问如何生成一定数量的随机整数，这些整数加起来至少等于某个数或更多？

EN

import random

low,high = 2,6
count = 10
target = 40

k = []
r = range(low,high+1)
tries = 0
while True:
    k.append(random.choice(r))
    if len(k) == count:
        if sum(k) == target:
            break
        k = k[1:]
        tries += 1
        
print(k)
print(len(k))
print(sum(k))
print(tries)

from itertools import combinations_with_replacement as combine
from random import choice, shuffle

sequences = [list(combo) for combo in combine(range(2, 6+1), 10) if sum(combo) == 40]

def get_random_sequence_of_sum_40():
    seq = choice(sequences)
    shuffle(seq)
    return seq

# ... later when you need random sequences of sum=40
for i in range(10):
    rand_sequence = get_random_sequence_of_sum_40()
    print(f"The sum of {rand_sequence} is {sum(rand_sequence)}")

The sum of [6, 3, 4, 4, 3, 3, 4, 6, 5, 2] is 40
The sum of [3, 3, 5, 3, 5, 5, 3, 3, 5, 5] is 40
The sum of [3, 3, 6, 3, 4, 6, 3, 4, 4, 4] is 40
The sum of [6, 6, 5, 3, 4, 3, 3, 2, 4, 4] is 40
The sum of [5, 2, 2, 4, 4, 4, 5, 4, 4, 6] is 40
The sum of [4, 4, 4, 3, 4, 4, 3, 6, 4, 4] is 40
The sum of [4, 4, 5, 4, 2, 4, 4, 5, 5, 3] is 40
The sum of [4, 2, 6, 2, 5, 6, 2, 5, 4, 4] is 40
The sum of [3, 6, 3, 4, 3, 3, 4, 4, 6, 4] is 40
The sum of [2, 2, 6, 2, 3, 5, 6, 4, 4, 6] is 40

import random as rd

run = True
while run:
    list = []
    for i in range(10):
        ran_num = rd.randint(2, 6)
        list.append(ran_num)
        if sum(list) >= 40 and len(list) == 10:
            print(list)
            run = False