我试着用邮件类发送一封简单的电子邮件。我已经在网上学习了这个教程,但是我仍然会收到这个错误。我不知道问题可能是什么,因为一切看起来都很好,我已经一步一步地遵循了教程。我做错了什么?
TestMail.php
<?php
namespace App\Mail;
use Illuminate\Bus\Queueable;
use Illuminate\Contracts\Queue\ShouldQueue;
use Illuminate\Mail\Mailable;
use Illuminate\Queue\SerializesModels;
class TestMail extends Mailable
{
use Queueable, SerializesModels;
public $details;
/**
* Create a new message instance.
*
* @return void
*/
public function __construct($details)
{
$this->details = $details;
}
/**
* Build the message.
*
* @return $this
*/
public function build()
{
return $this->subject('Test Mail from Duke')->view('emails.TestMail');
}
}MailController
<?php
namespace App\Http\Controllers;
use App\Mail\TestMail;
use Illuminate\Http\Request;
use Illuminate\Support\Facades\Mail;
class MailController extends Controller
{
//
public function sendEmail()
{
$details = [
'title' => 'The Title',
'body' => 'The body should be fine',
];
Mail::to("sirduketylo@gmail.com")->send(new TestMail());
return "Email Sent";
}
}路由
<?php
use App\Http\Controllers\MailController;
use Illuminate\Support\Facades\Route;
Route::get('/', function () {
return view('welcome');
});
Route::get('/send', [MailController::class, 'sendEmail']);发布于 2022-09-11 04:02:30
TestMail对象需要在其构造函数中传递一个$details参数,但没有提供任何参数。
(MailController)
而不是:❌
Mail::to("sirduketylo@gmail.com")->send(new TestMail());使用这个:✅
Mail::to("sirduketylo@gmail.com")->send(new TestMail($details));附录
我想您打算将$details传递给视图。因此:
(TestMail.php)
// ...
return $this
->subject('Test Mail from Duke')
->view('emails.TestMail')
->with("details", $this->details);
// ...https://stackoverflow.com/questions/73676656
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