X3Daudio与XAudio2的集成
X3Daudio与XAudio2的集成
提问于 2022-08-15 20:32:23
目前，我正努力用XAudio2库实现三维位置声音。当听者和源的位置在所有轴上都是0.0f时，我设法使它工作起来。当我移动听众或源，甚至一点点，声音不再被听到，但仍然在播放。我在这里错过了什么？谢谢:)
uint32_t sourceInputChannels = 2;
uint32_t masterInputChannels = 8;
float* outputMatrix = new float[masterInputChannels * sourceInputChannels];
// Listener
X3DAUDIO_LISTENER listener{};
listener.Position = { 0.0f, 0.0f, 0.0f };
listener.Velocity = { 0.0f, 0.0f, 0.0f };
listener.OrientFront = { 1.0f, 0.0f, 0.0f };
listener.OrientTop = { 0.0f, 0.0f, 1.0f };
// Emitter
X3DAUDIO_EMITTER sourceEmitter{};
sourceEmitter.ChannelCount = 1;
sourceEmitter.CurveDistanceScaler = FLT_MIN;
sourceEmitter.Position = { 0.0f, 0.0f, 0.0f };
sourceEmitter.Velocity = { 0.0f, 0.0f, 0.0f };
sourceEmitter.OrientFront = { 1.0f, 0.0f, 0.0f };
sourceEmitter.OrientTop = { 0.0f, 0.0f, 1.0f };
sourceEmitter.ChannelRadius = 2.0f;
sourceEmitter.InnerRadius = 2.0f;
sourceEmitter.InnerRadiusAngle = X3DAUDIO_PI / 4.0f;
X3DAUDIO_DSP_SETTINGS dspSettings{};
dspSettings.SrcChannelCount = sourceEmitter.ChannelCount; // 1
// 8 * 2, OUTPUT_CHANNELS is also present in CreateMasteringVoice
dspSettings.DstChannelCount = OUTPUT_CHANNELS * sourceVoiceDetails.InputChannels;
dspSettings.pMatrixCoefficients = outputMatrix;
// Calculating
X3DAudioCalculate(g_CealContext->X3DInstance, &listener, &sourceEmitter, X3DAUDIO_CALCULATE_MATRIX |
X3DAUDIO_CALCULATE_DOPPLER | X3DAUDIO_CALCULATE_LPF_DIRECT | X3DAUDIO_CALCULATE_REVERB, &dspSettings);
sourceVoice->SetOutputMatrix(g_CealContext->XMasterVoice, sourceInputChannels, masterInputChannels, outputMatrix);
delete[] outputMatrix;Stack Overflow用户
发布于 2022-08-19 21:09:35
X3DAudio有很多参数，但我猜问题是，您有一个立体声(2声道)源声音，并且正在尝试使用1声道DSP设置。您还传递了许多X3DAUDIO_CALCULATE_标志，这些标志需要比所提供的数据更多的数据。
您应该看看原始的DirectX SDK XAudio2示例，它们托管在GitHub上。特别是，请参见XAudio2Sound3D。
您还应该看看音频DirectX工具包。
另外，sourceEmitter.CurveDistanceScaler和sourceEmitter.DopplerScaler通常应该是1.0。
更新：如果SrcChannelCount大于1，则必须提供发射器方位。我在DirectX工具工具包中有一个用于音频AudioEmitter::EnableDefaultMultiChannel的帮助方法，它基于简单的扬声器几何来设置它们--这就是传统XACT处理它们的方式。
// **Note these constants came from xact3d3.h in the legacy DirectX SDK**
//
// Supported speaker positions, represented as azimuth angles.
//
// Here's a picture of the azimuth angles for the 8 cardinal points,
// seen from above. The emitter's base position is at the origin 0.
//
// FRONT
// | 0 <-- azimuth
// |
// 7pi/4 \ | / pi/4
// \ | /
// LEFT \|/ RIGHT
// 3pi/2-------0-------pi/2
// /|\
// / | \
// 5pi/4 / | \ 3pi/4
// |
// | pi
// BACK
//
constexpr float LEFT_AZIMUTH = 3 * X3DAUDIO_PI / 2;
constexpr float RIGHT_AZIMUTH = X3DAUDIO_PI / 2;
constexpr float FRONT_LEFT_AZIMUTH = 7 * X3DAUDIO_PI / 4;
constexpr float FRONT_RIGHT_AZIMUTH = X3DAUDIO_PI / 4;
constexpr float FRONT_CENTER_AZIMUTH = 0.0f;
constexpr float LOW_FREQUENCY_AZIMUTH = X3DAUDIO_2PI;
constexpr float BACK_LEFT_AZIMUTH = 5 * X3DAUDIO_PI / 4;
constexpr float BACK_RIGHT_AZIMUTH = 3 * X3DAUDIO_PI / 4;
constexpr float BACK_CENTER_AZIMUTH = X3DAUDIO_PI;
constexpr float c_channelAzimuths[9][8] =
{
/* 0 */ { 0.f, 0.f, 0.f, 0.f, 0.f, 0.f, 0.f, 0.f },
/* 1 */ { 0.f, 0.f, 0.f, 0.f, 0.f, 0.f, 0.f, 0.f },
/* 2 */ { FRONT_LEFT_AZIMUTH, FRONT_RIGHT_AZIMUTH, 0.f, 0.f, 0.f, 0.f, 0.f, 0.f },
/* 2.1 */ { FRONT_LEFT_AZIMUTH, FRONT_RIGHT_AZIMUTH, LOW_FREQUENCY_AZIMUTH, 0.f, 0.f, 0.f, 0.f, 0.f },
/* 4.0 */ { FRONT_LEFT_AZIMUTH, FRONT_RIGHT_AZIMUTH, BACK_LEFT_AZIMUTH, BACK_RIGHT_AZIMUTH, 0.f, 0.f, 0.f, 0.f },
/* 4.1 */ { FRONT_LEFT_AZIMUTH, FRONT_RIGHT_AZIMUTH, LOW_FREQUENCY_AZIMUTH, BACK_LEFT_AZIMUTH, BACK_RIGHT_AZIMUTH, 0.f, 0.f, 0.f },
/* 5.1 */ { FRONT_LEFT_AZIMUTH, FRONT_RIGHT_AZIMUTH, FRONT_CENTER_AZIMUTH, LOW_FREQUENCY_AZIMUTH, BACK_LEFT_AZIMUTH, BACK_RIGHT_AZIMUTH, 0.f, 0.f },
/* 6.1 */ { FRONT_LEFT_AZIMUTH, FRONT_RIGHT_AZIMUTH, FRONT_CENTER_AZIMUTH, LOW_FREQUENCY_AZIMUTH, BACK_LEFT_AZIMUTH, BACK_RIGHT_AZIMUTH, BACK_CENTER_AZIMUTH, 0.f },
/* 7.1 */ { FRONT_LEFT_AZIMUTH, FRONT_RIGHT_AZIMUTH, FRONT_CENTER_AZIMUTH, LOW_FREQUENCY_AZIMUTH, BACK_LEFT_AZIMUTH, BACK_RIGHT_AZIMUTH, LEFT_AZIMUTH, RIGHT_AZIMUTH }
};
...
emitter.ChannelCount = channels;
emitter.ChannelRadius = 1.f;
emitter.pChannelAzimuths = (channels <= 8)
? &c_channelAzimuths[channels] : nullptr;页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/73366157
复制相关文章
相似问题
腾讯云开发者
