blocks|key|2607977|text|我看到很多错误。首先，初始化最多2次。let+max+=+a;，然后您可以使用max。但else+if也错了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2607978|如果是c+<+b+<+a呢？则只有第一个如果应用，尽管c大于|2607979|entityMap^0|J|C|13|3|18|7|0|3|9|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|I|$]]

<p>I see many errors.
First, you initialize max 2 times. <code>let max = a;</code> and then you can use <code>max</code>.
But the <code>else if</code> is also wrong.</p>
<p>What if <code>c &lt; b &lt; a</code>? Then only the first if applies although c is greater than a</p>


blocks|key|1617086|text|您需要省略其他部分，因为如果b不大于a，则仍然需要与c进行比较。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1617087|另外两点是：|1617088|不需要声明一个分块的max，因为外部没有从条件中获得值。|ordered-list-item|1617089|您从不使用getMax调用的结果。|1617090|​|1617091|const+getMax+=+(a,+b,+c)+=>+{
++++let+max+=+a;

++++if+(b+>+max)+max+=+b;
++++if+(c+>+max)+max+=+c;

++++return+max;
}



console.log(`max+value:+${getMax(2,+72,+189)}`);|code-block|syntax|javascript|1617092|1617093|entityMap^0|E|1|I|1|Q|1|0|0|A|3|0|5|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|K|3|L|5|J|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|1A|8|@]|D|@]|E|$]]|$1|O|3|P|5|Q|7|1B|8|@]|D|@]|E|$R|S]]|$1|T|3|N|5|6|7|1C|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|V|$]]

<p>You need ot omit the else part, because if <code>b</code> is not greater than <code>a</code>, you need still a comparison with <code>c</code>.</p>
<p>The other two points are:</p>
<ol>
<li><p>No need to declare a blockwise <code>max</code>, because the outer does not get the value from the condition.</p>
</li>
<li><p>You never use the result of the call of <code>getMax</code>.</p>
</li>
</ol>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const getMax = (a, b, c) =&gt; {
    let max = a;

    if (b &gt; max) max = b;
    if (c &gt; max) max = c;

    return max;
}



console.log(`max value: ${getMax(2, 72, 189)}`);</code></pre>
</div>
</div>
</p>


blocks|key|1617127|text|使用let关键字声明的变量具有块作用域，也就是说，它们只能在定义在其中的块中访问。首先将max设置为a，然后在if语句中创建另一个具有相同名称的局部变量，并将其赋值为b。您应该做的是删除if/+the语句中的let声明。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1617128|其次，当满足第一个条件时，您的if块将退出。您应该使用另一个if语句(它将运行，而不管第一个语句中的条件是否满足)，而不是一个one语句(只有当第一个条件没有满足时才会运行)。|1617129|第三，在console.log中传递对函数的对象引用(所有函数都是javascript中的对象)，这相当于函数文本。您需要传递函数调用。|1617130|除了不使用未定义的变量之外，这就是您需要做的全部工作。|1617131|​|1617132|const+number1+=+54;
const+number2+=+72;
const+number3+=+189;

const+getMax+=+(a,+b,+c)+=>+{
++let+max+=+a;
++
++if(b+>+max)+{
++++max+=+b;
++}
++
++if+(c+>+max){
++++max+=+c;
++};
++
++return+max;
}

console.log(`Nilai+maksimum+adalah+${getMax(number1,+number2,+number3)}`);|code-block|syntax|javascript|1617133|1617134|entityMap^0|2|3|18|3|1E|1|2B|1|2W|3|0|0|4|B|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]|$9|14|A|15|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|16|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|1A|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|1B|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|1C|8|@]|D|@]|E|$Q|R]]|$1|S|3|M|5|6|7|1D|8|@]|D|@]|E|$]]|$1|T|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]]|U|$]]

<p>Variables declared with the <code>let</code> keyword have a block scope, that is, they are only accessible within the block they were defined in. You are first setting <code>max</code> to <code>a</code>, then inside your if statement, you are creating another local variable with the same name and assigning it the value <code>b</code>. What you should do is remove the <code>let</code> declarations inside your if/else statement.</p>
<p>Second, your if block is being exited when the first condition is satisfied. You should use another if statement (which will run regardless of whether or not the condition in the first one is met) as opposed to an else statement (which will only run if the first condition is not met).</p>
<p>Third, you are passing an object reference to your function in your <code>console.log</code> (all functions are objects in javascript) which is equivalent to the function text. You need to pass the function call instead.</p>
<p>That's all you need to do, besides not using undefined variables.</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const number1 = 54;
const number2 = 72;
const number3 = 189;

const getMax = (a, b, c) =&gt; {
  let max = a;
  
  if(b &gt; max) {
    max = b;
  }
  
  if (c &gt; max){
    max = c;
  };
  
  return max;
}

console.log(`Nilai maksimum adalah ${getMax(number1, number2, number3)}`);</code></pre>
</div>
</div>
</p>


blocks|key|2608092|text|正如注释中指出的，您的代码有一些错误，所以问题不是100%25清楚，所以我向您介绍以下方法.|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2608093|function+getMax()+{
++const+nums+=+arguments;
++var+max+=+null;

++for+(let+i+=+0;+i+<+nums.length;+i%2B%2B)+{
++++const+num+=+nums[i];
++++if+(max+===+null+%7C%7C+num+>+max)+{
++++++max+=+num;
++++}
++}

