如何为JS中的每个对象设置默认值以设置Map和/或value++
如何为JS中的每个对象设置默认值以设置Map和/或value++
提问于 2022-08-09 14:48:27
const salaries = {
Progger: {salary: 1000, tax: '15%'},
Tester: {salary: 800, tax: '10%'},
Manager: { salary: 1000, tax: '10%' },
Designer: { salary: 600, tax: '30%' },
Artist: { salary: 1500, tax: '15%' }
};
const team = [
{ name: 'Vasya', specialization: 'Tester' },
{ name: 'Taras', specialization: 'Tester' },
{ name: 'Taras I', specialization: 'Tester' },
{ name: 'Tapas', specialization: 'Humor' },
{ name: 'Misha', specialization: 'Manager' },
{ name: 'Max', specialization: 'Designer' },
{ name: 'Vova', specialization: 'Designer' },
{ name: 'Leo', specialization: 'Artist' }
];
function calculateTeamFinanceReport(salaries, team) {
const proffNames = Object.keys(salaries);
let proffesions = new Map();
let result = {};
let value;
// for (let every of proffNames) {
// proffesions.set(every, 0)
// }
for (let i = 0; i < team.length; i++) {
let specialization = team[i].specialization;
if (proffNames.some(proffesion => { //specialisation has to be salaries `team.specialization == salaries[any]`
if (specialization === proffesion) {
value = value || 0;
proffesions.set(proffesion, value++); // Right count here needed
}
}))
i++;
}
return proffesions
}结果= 'Progger‘=> 1，'Tester’=> 4，'Manager‘=> 5，'Designer’=> 7，'Artist‘=> 8
我需要在这里数一数人们有多少准确的职业。相反，我得到了总数。另外，来自team的team必须在salaries中，否则=忽略并继续。
team.specialization == salaries[any]如何对每个行业进行正确的计数？或者如何将默认值1设置为proffesions映射对象，然后将其设置为++？
回答 2
Stack Overflow用户
回答已采纳
发布于 2022-08-09 15:35:03
H 212H 113然后.get() .get() proffesions映射，并将value添加到salary中的.set()新value到proffesions地图。HF 226
const salaries={Programmer:{salary:1e3,tax:"15%"},Tester:{salary:800,tax:"10%"},Manager:{salary:1e3,tax:"10%"},Designer:{salary:600,tax:"30%"},Executive:{salary:1500,tax:"15%"}},team=[{name:"Vasya",specialization:"Tester"},{name:"Taras",specialization:"Tester"},{name:"Taras I",specialization:"Tester"},{name:"Tapas",specialization:"Programmer"},{name:"Misha",specialization:"Manager"},{name:"Max",specialization:"Designer"},{name:"Vova",specialization:"Designer"},{name:"Leo",specialization:"Executive"},
{name:"Ivan",specialization:"Unemployed"}];
function calculateTeamFinanceReport(salaries, team) {
const proffNames = Object.keys(salaries);
let proffesions = new Map();
let dept = {};
let value = 0;
for (let i = 0; i < team.length; i++) {
let specialization = team[i].specialization;
proffNames.forEach(proffesion => {
if (specialization === proffesion) {
value = salaries[proffesion]['salary'] || 0;
if (!dept[proffesion]) {
proffesions.set(proffesion, 0);
dept[proffesion] = 0;
}
dept[proffesion] = value;
let v = proffesions.get(proffesion);
value = v + value;
proffesions.set(proffesion, value);
}
});
}
return proffesions
}
console.log(Array.from(calculateTeamFinanceReport(salaries, team).entries()));
Stack Overflow用户
发布于 2022-08-09 16:51:18
function totalMembers(teams, selectedTeam) {
return teams.filter(team => team === selectedTeam)?.length;
}此函数将返回团队数组中提供的团队的成员总数。
function calculateTeamFinanceReport(salaries, team) {
const teamHashTable = {};
let totalMember = 1;
for (const specialization in salaries) {
const teamSpecializations = team.map(t => t.specialization);
totalMember += totalMembers(teamSpecializations, specialization);
teamHashTable[specialization] = totalMember;
}
return teamHashTable;
}将totalMember用于专门化，然后将其保存为专门化，然后从那里开始下一轮，以此类推。
输出：
希望这个答案能帮上忙！
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原文链接：
https://stackoverflow.com/questions/73293842
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