blocks|key|424038|text|最初共享的代码是不可运行的。从这个问题出发，我认为您想要重新格式化一个时间范围数组，以找到所有范围的开始和结束。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|424039|只要所有的时间都被表示为24小时的时钟格式，这就是如何实现它的一个例子。|424040|<?php

/**
+*+Convert+multiple+ranges+into+a+single+range.
+*
+*+@param+array+$ranges
+*+@return+array
+*/
function+overallRanges(array+$ranges):+array+{
++if+(sizeof($ranges)+===+0)+{
++++throw+new+\Exception('The+provided+ranges+array+is+empty');
++}
++$range+=+array_reduce($ranges,+function+($carry,+$current)+{
++++$from+=+DateTime::createFromFormat('H:i',+$current['from']);
++++$to+=+DateTime::createFromFormat('H:i',+$current['to']);
++++$carry['from']+=+($from+<+$carry['from'])+?+$from+:+$carry['from'];
++++$carry['to']+=+($to+>+$carry['to'])+?+$to+:+$carry['to'];
++++return+$carry;
++},
++++[
++++++'from'+=>+DateTime::createFromFormat('H:i',+$ranges[0]['from']),
++++++'to'+=>+DateTime::createFromFormat('H:i',+$ranges[0]['to']),
++++]
++);
++return+[
++++'from'+=>+$range['from']->format('G:i'),
++++'to'+=>+$range['to']->format('G:i'),
++];
}

//+example+use
$ranges+=+[
++['from'+=>+'9:00',+'to'+=>+'9:45'],
++['from'+=>+'9:55',+'to'+=>+'10:20'],
++['from'+=>+'10:30',+'to'+=>+'11:00'],
];

var_dump(overallRanges($ranges));|code-block|syntax|javascript|424041|产出：|424042|array(2)+{
++["from"]=>
++string(5)+"9:00"
++["to"]=>
++string(5)+"11:00"
}|424043|应该是一个很好的开始，你可以重新格式化为任何东西。|424044|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

The originally shared code was not runnable. From the question, I think you want to reformat a time range array to find the beginning and the end of all the ranges.
As long as all the time are represented as 24-hour clock format, this is an example of how it can be done.
<pre class="lang-php prettyprint-override"><code>&lt;?php

/**
 * Convert multiple ranges into a single range.
 *
 * @param array $ranges
 * @return array
 */
function overallRanges(array $ranges): array {
 if (sizeof($ranges) === 0) {
 throw new \Exception('The provided ranges array is empty');
 }
 $range = array_reduce($ranges, function ($carry, $current) {
 $from = DateTime::createFromFormat('H:i', $current['from']);
 $to = DateTime::createFromFormat('H:i', $current['to']);
 $carry['from'] = ($from &lt; $carry['from']) ? $from : $carry['from'];
 $carry['to'] = ($to &gt; $carry['to']) ? $to : $carry['to'];
 return $carry;
 },
 [
 'from' =&gt; DateTime::createFromFormat('H:i', $ranges[0]['from']),
 'to' =&gt; DateTime::createFromFormat('H:i', $ranges[0]['to']),
 ]
 );
 return [
 'from' =&gt; $range['from']-&gt;format('G:i'),
 'to' =&gt; $range['to']-&gt;format('G:i'),
 ];
}

// example use
$ranges = [
 ['from' =&gt; '9:00', 'to' =&gt; '9:45'],
 ['from' =&gt; '9:55', 'to' =&gt; '10:20'],
 ['from' =&gt; '10:30', 'to' =&gt; '11:00'],
];

var_dump(overallRanges($ranges));
</code></pre>
The output:
<pre><code>array(2) {
 [&quot;from&quot;]=&gt;
 string(5) &quot;9:00&quot;
 [&quot;to&quot;]=&gt;
 string(5) &quot;11:00&quot;
}
</code></pre>
Should be a good enough start for you to reformat into anything.

blocks|key|972362|text|如果我正确理解输入数据，则不需要迭代和重新格式化多维数组中的每个元素。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|972363|只需从第一行访问from，从最后一行访问to，就完成了。如果有必要，只格式化这两个值。|offset|length|style|CODE|972364|代码：(演示)|972365|$ranges+=+[
++++['from'+=>+'9:00',+'to'+=>+'9:45'],
++++['from'+=>+'9:55',+'to'+=>+'10:20'],
++++['from'+=>+'10:30',+'to'+=>+'11:00'],
];

if+(!isset($ranges[0]['from'],+$ranges[0]['to']))+{
++++throw+new+Exception('insufficient+business+hours+data');
}
printf(
++++'Open+hours+today:+%25s+-+%25s',
++++$ranges[0]['from'],
++++$ranges[array_key_last($ranges)]['to']
);|code-block|syntax|javascript|972366|输出：|972367|Open+hours+today:+9:00+-+11:00|972368|entityMap|0|LINK|mutability|MUTABLE|url|https://3v4l.org/7BS1d^0|0|8|4|K|2|0|4|2|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@$D|12|E|13|F|G]|$D|14|E|15|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|16|8|@]|9|@$D|17|E|18|1|19]]|A|$]]|$1|J|3|K|5|L|7|1A|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|1B|8|@]|9|@]|A|$]]|$1|Q|3|R|5|L|7|1C|8|@]|9|@]|A|$M|N]]|$1|S|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

If I understand the input data correctly, you don't need to iterate and reformat every element in the multidimensional array.
Just access the <code>from</code> from the first row and the <code>to</code> from the last row and you're done. Format just those two values if necessary.
Code: (<a href="https://3v4l.org/7BS1d" rel="nofollow noreferrer">Demo</a>)
<pre><code>$ranges = [
 ['from' =&gt; '9:00', 'to' =&gt; '9:45'],
 ['from' =&gt; '9:55', 'to' =&gt; '10:20'],
 ['from' =&gt; '10:30', 'to' =&gt; '11:00'],
];

if (!isset($ranges[0]['from'], $ranges[0]['to'])) {
 throw new Exception('insufficient business hours data');
}
printf(
 'Open hours today: %s - %s',
 $ranges[0]['from'],
 $ranges[array_key_last($ranges)]['to']
);
</code></pre>
Output:
<pre><code>Open hours today: 9:00 - 11:00
</code></pre>

So I have some code that returns all the time in an array like this Open hours today: 9:00- 9:45, 9:55 - 10:20, 10:30 - 11:00 . If we used $formatted_ranges[array_key_first($formatted_ranges)] instead of join, it would return a single element as like this, &quot;Open hours today: 9:00 - 9:45&quot;. However we need to return like this,
Open hours today: 9:00 - 11:00.
<pre><code>$start = DateTime::createFromFormat( 'H:i', $range['from'] );
$end = DateTime::createFromFormat( 'H:i', $range['to'] );

$formatted_ranges = array_map( function( $range ) {
 return $this-&gt;format_time( $range['from'] ).' - '.$this-&gt;format_time($range['to'] );
}, $ranges );

return sprintf(
 __( 'Open hours today:', 'example' ) . ' &lt;span&gt;%s&lt;/span&gt;',
 join( ', ', $formatted_ranges )
 );

</code></pre>

PHP returning an element from an array

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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所以我有一些代码可以在一个数组中一直返回，比如今天的开放时间:9:00-9:45，9:55 - 10:20，10:30-11:00。如果我们使用$formatted_rangesarray_key_first($formatted_ranges)而不是join，它将返回一个元素，如下所示：“今天的开放时间:9:00-9...

问从数组返回元素的PHP
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