如何使用JQ将JSON对象生成数组？
如何使用JQ将JSON对象生成数组？
提问于 2021-05-17 22:41:16
在这个JSON文件上执行了以下操作
输入
jq 'with_entries(select([.key] | inside(["adaway", "adguard", "disconnect", "yoyo"])))' adblock.sources输出
{
"adaway": {
"url": "https://raw.githubusercontent.com/AdAway/adaway.github.io/master/hosts.txt",
"rule": "/^127\\.0\\.0\\.1[[:space:]]+([[:alnum:]_-]{1,63}\\.)+[[:alpha:]]+([[:space:]]|$)/{print tolower($2)}",
"size": "S",
"focus": "mobile",
"descurl": "https://github.com/AdAway/adaway.github.io"
},
"adguard": {
"url": "https://adguardteam.github.io/AdGuardSDNSFilter/Filters/filter.txt",
"rule": "BEGIN{FS=\"[/|^|\\r]\"}/^\\|\\|([[:alnum:]_-]{1,63}\\.)+[[:alpha:]]+[\\/\\^\\r]+$/{print tolower($3)}",
"size": "L",
"focus": "general",
"descurl": "https://adguard.com"
},
"disconnect": {
"url": "https://s3.amazonaws.com/lists.disconnect.me/simple_malvertising.txt",
"rule": "/^([[:alnum:]_-]{1,63}\\.)+[[:alpha:]]+([[:space:]]|$)/{print tolower($1)}",
"size": "S",
"focus": "general",
"descurl": "https://disconnect.me"
},
"yoyo": {
"url": "https://pgl.yoyo.org/adservers/serverlist.php?hostformat=nohtml&showintro=0&mimetype=plaintext",
"rule": "/^([[:alnum:]_-]{1,63}\\.)+[[:alpha:]]+([[:space:]]|$)/{print tolower($1)}",
"size": "S",
"focus": "general",
"descurl": "https://pgl.yoyo.org"
}
}我希望它是一个数组，并尝试了一些建议，比如将其导入jq -s '.'。这些尝试只产生一个单一元素数组。什么是最好的方式来格式化这个？我高度怀疑from_entries和to_entries必须以某种方式合并。
预期输出
[
{
"key": "adaway",
"url": "https://raw.githubusercontent.com/AdAway/adaway.github.io/master/hosts.txt",
"rule": "/^127\\.0\\.0\\.1[[:space:]]+([[:alnum:]_-]{1,63}\\.)+[[:alpha:]]+([[:space:]]|$)/{print tolower($2)}",
"size": "S",
"focus": "mobile",
"descurl": "https://github.com/AdAway/adaway.github.io"
},
{
"key": "adguard",
"url": "https://adguardteam.github.io/AdGuardSDNSFilter/Filters/filter.txt",
"rule": "BEGIN{FS=\"[/|^|\\r]\"}/^\\|\\|([[:alnum:]_-]{1,63}\\.)+[[:alpha:]]+[\\/\\^\\r]+$/{print tolower($3)}",
"size": "L",
"focus": "general",
"descurl": "https://adguard.com"
},
{
"key": "disconnect",
"url": "https://s3.amazonaws.com/lists.disconnect.me/simple_malvertising.txt",
"rule": "/^([[:alnum:]_-]{1,63}\\.)+[[:alpha:]]+([[:space:]]|$)/{print tolower($1)}",
"size": "S",
"focus": "general",
"descurl": "https://disconnect.me"
},
{
"key": "yoyo",
"url": "https://pgl.yoyo.org/adservers/serverlist.php?hostformat=nohtml&showintro=0&mimetype=plaintext",
"rule": "/^([[:alnum:]_-]{1,63}\\.)+[[:alpha:]]+([[:space:]]|$)/{print tolower($1)}",
"size": "S",
"focus": "general",
"descurl": "https://pgl.yoyo.org"
}
]回答 1
Stack Overflow用户
回答已采纳
发布于 2021-05-17 23:08:37
正如注释中所暗示的那样，有几种方法可以按照最初的要求解释问题，但可以通过在jq筛选器中添加以下内容之一来实现三种主要解释：
| [keys_unsorted[] as $key | {$key} + .[$key] ]或
| map(.)或者：
| [keys_unsorted[] as $key | { $key): .[$key] } ]更新:第一个是与显示的预期输出相对应的输出。{$key}是{"key": $key}的缩写。
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原文链接：
https://stackoverflow.com/questions/67577852
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