax|javascript|3005792|像这样输出，|3005793|​|3005794|📷|atomic|3005795|3005796|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://developer.qcloudimg.com/http-save/yehe-900000/a70c626d85b41d18f519186feac8bee7.png|imageAlt^0|0|F|0|0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|15|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|16|8|@]|D|@]|E|$]]|$1|O|3|P|5|Q|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|R|3|N|5|6|7|1B|8|@]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z|10|-4]]]]

This will fix your error. Try this,
<pre><code>palavra = input('Digite a palavra:').upper()
lista = list(palavra)
print(lista)
x = 0 #ímpares
y = 0 #contador
z = len(palavra) #conta o numero de letras mais o add

while y &lt; z:
 if (x%2) == 0:
 x += 1
 else:
 if(len(palavra)-1 &lt; y): #Check the length of string and y value to end the loop
 break
 
 p = lista[y]*x
 print(p.rjust(z))
 x += 1
 y += 1
 z += 1
</code></pre>
Output like this,
<a href="https://i.stack.imgur.com/kjw0J.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/kjw0J.png" alt="enter image description here" /></a>

blocks|key|3537824|text|您正在迭代中递增'y‘&这就是问题所在。最后一次迭代，它将始终指向字符串和列表索引的长度，在那个时候不存在。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3537825|+palavra+=+input('Digite+a+palavra:').upper()
+lista+=+list(palavra)
+x+=+0+#ímpares
+y+=+0+#contador
+z+=+len(palavra)+#conta+o+numero+de+letras+mais+o+add
+strlen+=+len(palavra)+#conta+o+numero+de+letras+mais+o+a

while+y+<+strlen:
++if+(x%252)+==+0:
++++x+%2B=+1
++else:
++++p+=+lista[y]*x
++++print(p.rjust(z))
++++x+%2B=+1
++++y+%2B=+1
++++z+%2B=+1|code-block|syntax|javascript|3537826|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You are incrementing 'y' in iteration &amp; that's make the issue. And the last iteration the it will always pointing to length of the string and list index on that time doesn't exist
<pre><code> palavra = input('Digite a palavra:').upper()
 lista = list(palavra)
 x = 0 #ímpares
 y = 0 #contador
 z = len(palavra) #conta o numero de letras mais o add
 strlen = len(palavra) #conta o numero de letras mais o a

while y &lt; strlen:
 if (x%2) == 0:
 x += 1
 else:
 p = lista[y]*x
 print(p.rjust(z))
 x += 1
 y += 1
 z += 1
</code></pre>

blocks|key|3443806|text|palavra+=+input('Digite+a+palavra:').upper()
lista+=+list(palavra)
x+=+0+#ímpares
y+=+0+#contador
z+=+len(palavra)+#conta+o+numero+de+letras+mais+o+add
try:
+while+y+<+z:
++++if+(x%252)+==+0:
++++++++x+%2B=+1
++++else:
++++++++p+=+lista[y]*x
++++++++print(p.rjust(z))
++++++++x+%2B=+1
++++++++y+%2B=+1
++++++++z+%2B=+1
except:
++pass

#output

Digite+a+palavra:Talha
++++T
+++AAA
++LLLLL
+HHHHHHH
AAAAAAAAA|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3443807|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>palavra = input('Digite a palavra:').upper()
lista = list(palavra)
x = 0 #ímpares
y = 0 #contador
z = len(palavra) #conta o numero de letras mais o add
try:
 while y &lt; z:
 if (x%2) == 0:
 x += 1
 else:
 p = lista[y]*x
 print(p.rjust(z))
 x += 1
 y += 1
 z += 1
except:
 pass

#output

Digite a palavra:Talha
 T
 AAA
 LLLLL
 HHHHHHH
AAAAAAAAA
</code></pre>

blocks|key|3537863|text|您的代码是无效的，不能正常工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3537864|首先要做的是使用函数，这样就可以重用代码。|3537865|您应该做的第二件事是使用str.center方法。|offset|length|style|CODE|3537866|索引和字符串之间的数学关系是，每个字符串的长度是其索引长度乘以2(基于0的索引)。|3537867|因此，我重新实现了您的代码：|3537868|from+string+import+ascii_lowercase

