blocks|key|1790129|text|在盖克斯，他们的作用就像|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1790130|Get.back(result:"result");|code-block|syntax|javascript|1790131|所以当返回到任何页面路由时，为了触发一些功能|1790132|试着按照文档所写的方式来做|1790133|final+gotoHome+=+await+Get.toNamed(Route.name);+//+or+use+the+simple+one+Get.to(()=>+Home());|1790134|然后，如果你触发返回页面，你应该指出一些结果。|1790135|从手机的后退按钮使用威尔波普显微镜或后退按钮在用户界面。|1790136|Get.back(result:"triggerIt");+//+this+result+will+pass+to+the+home.|1790137|所以在将使用|1790138|+++//+It+depend+on+you+on+where+you+gonna+put+this
++//+onInit+or+onReady+or+anything+that+would+trigger
++++someTrigger()+async{
++++final+gotoHome+=+await+Get.toNamed(Route.name);
++++++if(gotoHome+==+"triggerIt"){
++++++++++anyFuntionYouwantoTrigger();
+++++++}+
++++}|1790139|有关它的更多信息，请阅读文档。https://github.com/jonataslaw/getx/blob/master/documentation/en_US/route_management.md|offset|length|1790140|编辑:+//也许会出现一些更好的答案，我确实有一个，但这并不是一个真正的实践，只是一个示例|1790141|您现在在当前页面中的示例，此页面还连接到主控制器或使用Get.find()，它需要将控制器绑定到页面；|1790142|class+BindingHome+with+Bindings{+++++
++@override
++void+dependencies()+{
+++Get.lazyPut(()+=>+HomeController(),+fenix:+true);
+++}+
}|1790143|然后从GetPage添加绑定|1790144|+GetPage(
+++name:+"/currentpage",
+++binding:+BindingHome(),
+++page:()+=>+HomeView(),
++),|1790145|所以，当主版被绑定到当前页面时，您现在是这样了。|1790146|//+lets+assume+this+one+is+put+to+the+CurrentController
final+homeController+=+Get.find<HomeController>();|1790147|因此，在用户界面上调用back按钮或当返回时，将尝试从家中触发该函数。|1790148|++gotBackfunction(){
++++Get.back();
++++homeController.anyFuntionYouwantoTrigger();
++}|1790149|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/jonataslaw/getx/blob/master/documentation/en_US/route_management.md^0|0|0|0|0|0|0|0|0|0|0|F|2E|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|1T|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|1U|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|1V|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|1W|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1X|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1Z|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|20|8|@]|9|@$Y|21|Z|22|1|23]]|A|$]]|$1|10|3|11|5|6|7|24|8|@]|9|@]|A|$]]|$1|12|3|13|5|6|7|25|8|@]|9|@]|A|$]]|$1|14|3|15|5|D|7|26|8|@]|9|@]|A|$E|F]]|$1|16|3|17|5|6|7|27|8|@]|9|@]|A|$]]|$1|18|3|19|5|D|7|28|8|@]|9|@]|A|$E|F]]|$1|1A|3|1B|5|6|7|29|8|@]|9|@]|A|$]]|$1|1C|3|1D|5|D|7|2A|8|@]|9|@]|A|$E|F]]|$1|1E|3|1F|5|6|7|2B|8|@]|9|@]|A|$]]|$1|1G|3|1H|5|D|7|2C|8|@]|9|@]|A|$E|F]]|$1|1I|3|-4|5|6|7|2D|8|@]|9|@]|A|$]]]|1J|$1K|$5|1L|1M|1N|A|$1O|1P]]]]

