问用特定值替换数组中与另一个数组中的任何项不匹配的项

EN

var originalArray = [
  '1:1',   'blah',
  '1:2',   undefined,
  '1:3',   'smith',
  '1:4',   'blah',
  '1:5',   'williams',
  '1:6',   'blah',
  '1:7',   'blah'
];

var matchArray = [ 
   'taylor', 
   'smith', 
   'williams', 
   'brown'
];

for (var i = 0; i < originalArray.length; i++) {
    var value = originalArray[i];
    //Check if it matches your RegEx
    if (value !== undefined) {
      var doesItMatchRegEx = value.match(/([0-9]+):([0-9]+)/g);
    } else {
      originalArray[i] = "johnson";
    }
    //Check if it is in your second array
    var isItInSecondArray = matchArray.includes(value);
    if (!doesItMatchRegEx && !isItInSecondArray) {
        //Let's replace it with Johnson
        originalArray[i] = "johnson";
    }
}

console.log(originalArray);    

validNames = [‘taylor’...];
numberFormatRegex = /([0-9]+):([0-9]+)/g;

// This function will run on each value in the array, and the RETURN becomes the new value in the array created after mapping
mapFunction = (value) => {
  if(!validNames.includes(value) && !numberFormatRegex.test(value)){
    // only values NOT in the validNames list AND (&&) NOT passing the refer will enter this branch 
    
    return ‘Johnson’;
  }
  // This only runs if the previous return didn’t so it will only happen for valid values

}

// Call map() method with our new function and save result to new array
// note that the inputArray will be unchanged and a new one will be returned and assigned to newArray
newArray = inputArray.map(mapFunction);