我试图申请一些许可,我的应用程序内的启动活动。此活动只检查权限,并提示用户请求缺少权限。我想要做的是,在1.5秒后,如果用户被提示并接受/拒绝所需的权限,则启动主活动,显示应用程序的仪表板。现在的问题是,无论我做什么,onRequestPermissionResult都不会被调用,我也不明白问题是从何而来的。我提到成功地请求了权限,提示用户并能够接受它们或拒绝它们,但是回调不会以某种方式触发。
这是我的活动代码:
public class LauncherActivity extends AppCompatActivity {
public static final String TAG = LauncherActivity.class.getSimpleName();
private boolean permissionsGiven;
private static final String[] REQUIRED_PERMISSIONS =
new String[] {
Manifest.permission.BLUETOOTH,
Manifest.permission.BLUETOOTH_ADMIN,
Manifest.permission.ACCESS_WIFI_STATE,
Manifest.permission.CHANGE_WIFI_STATE,
Manifest.permission.ACCESS_COARSE_LOCATION,
Manifest.permission.ACCESS_FINE_LOCATION
};
private static final int REQUEST_CODE_REQUIRED_PERMISSIONS = 1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_launcher);
if (!hasPermissions(this, REQUIRED_PERMISSIONS)) {
permissionsGiven = false;
Log.d(TAG, "onCreate: app does not have all the required permissions. Requesting permissions...");
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
ActivityCompat.requestPermissions(
this,
REQUIRED_PERMISSIONS,
REQUEST_CODE_REQUIRED_PERMISSIONS
);
}
} else {
permissionsGiven = true;
}
Runnable enterApplication = new Runnable() {
@Override
public void run() {
while (!permissionsGiven);
SharedPreferences loginPreferences = getApplicationContext().getSharedPreferences("LOGIN_DETAILS", MODE_PRIVATE);
boolean signedIn = loginPreferences.getBoolean("signedIn", false);
if (!signedIn) {
Log.d(TAG, "onCreate: user is not signed in. Sending him to login activity...");
sendUserToLoginActivity();
} else {
sendUserToMainActivity();
}
}
};
Handler launcherHandler = new Handler();
launcherHandler.postDelayed(enterApplication, 1500);
}
private static boolean hasPermissions(Context context, String... permissions) {
for (String permission : permissions) {
if (ActivityCompat.checkSelfPermission(context, permission) != PackageManager.PERMISSION_GRANTED) {
return false;
}
}
return true;
}
@CallSuper
@Override
public void onRequestPermissionsResult(
int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
if (requestCode != REQUEST_CODE_REQUIRED_PERMISSIONS) {
return;
}
permissionsGiven = true;
for (int grantResult : grantResults) {
if (grantResult == PackageManager.PERMISSION_DENIED) {
Toast.makeText(this, "Missing permissions", Toast.LENGTH_LONG).show();
finish();
return;
}
}
recreate();
}
private void sendUserToLoginActivity() {
Log.d(TAG, "sendUserToLoginActivity: starting login activity...");
Intent loginIntent = new Intent(LauncherActivity.this, SignInActivity.class);
loginIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TASK | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(loginIntent);
finish();
}
private void sendUserToMainActivity() {
Log.d(TAG, "sendUserToMainActivity: starting main activity...");
Intent mainIntent = new Intent(LauncherActivity.this, MainActivity.class);
mainIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TASK | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(mainIntent);
finish();
}
}有人能帮我理解我做错了什么,怎么触发onRequestPermissionsResult,这样我就可以在应用程序中启动下一个活动了吗?
发布于 2020-09-01 18:20:15
重新创建();
我从没见过那种方法。
不要叫它做测试,而是放一个烤面包。
我不知道你怎么知道它不是被触发的。
此外,我不会使用等待变量更改其值的线程。
此外,你根本不需要线程。只需调用onCreate或onRequestPermissionsResult中的代码即可。您可以将所有的代码放在一个函数中。
https://stackoverflow.com/questions/63691864
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