blocks|key|1171009|text|这里的问题是sb.replaceAll("0","")什么也不做。您正在丢弃包含已替换字符串的返回值。见这里。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1171010|你可能想要的是这样的东西：|1171011|while+(sb.length()+>+0+&&+sb.charAt(sb.length()+-+1)+==+'0')+{
++++sb+=+sb.replaceAll("0","+");|code-block|syntax|javascript|1171012|不过，我不确定您是否需要一个while循环。ReplaceAll会..。用空格替换所有的零。|1171013|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#replaceAll(java.lang.String,%2520java.lang.String))^0|6|L|1G|2|0|0|0|0|E|5|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|6|7|12|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|13|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

The problem here is that <code>sb.replaceAll(&quot;0&quot;,&quot;&quot;)</code> won't do anything. You're throwing away the return value that contains your replaced string. See <a href="https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#replaceAll(java.lang.String,%20java.lang.String)" rel="nofollow noreferrer">here</a>.
What you probably want is something like this:
<pre><code>while (sb.length() &gt; 0 &amp;&amp; sb.charAt(sb.length() - 1) == '0') {
 sb = sb.replaceAll(&quot;0&quot;,&quot; &quot;);
</code></pre>
I'm not sure you need a <code>while</code> loop, though. ReplaceAll will... replace all of the zeros with spaces.

blocks|key|1171048|text|replaceAll用您想要的字符(即空格)替换所有出现的字符串，这样您就根本不需要循环了，而且您还担心溢出，所以您应该实际使用BigInteger作为参数，而不是int+(int不适合任何接近20!)但是您的代码还有另一个问题，您说要替换尾随零，但是现在要用空字符替换每一个0，您应该尝试使用类似于https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/StringUtils.html的|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1171049|public+class+newuhu+{
public+static+int+numTrailingZeros(BigInteger+s)+{
++++String+sb+=+s.toString();
++++return+Integer.parseInt(sb.replaceAll("0",+""));+//+consider+returning+something+else+if+you're+working+with+BigInteger
}|code-block|syntax|javascript|1171050|entityMap|0|LINK|mutability|MUTABLE|url|https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/StringUtils.html^0|46|2O|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

replaceAll replaces all occurrences of string with character that you want (ie space) so you don't need loop at all, also you're concerned about overflow so you should actually use BigInteger as a parameter, not int (int wont fit anything close to 20!) but there's another issue with your code, you said you want to replace trailing zeros but right now you will replace every 0 with blank character, you should try to use something like <a href="https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/StringUtils.html" rel="nofollow noreferrer">https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/StringUtils.html</a>
<pre><code>public class newuhu {
public static int numTrailingZeros(BigInteger s) {
 String sb = s.toString();
 return Integer.parseInt(sb.replaceAll(&quot;0&quot;, &quot;&quot;)); // consider returning something else if you're working with BigInteger
}
</code></pre>

blocks|key|269136|text|请记住，当执行BigInteger.valueOf(int)时不会产生任何效果，因为int将永远不会存储在int中。也是20！对int来说没问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|269137|public+static+String+trimTrailingZeros(String+source)+{
++++for+(int+i+=+source.length()+-+1;+i+>+0;+%2B%2Bi)+{
++++++++char+c+=+source.charAt(i);
++++++++if+(c+!=+'0')+{
++++++++++++return+source.substring(0,+i+%2B+1);
++++++++}
++++}
++++return+"";+//+or+return+"0";
}|code-block|syntax|javascript|269138|或者如果你是BigInteger的话。|269139|public+static+BigInteger+trimTrailingZeros(BigInteger+num)+{
++++while+(num.remainder(BigInteger.TEN).signum()+==+0)+{
++++++++num+=+num.divide(BigInteger.TEN);+
++++}
++++return+num;
}|269140|这应该是快速的，因为您只创建一个字符串(通过子串+)。|269141|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#valueOf(long)|1|https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#substring(int%2529)^0|7|N|0|0|0|0|0|M|2|1|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|13|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|15|8|@]|9|@$A|16|B|17|1|18]]|C|$]]|$1|O|3|-4|5|6|7|19|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]]]

Keep in mind that when doing <a href="https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#valueOf(long)" rel="nofollow noreferrer">BigInteger.valueOf(int)</a> does not have an effect as a number to big for int will never be stored in an int. Also 20! is fine for int.
<pre><code>public static String trimTrailingZeros(String source) {
 for (int i = source.length() - 1; i &gt; 0; ++i) {
 char c = source.charAt(i);
 if (c != '0') {
 return source.substring(0, i + 1);
 }
 }
 return &quot;&quot;; // or return &quot;0&quot;;
}
</code></pre>
Or if you prever BigInteger.
<pre><code>public static BigInteger trimTrailingZeros(BigInteger num) {
 while (num.remainder(BigInteger.TEN).signum() == 0) {
 num = num.divide(BigInteger.TEN); 
 }
 return num;
}
</code></pre>
This should be fast as you only create one string (via <a href="https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#substring(int)" rel="nofollow noreferrer">substring</a>).

