如何将2d列表打印为偶数表？
如何将2d列表打印为偶数表？
提问于 2022-11-26 12:50:26
#Create a program that allows 2 players to throw a 6 sided dice and record the roll value 10 times.
#The winner is the player with the highest total
#This task must store the results in a 2D array
#Extra:
#Work out the average roll across the 10 throws per player and display the result
#Frequency analysis broken down per player and per game
from random import randint
results = [[],[]]
for i in range (2):
player = []
total = 0
average = 0
#player enters their name
name = input(f"\nEnter your name player {i + 1}: ")
player.append(name)
print(f"Player {i + 1} it is your turn")
for x in range(10):
print("\nTo roll the die press any key")
input()
roll = randint(1,6)
player.append(roll)
print("You rolled a", roll)
total += roll
average = total/10
player.append(total)
player.append(average)
results.append(player)
print("""\nNAME R1 R2 R3 R4 R5 R6 R7 R8 R9 R10 TOTAL AVG""")
for i in results:
for c in i:
print(c,end = " ")
print()我不知道如何将这些值均匀地划出，以便它们在打印时是一致的。
打印时，我尝试在值之间添加空格，但如果其中一个名称或数字的长度不同，则整个行将与该列不对齐。
回答 2
Stack Overflow用户
发布于 2022-11-26 13:18:39
您可以使用以下新税：
print('%5s' % str(c))基本上：
-
%字符通知python它将不得不替换一个令牌 - ，
s字符通知python令牌将是字符串 - ，
5(或任意数字)通知python填充最多5个字符的字符串。H 210f 211
Stack Overflow用户
发布于 2022-11-26 12:56:09
计算两个名称之间的差额
diff = abs(len(results[2][0]) - len(results[3][0])) #abs = absolute value比较两个名字的长度：
if len(results[2][0] ) > len(results[3][0]):
results[3][0] = results[3][0] + " "*diff # add spaces much as difference between 2 names
else:
results[2][0] = results[2][0] + " "*diff页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/74582309
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