def+pyramidize(s):
++++l+=+(len(s)+-+1)+*+2+%2B+1
++++return+'\n'.join([(c+*+(i+*+2+%2B+1)).center(l)+for+i,+c+in+enumerate(s)])
++++
print(pyramidize(ascii_lowercase))|code-block|syntax|javascript|3537869|+++++++++++++++++++++++++a+++++++++++++++++++++++++
++++++++++++++++++++++++bbb++++++++++++++++++++++++
+++++++++++++++++++++++ccccc+++++++++++++++++++++++
++++++++++++++++++++++ddddddd++++++++++++++++++++++
+++++++++++++++++++++eeeeeeeee+++++++++++++++++++++
++++++++++++++++++++fffffffffff++++++++++++++++++++
+++++++++++++++++++ggggggggggggg+++++++++++++++++++
++++++++++++++++++hhhhhhhhhhhhhhh++++++++++++++++++
+++++++++++++++++iiiiiiiiiiiiiiiii+++++++++++++++++
++++++++++++++++jjjjjjjjjjjjjjjjjjj++++++++++++++++
+++++++++++++++kkkkkkkkkkkkkkkkkkkkk+++++++++++++++
++++++++++++++lllllllllllllllllllllll++++++++++++++
+++++++++++++mmmmmmmmmmmmmmmmmmmmmmmmm+++++++++++++
++++++++++++nnnnnnnnnnnnnnnnnnnnnnnnnnn++++++++++++
+++++++++++ooooooooooooooooooooooooooooo+++++++++++
++++++++++ppppppppppppppppppppppppppppppp++++++++++
+++++++++qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq+++++++++
++++++++rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr++++++++
+++++++sssssssssssssssssssssssssssssssssssss+++++++
++++++ttttttttttttttttttttttttttttttttttttttt++++++
+++++uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu+++++
++++vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv++++
+++wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww+++
++xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx++
+yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy+
zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz|3537870|entityMap^0|0|0|C|A|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Y|8|@$F|Z|G|10|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|11|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|12|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|13|8|@]|9|@]|A|$Q|R]]|$1|S|3|T|5|P|7|14|8|@]|9|@]|A|$Q|R]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

Your code is ineffiecient and not working properly.
The first thing to do is to use functions, so that you can reuse your code.
The second thing you should do is to use <code>str.center</code> method.
The mathematical relationship between the indices and the strings is that each string has the length of its index times two (0 based indexing).
So I reimplemented your code:
<pre class="lang-py prettyprint-override"><code>
from string import ascii_lowercase

def pyramidize(s):
 l = (len(s) - 1) * 2 + 1
 return '\n'.join([(c * (i * 2 + 1)).center(l) for i, c in enumerate(s)])
 
print(pyramidize(ascii_lowercase))
</code></pre>
<pre><code> a 
 bbb 
 ccccc 
 ddddddd 
 eeeeeeeee 
 fffffffffff 
 ggggggggggggg 
 hhhhhhhhhhhhhhh 
 iiiiiiiiiiiiiiiii 
 jjjjjjjjjjjjjjjjjjj 
 kkkkkkkkkkkkkkkkkkkkk 
 lllllllllllllllllllllll 
 mmmmmmmmmmmmmmmmmmmmmmmmm 
 nnnnnnnnnnnnnnnnnnnnnnnnnnn 
 ooooooooooooooooooooooooooooo 
 ppppppppppppppppppppppppppppppp 
 qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq 
 rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr 
 sssssssssssssssssssssssssssssssssssss 
 ttttttttttttttttttttttttttttttttttttttt 
 uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 
 vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv 
 wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww 
 xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx 
 yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy 
zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
</code></pre>

Could someone explain why this error appears? the program asks for a word, and makes a pyramid with the word.
<pre><code>palavra = input('Digite a palavra:').upper()
lista = list(palavra)
x = 0 #ímpares
y = 0 #contador
z = len(palavra) #conta o numero de letras mais o add

while y &lt; z:
 if (x%2) == 0:
 x += 1
 else:
 p = lista[y]*x
 print(p.rjust(z))
 x += 1
 y += 1
 z += 1
</code></pre>

pyramid with the word received in python

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

有人能解释一下为什么会出现这个错误吗？这个程序要求一个单词，然后用这个单词制作一个金字塔。palavra = input('Digite a palavra:').upper()lista = list(palavra)x = 0 #ímparesy = 0 #contadorz = len(palavra) #con...

问金字塔，包含在python中接收到的单词
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问金字塔，包含在python中接收到的单词EN