blocks|key|1171128|text|(首先:变量和字段应该以小写字母开头-当没有常量时。)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1171129|它应该是|1171130|sb+=+sb.replaceAll(...)|code-block|syntax|javascript|1171131|由于sb不被replaceAll更改，因此只返回已替换的值。类字符串提供不变的值，这些值始终保持不变，因此您可以将一个变量分配给一个变量，而任何一个变量的更改值都不会影响另一个变量--不再共享。|offset|length|style|CODE|1171132|那就应该是：|1171133|sb+=+sb.replaceFirst("0$",+"");|1171134|replaceAll将每0替换一次，如"23043500“改为"23435”。|1171135|replaceFirst替换_regular表达式:+char+'0‘在$末尾。|1171136|不可能在输入编号上溢出，因为您已经在传递一个int。|1171137|public+static+int+numTrailingZeros(int+n)+{
++++while+(n+!=+0+&&+n+%25+10+==+0)+{
++++++++n+/=+10;
++++}
++++return+n;
}

public+static+int+numTrailingZeros(String+n)+{
++++n+=+n.replaceAll("0%2B",+"");
++++if+(n.isEmpty()+%7C%7C+n.equals("-"))+{+//+"-0"+for+pessimists?
+++++++n+=+"0";
++++}
++++return+Integer.parseInt(n);
}|1171138|%25是模运算符，其馀的整数除以147+%25+10+==+7.|1171139|这个名字是误导的，或者你在计算不同的东西。|1171140|public+static+int+numTrailingZeros(int+n)+{
++++int+trailingZeros+=+0;
++++while+(n+!=+0+&&+n+%25+10+==+0)+{
++++++++n+/=+10;
++++++++%2B%2BtrailingZeros+;
++++}
++++return+trailingZeros+;
}|1171141|entityMap^0|0|0|0|2|2|6|A|0|0|0|0|A|0|0|C|10|1|0|M|3|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|19|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|1A|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|1B|8|@$K|1C|L|1D|M|N]|$K|1E|L|1F|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|1G|8|@]|9|@]|A|$]]|$1|Q|3|R|5|F|7|1H|8|@]|9|@]|A|$G|H]]|$1|S|3|T|5|6|7|1I|8|@$K|1J|L|1K|M|N]]|9|@]|A|$]]|$1|U|3|V|5|6|7|1L|8|@$K|1M|L|1N|M|N]|$K|1O|L|1P|M|N]]|9|@]|A|$]]|$1|W|3|X|5|6|7|1Q|8|@$K|1R|L|1S|M|N]]|9|@]|A|$]]|$1|Y|3|Z|5|F|7|1T|8|@]|9|@]|A|$G|H]]|$1|10|3|11|5|6|7|1U|8|@$K|1V|L|1W|M|N]]|9|@]|A|$]]|$1|12|3|13|5|6|7|1X|8|@]|9|@]|A|$]]|$1|14|3|15|5|F|7|1Y|8|@]|9|@]|A|$G|H]]|$1|16|3|-4|5|6|7|1Z|8|@]|9|@]|A|$]]]|17|$]]

(First: variables and fields should start with a small letter - when no constants.)
It should be
<pre><code>sb = sb.replaceAll(...)
</code></pre>
as <code>sb</code> is not changed by <code>replaceAll</code>, only the replaced value is returned. The class String gives immutable values, that always remain the same, so you can assign a variable to a variable and changing values of either variable will never influence the other - no further sharing.
Then it should be:
<pre><code>sb = sb.replaceFirst(&quot;0$&quot;, &quot;&quot;);
</code></pre>
<code>replaceAll</code> would replace every 0, like &quot;23043500&quot; to &quot;23435&quot;.
<code>replaceFirst</code> replaces the _regular expression: char '0' at the end <code>$</code>.
Overflow on the input number is not possible, as you are already passing an <code>int</code>.
<pre><code>public static int numTrailingZeros(int n) {
 while (n != 0 &amp;&amp; n % 10 == 0) {
 n /= 10;
 }
 return n;
}

public static int numTrailingZeros(String n) {
 n = n.replaceAll(&quot;0+&quot;, &quot;&quot;);
 if (n.isEmpty() || n.equals(&quot;-&quot;)) { // &quot;-0&quot; for pessimists?
 n = &quot;0&quot;;
 }
 return Integer.parseInt(n);
}
</code></pre>
<code>%</code> is the modulo operator, the remainder of an integer division 147 % 10 == 7.
The name is misleading, or you are calculating something different.
<pre><code>public static int numTrailingZeros(int n) {
 int trailingZeros = 0;
 while (n != 0 &amp;&amp; n % 10 == 0) {
 n /= 10;
 ++trailingZeros ;
 }
 return trailingZeros ;
}
</code></pre>

I'm trying to remove trailing zeroes from an integer and here is my code so far.
<pre><code>import java.math.BigInteger;

public class newuhu {
 public static int numTrailingZeros(int s) {
 BigInteger J = BigInteger.valueOf(s);
 String sb = J.toString();
 String Y = &quot;&quot;;
 while (sb.length() &gt; 0 &amp;&amp; sb.charAt(sb.length() - 1) == '0') {
 sb.replaceAll(&quot;0&quot;,&quot; &quot;);


 }
 return Integer.parseInt(Y);
 }
</code></pre>
Note: I turned my int into a Biginteger because I've been warned that some inputs may look like 20!, which is 2.432902e+18
However, my IntelliJ debugging tool tells me that variable sb isn't in the loop. So, I'm trying to understand what must be done to make sure <code>sb</code> is in the loop.
Please understand that I'm a beginner in Java so, I'm trying to learn something new.

How can I loop through all the characters that are 0 in a given string?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋 

腾讯云代码助手

CODING DevOps

Cloud Studio

SDK中心

API中心

命令行工具

我试图从一个整数中移除尾随零，这是我目前为止的代码。import java.math.BigInteger;public class newuhu {    public static int numTrailingZeros(int s) {        BigInteger J = BigInteger.valu...

问如何循环遍历给定字符串中的所有字符？
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何循环遍历给定字符串中的所有字符？EN