blocks|key|1709986|text|输入是一个对象数组，因此array.map：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1709987|let+newArray+=+[]
input.map(function(item)+{
++item.options.map(function(option)+{
++++newArray.push({name:item.name,+options:+option})
++})
})
console.log(newArray);|code-block|syntax|javascript|1709988|应起作用|1709989|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Input is an array of object so array.map:
<pre><code>let newArray = []
input.map(function(item) {
 item.options.map(function(option) {
 newArray.push({name:item.name, options: option})
 })
})
console.log(newArray);
</code></pre>
should work

blocks|key|817751|text|你应该用地图来转换数组，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|817752|arr+=+arr.map((element)+=>+{
++++const+temp+=+[];
++++element.options.forEach(option+=>+{
++++++++temp.push({
++++++++++++name:+element.name,
++++++++++++options:+option
++++++++});
++++})
++++return+temp;
}).flat();|code-block|syntax|javascript|817753|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You should use map to transform the array,
<pre class="lang-js prettyprint-override"><code>arr = arr.map((element) =&gt; {
 const temp = [];
 element.options.forEach(option =&gt; {
 temp.push({
 name: element.name,
 options: option
 });
 })
 return temp;
}).flat();
</code></pre>

blocks|key|1710023|text|是的，.reduce是要走的路，下面是一种方法：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1710024|​|1710025|const+input+=+[{name:+"audio",+options:[{name:'true',+value:+'T'},{name:'false',+value:+'F'},{name:'yes',+value:+'Y'}]},
++++{name:+"video",+options:[{name:'true',+value:+'T'},{name:'false',+value:+'F'},{name:'yes',+value:+'Y'}]},
++++{name:+"call",+options:[{name:'true',+value:+'T'},{name:'false',+value:+'F'},{name:'yes',+value:+'Y'}]}];

const+output+=+input.reduce((acc,+cur)+=>+{
++const+newEntries+=+cur.options.reduce((a,+c)+=>+([...a,+{+...cur,+options:+c+}]),+[]);
++return+[
++++++...acc,
++++++...newEntries
++++];
},[]);

console.log(output);|code-block|syntax|javascript|1710026|1710027|在本例中，我减少原始数组(input)，然后还原每个条目的options数组，为每个条目创建一个新元素，然后将这些新条目添加到返回数组中。|1710028|entityMap^0|3|7|0|0|0|0|D|5|T|7|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|V|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|W|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@]|E|$]]|$1|P|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|Q|$]]

Yes, <code>.reduce</code> is the way to go, here is a way of doing it:
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const input = [{name: "audio", options:[{name:'true', value: 'T'},{name:'false', value: 'F'},{name:'yes', value: 'Y'}]},
 {name: "video", options:[{name:'true', value: 'T'},{name:'false', value: 'F'},{name:'yes', value: 'Y'}]},
 {name: "call", options:[{name:'true', value: 'T'},{name:'false', value: 'F'},{name:'yes', value: 'Y'}]}];

const output = input.reduce((acc, cur) =&gt; {
 const newEntries = cur.options.reduce((a, c) =&gt; ([...a, { ...cur, options: c }]), []);
 return [
 ...acc,
 ...newEntries
 ];
},[]);

console.log(output);</code></pre>
</div>
</div>

In this example I'm reducing the original array (<code>input</code>) and then I'm reducing each entry's <code>options</code> array to create a new element for each of them, and then I'm adding these new entries to the return array.

blocks|key|1710036|text|您可以使用sort方法和localeCompare。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1710037|尝试如下：|BOLD|1710038|arr.sort((a,+b)+=>+a.name.localeCompare(b.name))|code-block|syntax|javascript|1710039|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare^0|5|4|C|D|C|D|0|0|0|5|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@$9|10|A|11|1|12]]|E|$]]|$1|F|3|G|5|6|7|13|8|@$9|14|A|15|B|H]]|D|@]|E|$]]|$1|I|3|J|5|K|7|16|8|@]|D|@]|E|$L|M]]|$1|N|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|O|$P|$5|Q|R|S|E|$T|U]]]]

You can use the <code>sort</code> method and <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare" rel="nofollow noreferrer"><code>localeCompare</code></a>.
Try This:
<pre><code>arr.sort((a, b) =&gt; a.name.localeCompare(b.name))
</code></pre>

blocks|key|833291|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|833292|let+output+=+[];

input.map(item+=>+{
++item.options.forEach(o+=>+{
++++output.push({
++++++name:+item.name,
++++++options:+{
++++++++name:+o.name,
++++++++value:+o.value
++++++}
++++});
++});
});|code-block|syntax|javascript|833293|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:
<pre><code>let output = [];

input.map(item =&gt; {
 item.options.forEach(o =&gt; {
 output.push({
 name: item.name,
 options: {
 name: o.name,
 value: o.value
 }
 });
 });
});
</code></pre>

I have an array with multiple objects having the same name. How can I segregate the array based on the name?
I tried with map, filter but didn't work finally I used reduce also but not getting the output.
<pre><code>const result = Object.values(this.optionsArr.reduce((a, c) =&gt; {
 a[c.name] = a[c.name] || {name: c.name};
 a[c.name].options.push(c.options);
 return a;
 }, {})).map(item =&gt; ({...item, accessDetails: Object.values(item.accessDetails)}));
</code></pre>
Input:
<pre><code>[
{name: &quot;audio&quot;, options: [
 {name:'true', value: 'T'},
 {name:'false', value: 'F'},
 {name:'yes', value: 'Y'}]
},
{name: &quot;video&quot;, options: [
 {name:'true', value: 'T'},
 {name:'false', value: 'F'},
 {name:'yes', value: 'Y'}]
},
{name: &quot;call&quot;, options: [
 {name:'true', value: 'T'},
 {name:'false', value: 'F'},
 {name:'yes', value: 'Y'}]
}]
</code></pre>
Expected Ouput:
<pre><code>const arr = [{name: &quot;audio&quot;, options:{name:'true', value: 'T'}},
{name: &quot;audio&quot;, options:{name:'false', value: 'F'}},
{name: &quot;audio&quot;, options:{name:'yes', value: 'Y'}},
{name: &quot;video&quot;, options:{name:'true', value: 'T'}},
{name: &quot;video&quot;, options:{name:'yes', value: 'Y'}},
{name: &quot;video&quot;, options:{name:'false', value: 'F'}},
{name: &quot;call&quot;, options:{name:'true', value: 'T'}},
{name: &quot;call&quot;, options:{name:'No', value: 'N'}},
{name: &quot;call&quot;, options:{name:'false', value: 'F'}}];
</code></pre>

how to open an array of object based on the name

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个具有相同名称的多个对象的数组。如何根据名称分隔数组？我试过用地图，过滤器，但没有工作，最后我用的也减少，但没有得到输出。const result = Object.values(this.optionsArr.reduce((a, c) => {        a[c.name] = a[c.name] || ...

问如何根据名称打开对象数组
EN

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问如何根据名称打开对象数组EN