blocks|key|1058045|text|到String的转换是不正确的，因为数组不覆盖toString()的Object实现。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1058046|也就是说，没有理由将数组转换为String来比较它们。您可以使用Arrays.equals直接比较它们，这将返回真正的if+both+arrays+contain+the+same+number+of+elements,+and+all+corresponding+pairs+of+elements+in+the+two+arrays+are+equal。|1058047|char+sArray[]+=+s.toCharArray();
char+tArray[]+=+t.toCharArray();
Arrays.sort(sArray);
Arrays.sort(tArray);
return+Arrays.equals(sArray,tArray);|code-block|syntax|javascript|1058048|entityMap^0|1|6|N|A|Y|6|0|F|6|W|D|1N|3B|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|N|$]]

Your conversion to <code>String</code> is incorrect, since arrays don't override the <code>Object</code> implementation of <code>toString()</code>.
That said, there is no reason to convert the arrays to <code>String</code> in order to compare them. You can compare them directly using <code>Arrays.equals</code> which will return true <code>if both arrays contain the same number of elements, and all corresponding pairs of elements in the two arrays are equal</code>.
<pre><code>char sArray[] = s.toCharArray();
char tArray[] = t.toCharArray();
Arrays.sort(sArray);
Arrays.sort(tArray);
return Arrays.equals(sArray,tArray);
</code></pre>

blocks|key|492939|text|下面的代码行不将char数组转换为字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|492940|s+=+sArray.toString();
t+=+tArray.toString();|code-block|syntax|javascript|492941|这只会将地址转换为字符串，以便将数组转换为您应该使用的字符串：Arrays.toString(arrName)|offset|length|style|BOLD|492942|现在代码将如下所示：|492943|public+static+boolean+isAnagram(String+s,+String+t)+{
++++char+sArray[]+=+s.toCharArray();
++++char+tArray[]+=+t.toCharArray();
++++Arrays.sort(sArray);
++++Arrays.sort(tArray);
++++s+=+Arrays.toString(sArray);
++++t+=+Arrays.toString(tArray);
++++return+s.equals(t);++
}|492944|entityMap^0|0|0|V|O|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

The below line of code does not convert the char array to String:
<pre><code>s = sArray.toString();
t = tArray.toString();
</code></pre>
This only converts the address into String, in order to convert the Array to String you should use: Arrays.toString(arrName)
Now the code will look like this:
<pre><code>public static boolean isAnagram(String s, String t) {
 char sArray[] = s.toCharArray();
 char tArray[] = t.toCharArray();
 Arrays.sort(sArray);
 Arrays.sort(tArray);
 s = Arrays.toString(sArray);
 t = Arrays.toString(tArray);
 return s.equals(t); 
}
</code></pre>

blocks|key|1058151|text|在这里，从对象类继承的称为toString()方法的char数组上的toString()是：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1058152|public+String+toString()+{
++++return+getClass().getName()+%2B+"@"+%2B+Integer.toHexString(hashCode());
}|code-block|syntax|javascript|1058153|因此，使用String.valueOf再次将字符数组转换为字符串。|1058154|s+=+String.valueOf(sArray);
t+=+String.valueOf(tArray);|1058155|因为您只需要比较，所以可以使用Arrays.equals()直接比较字符数组。|1058156|return+Arrays.equals(sArray,tArray);|1058157|entityMap^0|D|A|Y|A|0|0|5|E|0|0|F|F|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|T|$]]

Here, <code>toString()</code> on char array called <code>toString()</code> method herited from the object class which is :
<pre><code>public String toString() {
 return getClass().getName() + &quot;@&quot; + Integer.toHexString(hashCode());
}
</code></pre>
So, use <code>String.valueOf</code> to convert a character array to String again
<pre><code>s = String.valueOf(sArray);
t = String.valueOf(tArray);
</code></pre>
Since you need to just compare, you can directly compare the character array using <code>Arrays.equals()</code>
<pre><code>return Arrays.equals(sArray,tArray);
</code></pre>

blocks|key|182700|text|中比较sArray和tArray的内存地址。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|182701|++++s+=+sArray.toString();
++++t+=+tArray.toString();|code-block|syntax|javascript|182702|我建议您循环遍历数组中的值，并将其存储在字符串中。|182703|++++for(+int+i+=+0;+i+<+sArray.length;+i%2B%2B+)
++++++++str+%2B=+sArray[i];

++++for(+int+i+=+0;+i+<+tArray.length;+i%2B%2B+)
++++++++str2+%2B=+tArray[i];|182704|然后像这样进行比较：|182705|return+str.equals(str2);|182706|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You are comparing the memory address of the sArray and tArray in
<pre><code> s = sArray.toString();
 t = tArray.toString();
</code></pre>
I suggest that you loop through the value in the array and store it in the String.
<pre><code> for( int i = 0; i &lt; sArray.length; i++ )
 str += sArray[i];

 for( int i = 0; i &lt; tArray.length; i++ )
 str2 += tArray[i];
</code></pre>
Then do comparison like this:
<pre><code>return str.equals(str2);
</code></pre>

blocks|key|497597|text|您可以使用public+String(char[]+value)在char[]之外创建一个String。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|497598|import+java.util.Arrays;

public+class+Main+{
++++public+static+void+main(String[]+args)+{
++++++++System.out.println(isAnagram("anagram",+"nagaram"));
++++}

