更改R中的行名
更改R中的行名
提问于 2022-09-06 14:59:28
我有两个具有类似行名的数据文件：
> rownames(abundance)[1:10]
[1] "X001.V2.fastq_mapped_to_agora.txt.uniq"
[2] "X001.V8.fastq_mapped_to_agora.txt.uniq"
[3] "X003.V17.fastq_mapped_to_agora.txt.uniq"
[4] "X003.V2.fastq_mapped_to_agora.txt.uniq"
[5] "X003.V8.fastq_mapped_to_agora.txt.uniq"
[6] "X004.V2.fastq_mapped_to_agora.txt.uniq"
[7] "X004.V8.fastq_mapped_to_agora.txt.uniq"
[8] "X005.V2.fastq_mapped_to_agora.txt.uniq"
[9] "X005.V8.fastq_mapped_to_agora.txt.uniq"
[10] "X006.V2.fastq_mapped_to_agora.txt.uniq"
> rownames(fluxes)[1:10]
[1] "001.V8" "003.V17" "003.V2" "003.V8" "004.V2" "004.V8" "005.V2"
[8] "005.V8" "006.V2" "006.V8" 但是数据丰度的行名更大。如何使每一行的名称像流的行名一样。可以是从"X“到”第二“。”
回答 2
Stack Overflow用户
发布于 2022-09-06 15:02:53
我们可以使用trimws
rownames(abundance) <- trimws(rownames(abundance), whitespace = "\\..*")也可能是
rownames(abundance) <- sub("^([^.]+\\.[^.]+)\\..*", "\\1", rownames(abundance))-testing
> trimws("X001.V2.fastq_mapped_to_agora.txt.uniq", whitespace = "\\..*")
[1] "X001"
> sub("^([^.]+\\.[^.]+)\\..*", "\\1", "X001.V2.fastq_mapped_to_agora.txt.uniq")
[1] "X001.V2"Stack Overflow用户
发布于 2022-09-06 15:05:04
我们可以用sub
rownames(abundance) <- sub("X(.*)\\.fastq_mapped_to_agora\\.txt\\.uniq", "\\1", rownames(abundance))输出：
[1] "001.V2" "001.V8" "003.V17" "003.V2" "003.V8" "004.V2" "004.V8" "005.V2" "005.V8" "006.V2" 页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/73624121
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