PySimpleGUI popup_get_folder default_path
PySimpleGUI popup_get_folder default_path
提问于 2022-06-25 15:01:21
我和popup_get_folder，PySimpleGUI有个问题。我不能设置默认路径，我得到了错误: popup()得到了一个意外的关键字参数‘default’，我能做什么呢？popup_get_folder()有一个参数"default_path“
if event == "BUTTON":
dirfiles = sg.popup_get_folder('Please enter a folder name')
sg.popup('Results', 'The value returned from popup_get_folder', dirfiles, default_path="C:/Users/User/Desktop/NEWFOLDER")回答 1
Stack Overflow用户
发布于 2022-06-25 15:06:57
查看错误消息error: popup() got an unexpected keyword argument 'default_path'
Python告诉我们导致错误的函数：popup
它还告诉我们错误是什么:当参数default_path不是popup函数所期望的内容时，您传递了这个参数。
要找出可以传递给popup函数的哪些参数，可以查看库的文档：https://pysimplegui.readthedocs.io/en/latest/#high-level-api-calls-popups
popup(args=*<1 or N object>,
title = None,
button_color = None,
background_color = None,
text_color = None,
button_type = 0,
auto_close = False,
auto_close_duration = None,
custom_text = (None, None),
non_blocking = False,
icon = None,
line_width = None,
font = None,
no_titlebar = False,
grab_anywhere = False,
keep_on_top = None,
location = (None, None),
relative_location = (None, None),
any_key_closes = False,
image = None,
modal = True)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/72754920
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