blocks|key|950264|text|当您调用person.get()时，您是而不是，调用v1/people/get端点时，您只是从字典中获得一个值。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|BOLD|entityRanges|data|950265|以前对service.people().connections()....execute()的调用已经从API中获取了所有信息，并将其放入字典列表中。|950266|然后，当您在connections上迭代时，您会得到一个名为person的字典，它包含两个键names和phoneNumbers。您的代码试图获得一个名为names,phoneNumbers的密钥，该密钥不存在。|950267|不确定您是如何使用data的，也不确定您期望它是什么类型，但是让data同时包含名称和电话就可以了：|950268|data+=+person|code-block|syntax|javascript|950269|或者直接在剩下的代码中使用person。|950270|entityMap^0|4|C|Q|D|K|3|1B|2|0|3|17|0|6|B|U|6|1A|5|1G|C|25|I|0|9|4|W|4|0|0|D|6|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|D]|$9|12|A|13|B|D]]|E|@]|F|$]]|$1|G|3|H|5|6|7|14|8|@$9|15|A|16|B|C]]|E|@]|F|$]]|$1|I|3|J|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]]|E|@]|F|$]]|$1|K|3|L|5|6|7|1I|8|@$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]]|E|@]|F|$]]|$1|M|3|N|5|O|7|1N|8|@]|E|@]|F|$P|Q]]|$1|R|3|S|5|6|7|1O|8|@$9|1P|A|1Q|B|C]]|E|@]|F|$]]|$1|T|3|-4|5|6|7|1R|8|@]|E|@]|F|$]]]|U|$]]

When you call <code>person.get()</code> you are not calling the <code>v1/people/get</code> endpoint, you're just getting a value from a dictionary.
The previous call to <code>service.people().connections()....execute()</code> already gets all the information from the API and puts it in a list of dictionaries.
Then when you iterate over <code>connections</code> you get a dictionary named <code>person</code> which holds two keys <code>names</code> and <code>phoneNumbers</code>.
Your code is trying to get a key with the name of <code>names,phoneNumbers</code> which doesn't exist.
Not sure how you're using <code>data</code> or what type are you expecting it to be, but to have <code>data</code> contain both name and phones simply do:
<pre><code>data = person
</code></pre>
or just use <code>person</code> directly in the rest of your code.

blocks|key|950296|text|正如@marmor所说，错误在于如何访问响应的内容。方法dict.get()确实同时拒绝两个键。以下是您可以使用的两种不同方法。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|950297|#+Calling+them+separately
personName+=+person.get('names',+[])
personPhone+=+person.get('phoneNumbers',[])
#+Calling+them+together+using+list+compression
keys+=+["names","phoneNumbers"]
data+=+[person.get(key)+for+key+in+keys]|code-block|syntax|javascript|950298|您应该参考people().connections().list()来更好地理解响应格式。在本例中，它是一个类型为人物的资源。|950299|另一种可能的近似方法是，获取姓名及其电话号码的列表，并将其存储在字典中：|950300|代码样本|950301|def+getNameAndPhones():
++service+=+people_service()
++results+=+service.people().connections().list(
++++resourceName=+"people/me",++++++++++++++++++++++++++++++++
++++personFields='names,phoneNumbers').execute()++++++++++++++
++person_dict+=+{}+++++++++++
++for+per+in++results['connections']:+++++++++++++++++++++++++
++++try:
++++++name+=++per['names'][0]['displayName']+
++++++#+As+the+response+is+an+array
++++++#+we+need+to+do+some+list+comprehension
++++++phoneNumbers+=+[x['value']+for+x+in+per['phoneNumbers']]+++++++++
++++++person_dict[name]+=+phoneNumber
++++except+:+
++++++name+=++per['names'][0]['displayName']+++++++++
++++++person_dict[name]+=+"No+phone+Number"

