为什么我的代码跳过所有的ifs，直接转到of语句，甚至满足if语句的要求？
为什么我的代码跳过所有的ifs，直接转到of语句，甚至满足if语句的要求？
提问于 2022-06-18 11:54:32
import random
player=""
com=""
start = input("Press enter to start")
def bj():
com = random.choice([2,3,4,5,6,7,8,9])
print(com)
player = input("Hit/Stand/Forfeit: ").lower()
print(player)
def stand():
if player_value > com and player_value != 22:
print("You win")我已经给玩家写了“没收”。但是，即使玩家没有被“没收”，它仍然在运行。
while player != 22 or player != "forfeit":
bj()这里是条件。即使你键入“击中”/“没收”/“站立”，它也会直接转到其他地方。
if player == "hit":
player_value = random.choice([2,3,4,5,6,7,8,9])
elif player == "stand" or player == 22:
stand()
break
elif player == "forfeit":
break
else:
print("Invalid. Try again")
print("----------------------")回答 2
Stack Overflow用户
发布于 2022-06-18 12:04:46
变量不能同时是两个值。因为您的条件是检查它不等于两个不同的值，所以保证其中一个或另一个值为真。你可能想：
player != 22 and player != "forfeit"
# ^^^Stack Overflow用户
发布于 2022-06-18 12:40:48
我希望这能帮到你。
import random
def stand():
print('stand')
player = 'hit' # Test different player values.
while True:
if player == "hit":
player_value = random.choice([2, 3, 4, 5, 6, 7, 8, 9])
break # This break is required. Was not in the example code.
elif player == "stand" or player == 22:
stand()
break
elif player == "forfeit":
break
else:
print("Invalid. Try again")
print("----------------------")页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/72669038
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