10位数字的反向模式(模式问题)
10位数字的反向模式(模式问题)
提问于 2021-01-26 08:47:13
这是我要打印的图案。
1
3 2
6 5 4
10 9 8 7
现在我有了一个解决方案，但是我不知道到底是如何工作的。
解决办法：
length = 6
start = 1
stop = 2
currentNumber = stop
for row in range(stop, length):
for col in range(start, stop):
currentNumber -= 1
print(currentNumber, end=" ")
print(" ")
start = stop
stop += row
currentNumber = stop我认为这是如何运作的：
# for row in range(2, 6): 2, 3, 4, 5,
# for col in range(1, 2):
# currentnum = 2-1 = 1
# print( 1 )
# start = stop (start = 2)
# stop += 2 (row = 2,3,4,5) so now stop = 2 + 2 = 4
# currentNumber = 4
# for row in range(4, 6): 4,5
# for col in range(2, 4): 2, 3 means 2 time will loop run
# currentnum = 4-1 = 3,
# currentnum = 3-2 = 2
# print( 3, 2 )
# start = stop (start = 4)
# stop += 3 (stro = 4+3 = 7)
# currentnum = 7
**PROBLEM**
# for row in range(7, 6):
# for col in range(4, 7): 5,6,7 means 3 time will loop run
# currentnum = 7-1 = 6,
# currentnum = 7-2 = 5,
# currentnum = 7-3 = 4,
# print( 6, 5, 4)
# start = stop (start = 7)
# stop += 3 (stro = 7+3 = 11)
# currentnum = 11下面是问题(talking from the #commented calculations)：
for i in range(11, 6):
for j in range(4, 7):
print("h")
print("k")
print("j")这个For循环不会执行，因为(11，6)。
这就是我的计算出错的地方，我知道我不知道这个解决方案是如何工作的。任何对当前解决方案有更好的解决方案或解释的人都将不胜感激。
只是想知道代码是如何工作的，
谢谢你。
回答 1
Stack Overflow用户
回答已采纳
发布于 2021-01-26 12:23:21
我认为在你的理解中的问题是重写第一个for循环每次停止被改变。但是，不应该这样做，因为for循环只在开始时进行计算，因此在循环已经运行时，更改变量stop不应该对其产生影响，如果这是有意义的话。我在这里更正了你的“理解”部分：
#### for loop does not change
# for row in range(2, 6): 2, 3, 4, 5,
### for loop 2 ###
# for col in range(1, 2):
# currentNumber -= 1 # 2-1 = 1
# print(1)
# start = stop # (start = 2)
# stop += 2 # (row currently = 2) so now stop = 2 + 2 = 4
# currentNumber = 4
### for loop 3 ###
# for col in range(2, 4): 2, 3 means 2 time will loop run
# currentnum = 4-1 = 3,
# currentnum = 3-2 = 2
# print(3, 2)
# start = stop # (start = 4)
# stop += 3 # (row currently = 3) so now stop = 4 + 3 = 7
# currentnum = 7
### for loop 4 ###
# for col in range(4, 7): # 4, 5, 6 i.e. loop 3 times
# currentnum = 7-1 = 6,
# currentnum = 6-1 = 5
# currentnum = 5 - 1 = 4
# print(6, 5, 4)
# start = stop # (start = 7)
# stop += 4 # (row currently = 4) so now stop = 7 + 4 = 11
# currentnum = 11
### for loop 5 ###
# for col in range(7, 11): # 7, 8, 9, 10 i.e. loop 4 times
# currentnum = 11 - 1 = 10
# currentnum = 10 - 1 = 9
# currentnum = 9 - 1 = 8
# currentnum = 8 - 1 = 7
# print(10, 9, 8, 7)
# start = stop # (start = 11)
# stop += 5 # (row currently = 5) so now stop = 11 + 5 = 16
# currentnum = 16希望这是有意义的，但可以要求澄清。注意，最后几行并不重要，因为它是最后一个for循环。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/65898246
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