我有以下内容:
public enum TicketQuestionType
{
General = 1,
Billing = 2,
TMS = 3,
HOS = 4,
DeviceManagement = 5
}
和示范班:
public class TicketCreateApi
{
public string Subject { get; set; }
public TicketQuestionType QuestionType { get; set; } = TicketQuestionType.General;
public TicketType Type { get; set; } = TicketType.Problem;
public TicketStatus Status { get; set; } = TicketStatus.New;
public TicketPriority Priority { get; set; } = TicketPriority.Normal;
public string Description { get; set; }
public List<string> Attachments { get; set; }
public int? DeviceId { get; set; }
public int? DriverId { get; set; }
}
我的API方法使用它:
Task<IActionResult> Create(TicketCreateApi model);
Swagger生成以下内容:
这是:
因此,我们只能看到默认值,而无法看到可用的枚举列表(名称和值)。我想展示给你看。该怎么做呢?
发布于 2020-12-16 06:46:36
,我们只能看到默认值,无法看到可用的枚举列表(名称和值)。我想展示给你看。该怎么做呢?
要在swagger中将枚举显示为字符串,可以配置JsonStringEnumConverter,在ConfigureServices中添加以下行:
services.AddControllers().AddJsonOptions(options =>
options.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()));
产出如下:
如果要将枚举显示为刺和int值,可以尝试创建一个EnumSchemaFilter来更改架构。守则如下:
public class EnumSchemaFilter : ISchemaFilter
{
public void Apply(OpenApiSchema model, SchemaFilterContext context)
{
if (context.Type.IsEnum)
{
model.Enum.Clear();
Enum.GetNames(context.Type)
.ToList()
.ForEach(name => model.Enum.Add(new OpenApiString($"{Convert.ToInt64(Enum.Parse(context.Type, name))} = {name}")));
}
}
}
将SwaggerGen配置为使用上面的ShemaFilter。
services.AddSwaggerGen(c =>
{
c.SwaggerDoc("v1", new OpenApiInfo
{
Version = "v1",
Title = "ToDo API",
Description = "A simple example ASP.NET Core Web API",
TermsOfService = new Uri("https://example.com/terms"),
Contact = new OpenApiContact
{
Name = "Shayne Boyer",
Email = string.Empty,
Url = new Uri("https://twitter.com/spboyer"),
},
License = new OpenApiLicense
{
Name = "Use under LICX",
Url = new Uri("https://example.com/license"),
}
});
c.SchemaFilter<EnumSchemaFilter>();
});
结果如下:
发布于 2021-09-16 07:25:01
我试过EnumSchemaFilter。每次我提交请求时都会出错。因为将枚举字符串序列化为int
我使用了这个代码块,我希望它能工作。
services.AddControllersWithViews()
.AddJsonOptions(
opts =>
{
var enumConverter = new JsonStringEnumConverter();
opts.JsonSerializerOptions.Converters.Add(enumConverter);
});
https://stackoverflow.com/questions/65312198
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