++return+max;
}|code-block|syntax|javascript|2608094|此函数接受要与之比较的无穷多个参数，并且不限制输入的固定数量。例如，以下都是有效的用途：|2608095|const+validExample1+=+getMax(33,+72,+189,+4,+1);+//+Output:+189
const+validExample2+=+getMax(2,+2);+//+Output:+2
const+validExample3+=+getMax(320,+1,+8);+//+Output:+320
const+validExample4+=+getMax(-1,+-200,+-34);+//+Output:+-1|2608096|通过不使用箭头函数表达式，您可以使用arguments关键字检索所有值的可迭代对象。或者，如果要求使用箭头函数，您可以简单地使用扩展语法(.)+do.|offset|length|style|CODE|2608097|const+getMax+=+(+...nums+)+=>+{
++var+max+=+null;

++for+(let+i+=+0;+i+<+nums.length;+i%2B%2B)+{
++++const+num+=+nums[i];
++++if+(max+===+null+%7C%7C+num+>+max)+{
++++++max+=+num;
++++}
++}

++return+max;
}|2608098|一个完整的工作示例：|BOLD|2608099|​|2608100|const+number1+=+3;
const+number2+=+72;
const+number3+=+189;

function+getMax()+{

++const+nums+=+arguments;
++var+max+=+null;

++for+(let+i+=+0;+i+<+nums.length;+i%2B%2B)+{
++++const+num+=+nums[i];
++++if+(max+===+null+%7C%7C+num+>+max)+{
++++++max+=+num;
++++}
++}

++return+max;
}

const+result+=+getMax(number1,+number2,+number3);

console.log(`Nilai+maksimum+adalah+${result}`);|2608101|2608102|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Functions/Arrow_functions|1|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Functions/arguments|2|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Spread_syntax^0|0|0|0|0|I|9|5|7|0|I|9|1|1S|7|2|0|0|0|A|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1C|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1E|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1G|8|@$M|1H|N|1I|O|P]]|9|@$M|1J|N|1K|1|1L]|$M|1M|N|1N|1|1O]|$M|1P|N|1Q|1|1R]]|A|$]]|$1|Q|3|R|5|D|7|1S|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1T|8|@$M|1U|N|1V|O|U]]|9|@]|A|$]]|$1|V|3|W|5|6|7|1W|8|@]|9|@]|A|$]]|$1|X|3|Y|5|D|7|1X|8|@]|9|@]|A|$E|F]]|$1|Z|3|W|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|10|3|-4|5|6|7|1Z|8|@]|9|@]|A|$]]]|11|$12|$5|13|14|15|A|$16|17]]|18|$5|13|14|15|A|$16|19]]|1A|$5|13|14|15|A|$16|1B]]]]

<p>There are a few things wrong with your code as pointed out in the comments so the question isn't 100% clear so I present you with the below approach...</p>
<pre class="lang-js prettyprint-override"><code>function getMax() {
  const nums = arguments;
  var max = null;

  for (let i = 0; i &lt; nums.length; i++) {
    const num = nums[i];
    if (max === null || num &gt; max) {
      max = num;
    }
  }

  return max;
}
</code></pre>
<p>This function accepts an <em>infinite</em> number of arguments to compare against and does not restrict to a fix number of inputs. For example, the below are all valid uses:</p>
<pre class="lang-js prettyprint-override"><code>const validExample1 = getMax(33, 72, 189, 4, 1); // Output: 189
const validExample2 = getMax(2, 2); // Output: 2
const validExample3 = getMax(320, 1, 8); // Output: 320
const validExample4 = getMax(-1, -200, -34); // Output: -1
</code></pre>
<p>By not using the <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Functions/Arrow_functions" rel="nofollow noreferrer">arrow function expression</a> you can use the <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Functions/arguments" rel="nofollow noreferrer"><code>arguments</code></a> keyword to retrieve an iterable object of all values. Alternatively, if requirements are to use arrow functions you can simply use the <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Spread_syntax" rel="nofollow noreferrer">spread syntax (...)</a> do...</p>
<pre class="lang-js prettyprint-override"><code>const getMax = ( ...nums ) =&gt; {
  var max = null;

  for (let i = 0; i &lt; nums.length; i++) {
    const num = nums[i];
    if (max === null || num &gt; max) {
      max = num;
    }
  }

  return max;
}
</code></pre>
<p><strong>A full working example:</strong></p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const number1 = 3;
const number2 = 72;
const number3 = 189;

function getMax() {

  const nums = arguments;
  var max = null;

  for (let i = 0; i &lt; nums.length; i++) {
    const num = nums[i];
    if (max === null || num &gt; max) {
      max = num;
    }
  }

  return max;
}

const result = getMax(number1, number2, number3);

console.log(`Nilai maksimum adalah ${result}`);</code></pre>
</div>
</div>
</p>


<p>first thing first i would like to say thank you so much for dropping by. I'm a beginner at Javascript. And now dealing with some issue, and i need help to identify what is wrong with my lines. So here it is, i want to find out the highest number from the variable using conditional statement inside a function, I'm stuck right now.</p>
<p>EDITED : Thankyou guys for helping me out, now I have a clear vision about what I should learn more.</p>
<pre><code>const number1 = 103;
const number2 = 72;
const number3 = 189;

const getMax = (a, b, c) =&gt; {
  let max = a;
  
  if(b &gt; max) {
    let max = b;
  } else if (c &gt; max){
    let max = c;
  };
  
  return max;
}

getMax(number1, number2, number3);

console.log(`Max number is ${getMax}`);```
</code></pre>


Need help finding max value in java script (without max method)

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

首先，我想说非常感谢你的来访。我是Javascript的初学者。现在处理一些问题，我需要帮助找出我的台词出了什么问题。所以在这里，我想用一个函数中的条件语句从变量中找出最高的数字，我现在被卡住了。编辑:谢谢你们帮助我，现在我对我应该学到的东西有了清晰的认识。const number1 = 103;const numbe...

问需要帮助在java脚本中找到max值(没有max方法)
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问需要帮助在java脚本中找到max值(没有max方法)EN