In Getx they have a funtion like
<pre><code>Get.back(result:&quot;result&quot;);
</code></pre>
so in order to trigger some funtion when going back to any page route
try doing this as the document written
<pre><code>final gotoHome = await Get.toNamed(Route.name); // or use the simple one Get.to(()=&gt; Home());
</code></pre>
then if you trigger to go back in page you should indicate some result e.g.
from back button in phone using willpopscope or a back button in UI.
<pre><code>Get.back(result:&quot;triggerIt&quot;); // this result will pass to the home.
</code></pre>
so in will use
<pre><code> // It depend on you on where you gonna put this
 // onInit or onReady or anything that would trigger
 someTrigger() async{
 final gotoHome = await Get.toNamed(Route.name);
 if(gotoHome == &quot;triggerIt&quot;){
 anyFuntionYouwantoTrigger();
 } 
 }
</code></pre>
for more info about it try to read the documentation.
<a href="https://github.com/jonataslaw/getx/blob/master/documentation/en_US/route_management.md" rel="nofollow noreferrer">https://github.com/jonataslaw/getx/blob/master/documentation/en_US/route_management.md</a>
Edited: // Maybe some answer will pop up for better
I do have one but it's not that quite a real practice just a sample
e.g // sample you are now in the current page and this page is also connected to homecontroller or using Get.find() it need to bind the controller to the page;
<pre><code>class BindingHome with Bindings{ 
 @override
 void dependencies() {
 Get.lazyPut(() =&gt; HomeController(), fenix: true);
 } 
}
</code></pre>
then from GetPage add Binding
<pre><code> GetPage(
 name: &quot;/currentpage&quot;,
 binding: BindingHome(),
 page:() =&gt; HomeView(),
 ),
</code></pre>
so while homecontroller is bind to the current page you are now so
<pre><code>// lets assume this one is put to the CurrentController
final homeController = Get.find&lt;HomeController&gt;();
</code></pre>
so while calling back button on ui or willpopscope
when back try to trigger the function from home
<pre><code> gotBackfunction(){
 Get.back();
 homeController.anyFuntionYouwantoTrigger();
 }
</code></pre>

blocks|key|1790166|text|我建议您使用Get.offNamed()而不是Get.toNamed()，因为offNamed()函数将清除存储在catch中的数据，因此在返回到该屏幕时将再次调用onInit()或onReady()生命周期中声明的API。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1790167|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

I would suggest you to use Get.offNamed() instead of Get.toNamed() as the offNamed() function will clear the data stored in catch and thus will again call the API declared in onInit() or onReady() lifecycle when returning back to that screen.

blocks|key|1790186|text|不，你不能在这样做的时候调用函数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1790187|您应该在弹出视图之前使用回调函数。|1790188|onBackClick()+async+{
++++Get.lazyPut<MainController>(
++++++++()+=>+MainController(),
++++);
++++controller.allItems.refresh();
++++Get.back();
}|code-block|syntax|javascript|1790189|下面是一个例子，您可以在没有任何复杂情况下做到这一点：|1790190|​|1790191|WillPopScope(
++++++onWillPop:+()+async+{
++++++++await+onBackClick();
++++++++return+Future(()+=>+false);
++++++},
++++++child:+Scaffold(
++++++++appBar:+CustomAppBarWithBack(
++++++++++title:+"Appbar",
++++++++++OnClickBack:+onBackClick,
++++++++),
++++++++body:+Widget(),
++++++),
++++);|1790192|1790193|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|T|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|U|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|V|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|O|3|L|5|6|7|X|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|Q|$]]

No you can't really call a function when doing so.
You should be using callback function just before popping the view.
<pre><code>onBackClick() async {
 Get.lazyPut&lt;MainController&gt;(
 () =&gt; MainController(),
 );
 controller.allItems.refresh();
 Get.back();
}
</code></pre>
Here is an example how you can do it without any complications:
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>WillPopScope(
 onWillPop: () async {
 await onBackClick();
 return Future(() =&gt; false);
 },
 child: Scaffold(
 appBar: CustomAppBarWithBack(
 title: "Appbar",
 OnClickBack: onBackClick,
 ),
 body: Widget(),
 ),
 );
 </code></pre>
</div>
</div>

I am switching from the home view to another using <code>Get.toNamed(Routes.DETAIL)</code>. When I want to return from the details view to the home view, I am calling <code>Get.back()</code> (or the user is using the back button of the devices).
Back on the home view, I would like to fetch all data from my database again.
Is there any function that is triggered when I am leaving a few and returning to it, so I can put my logic there?
Thank you

How to call a function when returning to view/controller with `Get.back()`?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在使用Get.toNamed(Routes.DETAIL)从家庭视图切换到另一个视图。当我想从details视图返回到home视图时，我调用Get.back() (或者用户正在使用设备的后退按钮)。回到主视图，我想再次从我的数据库中获取所有数据。有什么功能是触发的，当我离开几个并回到它，这样我可以把我的逻辑在那里？...

问当返回到`Get.back()`的视图/控制器时，如何调用函数？
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问当返回到`Get.back()`的视图/控制器时，如何调用函数？
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