python:逐行打印多个字典和字符串
python:逐行打印多个字典和字符串
提问于 2021-05-26 13:37:36
我有一个包含各种列的数据，我计算了每个列的value_counts，并将它们转换为to_dict。现在，我想逐行打印它们，并添加一些字符串，描述每个字典如下：
print( 'Names and counts',
'\n',
df['names'].value_counts()[:3].to_dict(),
'\n',
'Last names and counts',
'\n',
df['last names'].value_counts()[:3].to_dict(),
'Staff names and counts',
'\n',
df['staff_names'].value_counts()[:3].to_dict(),
'\n',
'Staff last names and counts',
'\n',
df['staff last names'].value_counts()[:3].to_dict())
Current output:
Names and counts
{"Jack": 20, "John": 10, "Samuel": 9}
Last names and counts
{"Brown": 25, "Smith": 30, "Jackson": 5}
Staff names and counts
{"Mars": 22, "Joshua": 20, "Simon": 8}
Staff last names and counts
{"Bernard": 27, "Kohlen": 16, "Dimun": 7}因此，我希望输出结果如下：
Desired output:
Names and counts
{"Jack": 20,
"John": 10,
"Samuel": 9}
Last names and counts
{"Brown": 25,
"Smith": 30,
"Jackson": 5}
Staff names and counts
{"Mars": 22,
"Joshua": 20,
"Simon": 8}
Staff last names and counts
{"Bernard": 27,
"Kohlen": 16,
"Dimun": 7}我尝试了pprint()或print()，但是这会引发一个错误。
我还尝试添加print(*每个字典，sep= '\n')，但它只返回索引并删除数字(计数)
回答 2
Stack Overflow用户
回答已采纳
发布于 2021-05-26 13:47:41
尝尝这个,
import json
print( 'Names and counts',
'\n',
json.dumps(df['names'].value_counts()[:3].to_dict(),indent=2),
'\n',
'Last names and counts',
'\n',
json.dumps(df['last names'].value_counts()[:3].to_dict(),indent=2),
'Staff names and counts',
'\n',
json.dumps(df['staff_names'].value_counts()[:3].to_dict(),indent=2),
'\n',
'Staff last names and counts',
'\n',
json.dumps(df['staff last names'].value_counts()[:3].to_dict(),indent=2)将缩进参数更改为更高的编号以获得更好的格式。
备注:由Creator测试并运行良好。
Stack Overflow用户
发布于 2021-05-26 13:52:44
将json.dumps与indent =Levelof字典一起使用：
for c in df.columns:
print(f"{c} and counts\n{json.dumps(df[c].value_counts()[:3].to_dict(),indent=2)}")页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/67706118
复制相关文章
相似问题
腾讯云开发者
