我是一个C新手,我有这个代码,它应该是用红外线传感器测量树莓派的体温。代码运行良好,但不能在循环模式下运行,它只打印一次温度,然后退出。而我想让它持续运行,直到用户按下某个中断键/被用户杀死。
//gcc mlx90614.c -o mlx90614 -l bcm2835
#include <stdio.h>
#include <bcm2835.h>
#include <stdlib.h>
#include <fcntl.h>
#include <string.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>
#include <time.h>
#define AVG 1 //averaging samples
int main(int argc, char **argv)
{
unsigned char buf[6];
unsigned char i,reg;
double temp=0,calc=0, skytemp,atemp;
bcm2835_init();
bcm2835_i2c_begin();
bcm2835_i2c_set_baudrate(25000);
// set address
bcm2835_i2c_setSlaveAddress(0x5a);
printf("\ndevice is working!!\n");
calc=0;
reg=7;
for(i=0;i<AVG;i++)
{
bcm2835_i2c_begin();
bcm2835_i2c_write (®, 1);
bcm2835_i2c_read_register_rs(®,&buf[0],3);
temp = (double) (((buf[1]) << 8) + buf[0]);
temp = (temp * 0.02)-0.01;
temp = temp - 273.15;
calc+=temp;
sleep(1);
}
skytemp=calc/AVG;
calc=0;
reg=6;
for(i=0;i<AVG;i++){
bcm2835_i2c_begin();
bcm2835_i2c_write (®, 1);
bcm2835_i2c_read_register_rs(®,&buf[0],3);
temp = (double) (((buf[1]) << 8) + buf[0]);
temp = (temp * 0.02)-0.01;
temp = temp - 273.15;
calc+=temp;
sleep(1);
}
atemp=calc/AVG;
printf("ambient temperature = %04.2f\n", atemp);
printf("object temperature = %04.2f\n", skytemp);
printf("done\n");
return 0;
}编译
gcc mlx90614.c -o mlx90614 -l bcm2835
sudo ./mlx90614输出
device is working!!
ambient temperature = 30.06
object temperature=31.04
done发布于 2020-06-30 21:46:12
你需要一个无限循环。例如:
printf("\ndevice is working!!\n");
while(1)
{
calc=0;
reg=7;
...
printf("ambient temperature = %04.2f\n", atemp);
printf("object temperature = %04.2f\n", skytemp);
}
printf("done\n");https://stackoverflow.com/questions/62658799
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