我有一个复杂的结构化XML文件,我试图使用xmlstartlet解析一些值。我认为问题在于,逻辑对象是由元素属性而不是实际元素名称标识的。
本例中简化的文件test.xml如下所示:
<?xml version="1.0" encoding="utf-8"?>
<configDump>
<cluster top-level-assembly="XYZ12312312312">
</cluster>
<views>
<view status="ok" name="ABC">
<viewInitiators>
<viewInitiator id="ABCi1"></viewInitiator>
<viewInitiator id="ABCi2"></viewInitiator>
</viewInitiators>
<viewPorts>
<viewPort id="ABCp1"></viewPort>
<viewPort id="ABCp2"></viewPort>
</viewPorts>
<viewVolumes>
<viewVolume lun="1" id="ABCv1"></viewVolume>
<viewVolume lun="2" id="ABCv2"></viewVolume>
</viewVolumes>
</view>
<view status="ok" name="DEF">
<viewInitiators>
<viewInitiator id="DEFi1"></viewInitiator>
<viewInitiator id="DEFi2"></viewInitiator>
</viewInitiators>
<viewPorts>
<viewPort id="DEFp1"></viewPort>
<viewPort id="DEFp2"></viewPort>
</viewPorts>
<viewVolumes>
<viewVolume lun="1" id="DEFv1"></viewVolume>
<viewVolume lun="2" id="DEFv2"></viewVolume>
</viewVolumes>
</view>
</views>
</configDump>
我试图用如下所示的字段生成输出:
<top-level-assembly>-<view-name>,<viewInitiator-ID>
当我运行以下命令时:
xmlstarlet sel -t \
-m //cluster \
--var sn=@top-level-assembly \
-m //views/view \
--var view=@name \
-m //views/view/viewInitiators/viewInitiator \
-v 'concat($sn,"-",$view,",",@id)' -n test.xml
我得到以下输出:
XYZ12312312312-ABC,ABCi1
XYZ12312312312-ABC,ABCi2
XYZ12312312312-ABC,DEFi1
XYZ12312312312-ABC,DEFi2
XYZ12312312312-DEF,ABCi1
XYZ12312312312-DEF,ABCi2
XYZ12312312312-DEF,DEFi1
XYZ12312312312-DEF,DEFi2
正如您所看到的,我将在每个“视图”下获取所有“启动器”值,而不仅仅是XML结构中的那些值。我正期待着,希望能得到:
XYZ12312312312-ABC,ABCi1
XYZ12312312312-ABC,ABCi2
XYZ12312312312-DEF,DEFi1
XYZ12312312312-DEF,DEFi2
对我做错了什么有什么想法吗?
发布于 2021-11-17 10:33:39
对我做错了什么有什么想法吗?
-m
选项嵌套到xsl:for-each
语句,因此您需要每个view
的所有viewInitiator/@id
。要查看生成的XSLT代码,在-C
之前添加一个-t
选项。
所需的输出可以通过以下方式生成:
xmlstarlet sel -t \
--var sn='configDump/cluster/@top-level-assembly' \
-m '//viewInitiator' \
-v 'concat($sn,"-",../../@name,",",@id)' -n \
< file.xml
https://stackoverflow.com/questions/69999152
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