从嵌套If语句返回变量的Python
从嵌套If语句返回变量的Python
提问于 2020-06-22 21:38:21
我是一个初学者，我想知道我如何管理程序去一个函数取决于一年是否是闰年。这是我的密码。也许我可以指示这个函数返回一个变量，该变量表示年份要么是常规年份，要么是闰年，根据结果变量，我可以选择下一个函数吗？我不知道该怎么做，或者有没有更好的方法。
def get_year():
print("Enter a year:")
year = int(input())
return year
def leap_year(year):
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("This is a leap year")
else:
print("This is not a leap year")
else:
print("This is a leap year")
else:
print("This is not a leap year")
def main():
months = ["January", "February", "March", "April", "May",
"June", "July", "August", "September", "October",
"November", "December"]
days_leap = [31, 29, 31, 30, 31, 30, 31, 30, 31, 30, 31, 30]
days = [31, 28, 31, 30, 31, 30, 31, 30, 31, 30, 31, 30]
year = get_year()
leap_year(year)
main()回答 3
Stack Overflow用户
回答已采纳
发布于 2020-06-22 21:42:29
你可以这样做：
def leap_year(year):
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("This is a leap year")
return True
else:
print("This is not a leap year")
return False
else:
print("This is a leap year")
return True
else:
print("This is not a leap year")
return False这样，你以后可以说：
if leap_year(year):
doAThing()
else:
doADifferentThing()Stack Overflow用户
发布于 2020-06-22 21:46:29
不要使用print()，而是使用return True、return False和result = leap_year(year)。当您拥有result时，您可以在其他函数中打印文本或使用result。
def get_year():
print("Enter a year:")
year = int(input())
return year
def leap_year(year):
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
return True
else:
return False
else:
return True
else:
return False
def main():
months = ["January", "February", "March", "April", "May",
"June", "July", "August", "September", "October",
"November", "December"]
days_leap = [31, 29, 31, 30, 31, 30, 31, 30, 31, 30, 31, 30]
days = [31, 28, 31, 30, 31, 30, 31, 30, 31, 30, 31, 30]
year = get_year()
result = leap_year(year)
if result:
print("This is a leap year")
else:
print("This is not a leap year")
main()Stack Overflow用户
发布于 2020-06-22 21:48:32
另一种可能性是：
year=int(input("Enter a year:"))
if(year%4==0 and year%100==0 and year%400==0):
print("This is a leap year")
else:
print("This is not a leap year")条件的组合直接提供了一个布尔值，您可以检查！简单的"if条件: do“与"if condition==True: do”相同。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/62523900
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