复杂字典获得条件为字符串的值
复杂字典获得条件为字符串的值
提问于 2022-08-21 18:02:27
我已经使用laanlabs/SwiftSurvey调查构建了一项调查，并且我能够作为字典从surveyComplete方法中获得结果。
结果以一个复杂的结构返回，我需要通过questions数组-> question对象的键->来获取每个响应的值。这个对象包含一个choices数组，在每个选择对象中都有一个selected键。如果所选键的值为true (1)，则需要获取位于同一对象中的text键的值。其中一些选项将有多个selected键，值为true (1)，如果是这样的话，我希望在值之间用逗号连接text键值。
然后将密钥插入到SQLite数据库中。
我刚开始对字典进行解码并以正确的方式遍历它们，我可以访问字典print(dictionary)，也可以进入正确的NSArray - print(dictionary["questions"]，但是从那里我很困惑，有人能告诉我怎么做吗？
结果如下，不幸的是，这是一个很大的块道歉。
[
"version": 001,
"metadata":
{
"app_version" = "1.1";
build = 22;
debug = true;
},
"questions": <__NSArrayI 0x600000614d20>(
{
question = {
allowsMultipleSelection = 0;
choices = (
{
allowsCustomTextEntry = 0;
selected = 1;
text = Physician;
uuid = "224E1B76-D220-4068-AA22-6861E5F836CB";
},
{
allowsCustomTextEntry = 0;
selected = 0;
text = Dietitian;
uuid = "2DB2B6FB-E344-4BBF-A551-2FABE0DFF6AA";
},
{
allowsCustomTextEntry = 0;
selected = 0;
text = "Genetic Counsellor";
uuid = "A9BE7093-B95C-4BF4-B629-12FDA3154ABE";
},
{
allowsCustomTextEntry = 0;
selected = 0;
text = "Nurse/Nurse Practitioner/Physician Assistant";
uuid = "8E75A41B-0D8C-4ADA-A31C-2BC408F8269D";
},
{
allowsCustomTextEntry = 0;
selected = 0;
text = "Pharmacist / Pharmaceutical Industry";
uuid = "C943430D-EA48-4BCB-8ADF-011A223BDF36";
},
{
allowsCustomTextEntry = 0;
selected = 0;
text = "Academic/Researcher";
uuid = "E28377A4-37FC-4351-A857-88383A3D5A3B";
},
{
allowsCustomTextEntry = 0;
selected = 0;
text = "Patient/Patient Advocacy Group";
uuid = "E5836187-6C08-4272-A88E-40578F4FCF44";
},
{
allowsCustomTextEntry = 1;
selected = 0;
text = "Other (please specify)";
uuid = "EFF22342-48A9-4B8E-81A0-BB44D0E86EBC";
}
);
required = 1;
tag = "hcp-specialty";
title = "Please select the option that best describes your specialty:";
uuid = "7F77E248-8429-463E-9291-241B94BEE4F8";
};
type = 0;
},
{
question = {
autoAdvanceOnChoice = 1;
choices = (
{
allowsCustomTextEntry = 0;
selected = 1;
text = Yes;
uuid = "3C7A330D-F16B-4F3E-8ABC-6767A1A6332A";
},
{
allowsCustomTextEntry = 0;
selected = 0;
text = No;
uuid = "0E4F5360-FCCD-4860-9971-86E23BB8F6C1";
}
);
required = 1;
tag = "newborn-screening";
title = "Is newborn screening for classical homocystinuria available in your region/country?";
uuid = "F7C1A9D5-43AB-420D-80CF-F6644B95C73E";
};
type = 1;
},
{
question = {
feedback = "This is a free text response";
required = 1;
tag = "biggest-unmet-need";
title = "What do you believe is the biggest unmet need for patients living with classical HCU?";
uuid = "133E2EDC-8FF4-48D1-8BFA-3A20E5DA0052";
};
type = 4;
}
)
]回答 1
Stack Overflow用户
发布于 2022-08-21 19:06:42
根据他们的结果示例，您将得到JSON。当然，将JSON转换为Dictionary是最简单的，但也是最脏的。你基本上是得到“任何”，所以当是时候使用数据，你必须做很多-如你所说-“解码”，验证，等等。
相反，创建一些与您的响应相匹配的Decodable结构。在这种情况下，只需要3种结构：
struct Survey: Codable {
let questions: [Question]
}
struct Question: Codable {
let allowsMultipleSelection: Int?
let choices: [Choice]?
let required: Int
let tag: String
let title: String
let uuid: String
let feedback: String?
}
struct Choice: Codable {
let allowsCustomTextEntry: Int
let selected: Int
let text: String
let uuid: String
}(我没有核实每个字段，你可以根据需要进行调整。你可以省略任何你不需要/不关心的属性。)
然后你像这样解码它：
// Assume jsonData is your original JSON, which you currently decode as dictionary. So instead you do this:
let decoder = JSONDecoder()
let product = try decoder.decode(Survey.self, from: jsonData)这种方法允许您
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/73437018
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