Python smtplib.SMTPRecipientsRefused
Python smtplib.SMTPRecipientsRefused
提问于 2022-11-22 16:47:38
我一直在尝试制作一个发送电子邮件的python程序，但是我一直收到这个错误。
Traceback (most recent call last):
File "C:\Users\25194\PycharmProjects\Gmail\Yo.py", line 25, in <module>
smtp.sendmail(email_sender, email_password, em.as_string())
File "C:\Users\25194\AppData\Local\Programs\Python\Python310\lib\smtplib.py", line 901, in sendmail
raise SMTPRecipientsRefused(senderrs)
smtplib.SMTPRecipientsRefused: {'google login': (553, b'5.1.3 The recipient address <Gmail app password> is not a valid RFC-5321\n5.1.3 address. Learn more at\n5.1.3 https://support.google.com/mail/answer/6596 k9-20020a7bc409000000b003c6bd91caa5sm17184983wmi.17 - gsmtp')}代码是
from email.message import EmailMessage
import ssl
import smtplib
email_sender = 'oropyt32@gmail.com'
email_password = 'google login'
email_reciver = 'milkiwasihunpro@gmail.com'
subject = 'Check mate'
body = """
I am making this sending this isnt it cool oro
"""
em = EmailMessage()
em['From'] = email_sender
em['TO'] = email_reciver
em['Subject'] = subject
em.set_content(body)
context = ssl.create_default_context()
with smtplib.SMTP_SSL('smtp.gmail.com', 465, context=context) as smtp:
smtp.login(email_sender, email_password)
smtp.sendmail(email_sender, email_password, em.as_string())我很难想出解决办法
回答 1
Stack Overflow用户
回答已采纳
发布于 2022-11-22 17:51:38
..。b'5.1.3收件人地址不是有效的RFC-5321\n 5.1.3地址。..。
很明显，您使用的密码在需要电子邮件的地方。
smtp.sendmail(email_sender，email_password，em.as_string())
来自寄信的文档
SMTP.sendmail(from_addr，to_addrs，msg，mail_options=()，rcpt_options=())
因此，您给出了email_password，to_addrs是预期的。难怪它会抱怨你的密码被用作收件人。您可能打算使用email_reciver代替。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/74536260
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