blocks|key|774087|text|您可以尝试匹配上面，然后是上面或上面%2B而不是上面：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|774088|​|774089|m+=+'FooBARBazAB'.match(/([A-Z](?=[A-Z]%7C$))%2B%7C[A-Z][%5EA-Z]*/g)

console.log(m)|code-block|syntax|javascript|774090|774091|但不确定这是如何“更清洁”。|774092|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

<p>You can try to match upper, followed by upper or upper + not upper:</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>m = 'FooBARBazAB'.match(/([A-Z](?=[A-Z]|$))+|[A-Z][^A-Z]*/g)

console.log(m)</code></pre>
</div>
</div>
</p>
<p>Not sure about how this is &quot;cleaner&quot; though.</p>


blocks|key|655403|text|像/([][]%2B)/g这样的简单正则表达式已经实现了.技巧是+https://javascript.info/regexp-groups+，它在与+https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split#description+方法一起使用时会被保存下来。因此，您只需要使用一个组模式(一个大写字母后面至少有一个小写字母)，并免费获得其余的(一个有效的所有大写字母组)。另外，由于拆分数组还包含空字符串值，因此需要运行额外的filter任务。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|CODE|entityRanges|data|655404|​|655405|console.log(
++'just+split+...\n',
++'"FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar"+=>',

++'FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar'
++++.split(/([A-Z][a-z]%2B)/g)
);
console.log(
++'split+and+filter+...\n',
++'"FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar"+=>',

++'FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar'
++++.split(/([A-Z][a-z]%2B)/g)
++++.filter(val+=>+val+!==+'')
);
console.log(
++'split,+filter+and+join+...\n',
++'"FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar"+=>\n',

++'FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar'
++++.split(/([A-Z][a-z]%2B)/g)
++++.filter(val+=>+val+!==+'')
++++.join('+')
);|code-block|syntax|javascript|655406|.as-console-wrapper+{+min-height:+100%25!important;+top:+0;+}|655407|655408|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/r/q2Pzyh/1|1|https://javascript.info/regexp-groups|2|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split#description|3|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter^0|R|3|1X|4|50|2|7Q|6|1|A|0|V|11|1|22|2X|2|7Q|6|3|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]|$9|19|A|1A|B|C]|$9|1B|A|1C|B|D]]|E|@$9|1D|A|1E|1|1F]|$9|1G|A|1H|1|1I]|$9|1J|A|1K|1|1L]|$9|1M|A|1N|1|1O]]|F|$]]|$1|G|3|H|5|6|7|1P|8|@]|E|@]|F|$]]|$1|I|3|J|5|K|7|1Q|8|@]|E|@]|F|$L|M]]|$1|N|3|O|5|K|7|1R|8|@]|E|@]|F|$L|M]]|$1|P|3|H|5|6|7|1S|8|@]|E|@]|F|$]]|$1|Q|3|-4|5|6|7|1T|8|@]|E|@]|F|$]]]|R|$S|$5|T|U|V|F|$W|X]]|Y|$5|T|U|V|F|$W|Z]]|10|$5|T|U|V|F|$W|11]]|12|$5|T|U|V|F|$W|13]]]]

<p>A simple regex like <a href="https://regex101.com/r/q2Pzyh/1" rel="nofollow noreferrer"><strong><code>/([A-Z][a-z]+)/g</code></strong></a> already does it ... <em><strong>the trick is the <a href="https://javascript.info/regexp-groups" rel="nofollow noreferrer">capture group</a> which gets preserved when being used with the <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split#description" rel="nofollow noreferrer"><code>split</code></a> method</strong></em>. Thus one just needs to go for one group pattern (a single uppercase letter followed by at least one lower case letter) and does get the rest (a valid all uppercase letter group) for free.
And since the split array in addition contains empty string values one needs to run an extra <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter" rel="nofollow noreferrer"><code>filter</code></a> task.</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>console.log(
  'just split ...\n',
  '"FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar" =&gt;',

  'FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar'
    .split(/([A-Z][a-z]+)/g)
);
console.log(
  'split and filter ...\n',
  '"FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar" =&gt;',

  'FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar'
    .split(/([A-Z][a-z]+)/g)
    .filter(val =&gt; val !== '')
);
console.log(
  'split, filter and join ...\n',
  '"FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar" =&gt;\n',

  'FooBARBazBizBuzBOOOOZBozzzBarFOOBARBazbizBUZBoooozBOZZZBar'
    .split(/([A-Z][a-z]+)/g)
    .filter(val =&gt; val !== '')
    .join(' ')
);</code></pre>
<pre class="snippet-code-css lang-css prettyprint-override"><code>.as-console-wrapper { min-height: 100%!important; top: 0; }</code></pre>
</div>
</div>
</p>


blocks|key|774174|text|您可以通过在replacer方法中使用这个String.replace()函数来实现这一点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|774175|现场演示|774176|​|774177|const+str+=+'FooBARBaz';

function+replacer()+{
++return+'+'+%2B+arguments[0]+%2B+'+';
}

console.log(str.replace(/[A-Z][a-z]%2B/g,+replacer).trim());|code-block|syntax|javascript|774178|774179|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace^0|6|8|L|G|L|G|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@$9|12|A|13|1|14]]|E|$]]|$1|F|3|G|5|6|7|15|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|16|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|17|8|@]|D|@]|E|$M|N]]|$1|O|3|I|5|6|7|18|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|Q|$R|$5|S|T|U|E|$V|W]]]]

<p>You can achieve this by using this <code>replacer</code> function inside the <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace" rel="nofollow noreferrer"><code>String.replace()</code></a> method.</p>
<p>Live Demo <strong>:</strong></p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const str = 'FooBARBaz';

function replacer() {
  return ' ' + arguments[0] + ' ';
}

console.log(str.replace(/[A-Z][a-z]+/g, replacer).trim());</code></pre>
</div>
</div>
</p>


<p>I want to split a string on the first capital letter in a group.</p>
<p>For example, <code>FooBARBaz</code> should become <code>Foo BAR Baz</code>.</p>
<p>I've come up with:</p>
<pre class="lang-js prettyprint-override"><code>str.replace(/[A-Z][a-z]+/g, ' $&amp;')
    .replace(/[A-Z]+/g, ' $&amp;')
    .replace(/\s+/g, ' ')
    .trim();
</code></pre>
<p>Can anyone suggest a cleaner solution?</p>


Convert pair of regex replacements with single replacement

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想在一个组的第一个大写字母上分割一个字符串。例如，FooBARBaz应该变成Foo BAR Baz。我想出了：str.replace(/[A-Z][a-z]+/g, ' $&')    .replace(/[A-Z]+/g, ' $&')    .replace(/\s+/g, ' ')    .trim();有人能...

问用单次替换转换成对重定位替换
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问用单次替换转换成对重定位替换EN