++print(person_dict)
++return+person_dict|950302|响应|950303|{
+++"Eco":["00112233"],
+++"Maxim+maxim":"No+phone+Number",
+++"dummy+super":[
++++++"123123123",
++++++"12312309812390"
+++]
}|950304|文档|950305|Python库v1|unordered-list-item|950306|人民API|950307|entityMap|0|LINK|mutability|MUTABLE|url|https://googleapis.github.io/google-api-python-client/docs/dyn/people_v1.people.connections.html#list|1|https://developers.google.com/people/api/rest/v1/people#Person|2|https://googleapis.github.io/google-api-python-client/docs/dyn/people_v1.html|3|https://developers.google.com/people/api/rest^0|S|A|0|0|5|T|0|1L|2|1|0|0|0|0|0|0|0|0|9|2|0|0|5|3|0^^$0|@$1|2|3|4|5|6|7|1H|8|@$9|1I|A|1J|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1K|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1L|8|@]|D|@$9|1M|A|1N|1|1O]|$9|1P|A|1Q|1|1R]]|E|$]]|$1|M|3|N|5|6|7|1S|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|1T|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1U|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1V|8|@]|D|@]|E|$]]|$1|U|3|V|5|H|7|1W|8|@]|D|@]|E|$I|J]]|$1|W|3|X|5|6|7|1X|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|10|7|1Y|8|@]|D|@$9|1Z|A|20|1|21]]|E|$]]|$1|11|3|12|5|10|7|22|8|@]|D|@$9|23|A|24|1|25]]|E|$]]|$1|13|3|-4|5|6|7|26|8|@]|D|@]|E|$]]]|14|$15|$5|16|17|18|E|$19|1A]]|1B|$5|16|17|18|E|$19|1C]]|1D|$5|16|17|18|E|$19|1E]]|1F|$5|16|17|18|E|$19|1G]]]]

As @marmor has said, the error lies in how you are accessing the content of the response. The method <code>dict.get()</code> does refuse two keys at the same time.
Here are two different approaches that you can use.
<pre class="lang-py prettyprint-override"><code># Calling them separately
personName = person.get('names', [])
personPhone = person.get('phoneNumbers',[])
# Calling them together using list compression
keys = [&quot;names&quot;,&quot;phoneNumbers&quot;]
data = [person.get(key) for key in keys]
</code></pre>
You should refer to <a href="https://googleapis.github.io/google-api-python-client/docs/dyn/people_v1.people.connections.html#list" rel="nofollow noreferrer">people().connections().list()</a> to better understand the response format. In this case, it is a resource of type <a href="https://developers.google.com/people/api/rest/v1/people#Person" rel="nofollow noreferrer">Person</a>
As another possible approximation is, getting a list of names and their phone numbers and store them in a dictionary:
<h6>Code sample</h6>
<pre class="lang-py prettyprint-override"><code>def getNameAndPhones():
 service = people_service()
 results = service.people().connections().list(
 resourceName= &quot;people/me&quot;, 
 personFields='names,phoneNumbers').execute() 
 person_dict = {} 
 for per in results['connections']: 
 try:
 name = per['names'][0]['displayName'] 
 # As the response is an array
 # we need to do some list comprehension
 phoneNumbers = [x['value'] for x in per['phoneNumbers']] 
 person_dict[name] = phoneNumber
 except : 
 name = per['names'][0]['displayName'] 
 person_dict[name] = &quot;No phone Number&quot;

 print(person_dict)
 return person_dict
</code></pre>
<h6>Response</h6>
<pre class="lang-json prettyprint-override"><code>{
 &quot;Eco&quot;:[&quot;00112233&quot;],
 &quot;Maxim maxim&quot;:&quot;No phone Number&quot;,
 &quot;dummy super&quot;:[
 &quot;123123123&quot;,
 &quot;12312309812390&quot;
 ]
}
</code></pre>
<h6>Documentation</h6>
<ul>
<li><a href="https://googleapis.github.io/google-api-python-client/docs/dyn/people_v1.html" rel="nofollow noreferrer">Python API Library v1</a></li>
<li><a href="https://developers.google.com/people/api/rest" rel="nofollow noreferrer">People API</a></li>
</ul>

I'm using the Google People API in Python to query my Google Contacts list. I can get this feature to work, but one specific operation does not work.
<pre><code>results = service.people().connections().list(
 resourceName='people/me',
 pageSize=1,
 personFields='names,phoneNumbers').execute()
connections = results.get('connections', [])

for person in connections:
 data = person.get('names', [])
</code></pre>
This works -- it gives me a list of names. However, I want a list of names and phone numbers. If I do this:
<pre><code>for person in connections:
 data = person.get('phoneNumbers', [])
</code></pre>
This also works. I get a list of phone numbers. However, if I try to get both, I get no results:
<pre><code>for person in connections:
 data = person.get('names,phoneNumbers', [])
</code></pre>
According to my interpretation of the People API docs (<a href="https://developers.google.com/people/api/rest/v1/people/get" rel="nofollow noreferrer">https://developers.google.com/people/api/rest/v1/people/get</a>), this should work. Instead, I just get nothing.
What am I doing wrong?

Obtaining both the name and phone number from a Google People API search

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在使用Python中的Google来查询我的Google联系人列表。我可以让这个特性工作，但是一个特定的操作不起作用。results = service.people().connections().list(    resourceName='people/me',    pageSize=1,    perso...

问从Google搜索中获得姓名和电话号码
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