我在PowerShell中用VSCode做了以下工作:
PS D:\Project Resume> set GOOS=linux
PS D:\Project Resume> set GOARCH=amd64
PS D:\Project Resume> set CGO_ENABLED=0
PS D:\Project Resume> cd .\dist\events\
PS D:\Project Resume\dist\events> go build -o main main.go
PS D:\Project Resume\dist\events> ~\Go\Bin\build-lambda-zip.exe -o main.zip main
2020/11/14 14:05:13 wrote main.zip这似乎可以很好地压缩文件,我还在Lambda控制台中将处理程序更改为"main“。然而,我仍然得到了这个:
START RequestId: 42d5f7d6-3c9d-457d-ab2f-5030b39a5bce Version: $LATEST
fork/exec /var/task/main: exec format error: PathError
null
END RequestId: 42d5f7d6-3c9d-457d-ab2f-5030b39a5bce
REPORT RequestId: 42d5f7d6-3c9d-457d-ab2f-5030b39a5bce Duration: 0.43 ms Billed Duration: 100 ms Memory Size: 512 MB Max Memory Used: 24 MB Init Duration: 2.84 ms 如果这很重要,下面是我的代码(我学习了一个关于YouTube的教程,使用"main.go“作为文件名):
//Lambda Function Go Code
package main
import (
"errors"
"github.com/aws/aws-lambda-go/events"
"github.com/aws/aws-lambda-go/lambda"
)
func main() {
lambda.Start(HandleRequest)
}
//HandleRequest the request handler for our lambda stuff
func HandleRequest(request events.APIGatewayProxyRequest) (events.APIGatewayProxyResponse, error) {
if request.HTTPMethod == "POST" {
var stringResponse string = "Success :)"
APIResponse := events.APIGatewayProxyResponse{Body: stringResponse, StatusCode: 200}
return APIResponse, nil
}
err := errors.New("Method Not Allowed")
APIResponse := events.APIGatewayProxyResponse{Body: "Method Not OK", StatusCode: 502}
return APIResponse, err
}出于好奇,我决定也检查zip文件的权限。这可能与此有关吗?

发布于 2020-11-16 15:55:08
在我的例子中,我遵循文档,认为设置GOOS env变量的命令如下所示:
set GOOS=linux然而,根据下列文件:
https://mcpmag.com/articles/2019/03/28/environment-variables-in-powershell.aspx?m=1
因为我是在PowerShell中运行的,所以我应该使用以下命令:
$env:GOOS = "linux"正如许多文档在其他地方说的那样,当您在PowerShell中使用以下内容时(无论是来自VSCode还是在该IDE之外),您将知道已经正确地设置了env变量:
go env我希望这能帮助人们在Windows环境下进行编译。
发布于 2020-11-14 23:10:08
https://stackoverflow.com/questions/64838323
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