select users.name
from(
select users.name, pay.uid,
RANK() OVER(ORDER BY count(pay.uid) DESC) AS ranking
from pay, users
where users.uid = pay.uid
group by users.uid)
where ranking = 1我只想得到users.name输出,而不是名字,uid,排名。
发布于 2022-10-12 23:44:30
如果我读到您的问题,您可以使用以下查询:
select table.name
from(select users.name, loans.uid, RANK() OVER(ORDER BY count(loans.uid) DESC) AS ranking from loans left join users on users.uid = loans.uid group by users.uid) as 'table'
where ranking = 1https://stackoverflow.com/questions/74048961
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