++++public+static+boolean+isAnagram(String+s,+String+t)+{
++++++++char+sArray[]+=+s.toCharArray();
++++++++char+tArray[]+=+t.toCharArray();
++++++++Arrays.sort(sArray);
++++++++Arrays.sort(tArray);
++++++++s+=+new+String(sArray);//+Create+String+out+of+sArray
++++++++t+=+new+String(tArray);//+Create+String+out+of+tArray
++++++++return+s.equals(t);
++++}
}|code-block|syntax|javascript|497599|输出：|BOLD|497600|true|497601|或者，您可以使用String#valueOf从char[]中创建一个String。还有更多的解决方案(例如，直接使用Arrays#equals比较char数组，我建议您尽可能多地尝试以达到学习目的。|497602|你的方法出了什么问题？|497603|sArray.toString()和tArray.toString()返回不同的字符串，您可以通过打印它们或调试代码来找到它们。造成这种差异的原因是sArray和tArray的哈希代码不同。请检查What+is+a+debugger+and+how+can+it+help+me+diagnose+problems?以了解如何使用调试器来避免这种情况。|497604|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#valueOf(char[])|1|https://docs.oracle.com/javase/7/docs/api/java/util/Arrays.html#equals(char%255B%255D,%2520char%255B%255D%2529),%2520comparing%2520each%2520element%2520of%2520one%2520array%2520with%2520those%2520of%2520the%2520other%2520etc.|2|https://stackoverflow.com/questions/25385173/what-is-a-debugger-and-how-can-it-help-me-diagnose-problems^0|5|R|X|6|19|6|0|0|0|3|0|0|8|E|N|6|Y|6|1M|D|8|E|0|1M|D|1|0|0|0|H|I|H|22|6|29|6|2Q|1O|2|0^^$0|@$1|2|3|4|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1F|8|@$9|1G|A|1H|B|M]]|D|@]|E|$]]|$1|N|3|O|5|H|7|1I|8|@]|D|@]|E|$I|J]]|$1|P|3|Q|5|6|7|1J|8|@$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]|$9|1O|A|1P|B|C]|$9|1Q|A|1R|B|C]]|D|@$9|1S|A|1T|1|1U]|$9|1V|A|1W|1|1X]]|E|$]]|$1|R|3|S|5|6|7|1Y|8|@]|D|@]|E|$]]|$1|T|3|U|5|6|7|1Z|8|@$9|20|A|21|B|C]|$9|22|A|23|B|C]|$9|24|A|25|B|C]|$9|26|A|27|B|C]]|D|@$9|28|A|29|1|2A]]|E|$]]|$1|V|3|-4|5|6|7|2B|8|@]|D|@]|E|$]]]|W|$X|$5|Y|Z|10|E|$11|12]]|13|$5|Y|Z|10|E|$11|14]]|15|$5|Y|Z|10|E|$11|16]]]]

You can use <code>public String(char[] value)</code> to create a <code>String</code> out of the <code>char[]</code> e.g.
<pre><code>import java.util.Arrays;

public class Main {
 public static void main(String[] args) {
 System.out.println(isAnagram(&quot;anagram&quot;, &quot;nagaram&quot;));
 }

 public static boolean isAnagram(String s, String t) {
 char sArray[] = s.toCharArray();
 char tArray[] = t.toCharArray();
 Arrays.sort(sArray);
 Arrays.sort(tArray);
 s = new String(sArray);// Create String out of sArray
 t = new String(tArray);// Create String out of tArray
 return s.equals(t);
 }
}
</code></pre>
Output:
<pre><code>true
</code></pre>
Alternatively, you can use <a href="https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#valueOf(char%5B%5D)" rel="nofollow noreferrer"><code>String#valueOf</code></a> to create a <code>String</code> out of the <code>char[]</code>. There are many more solutions (e.g. comparing the char arrays directly using <a href="https://docs.oracle.com/javase/7/docs/api/java/util/Arrays.html#equals(char%5B%5D,%20char%5B%5D)" rel="nofollow noreferrer"><code>Arrays#equals</code></a>, comparing each element of one array with those of the other etc.) and I would recommend you try as many as you can for learning purpose.
<h2>What went wrong with your approach?</h2>
<code>sArray.toString()</code> and <code>tArray.toString()</code> return different strings which you could have found out by printing them or by debugging your code. The reason behind this difference is the difference in the hash code of <code>sArray</code> and <code>tArray</code>. Check <a href="https://stackoverflow.com/questions/25385173/what-is-a-debugger-and-how-can-it-help-me-diagnose-problems">What is a debugger and how can it help me diagnose problems?</a> to learn how to use a debugger to avoid such situations.

When I tried to take two strings as input to a function and check whether they are anagrams, I am getting the wrong output. I have written the following code.
<pre><code> class Solution {
 public boolean isAnagram(String s, String t) {
 char sArray[] = s.toCharArray();
 char tArray[] = t.toCharArray();
 Arrays.sort(sArray);
 Arrays.sort(tArray);
 s = sArray.toString();
 t = tArray.toString();
 return s.equals(t);
 
 }
}
</code></pre>
The sample input I have taken is <code>s = &quot;anagram&quot; and t = &quot;nagaram&quot;</code> . When checked, both the char arrays are printing the same value, i.e.
<pre><code>sArray is: 
aaagmnr
tArray is: 
aaagmnr
</code></pre>
But my output seems to be false. Could someone please help me why am I getting such result when I use <code>equals()</code> after <code>toString()</code>?

problem with equals() method when used after toString() method

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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当我试图将两个字符串作为函数的输入并检查它们是否为字谜时，我得到了错误的输出。我写了以下代码。    class Solution {    public boolean isAnagram(String s, String t) {        char sArray[] = s.toCharArray();   ...

问在toString()方法之后使用equals()方法时的问题
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