顺式解析BGP不描述其中一个邻居
顺式解析BGP不描述其中一个邻居
提问于 2020-06-20 06:02:37
我正在尝试使用ciscoconfparse将邻居、远程as和描述提取到字典中。然而，其中一个邻居没有描述。因此，它不会返回值。
有谁能帮助我们找到正确的方法来获取所有的邻居值吗？
Config:
router bgp 42098001
neighbor SERVER peer-group
neighbor SERVER remote-as 64700
neighbor 10.29.0.65 remote-as 1111
neighbor 10.29.0.65 description to ZZZ
neighbor 10.29.0.73 remote-as 2222
neighbor 10.29.0.73 description to AAA
neighbor 10.29.0.81 remote-as 3333
neighbor 10.29.0.81 description to BBB
neighbor 10.29.0.90 remote-as 4209800190
neighbor 10.29.0.90 description to ABC
neighbor 10.232.122.170 remote-as 64700
neighbor 10.232.122.170 description ABD
neighbor 10.237.34.2 remote-as 4209800192
neighbor 10.237.34.2 description to CCC bgp_as_name = confparse.find_all_children(r"^router bgp")
for details in bgp_as_name:
if 'remote-as' in details:
remote_ip = details.strip().rsplit(' ')[1]
as_number = details.strip().rsplit(' ')[3]
#print(remote_ip)
if 'description' in details:
description = details.strip().rsplit(' ')[3:]
desc = (' ').join(description)
bgp_as_ip.update({'description': desc})
print(bgp_as_ip)
#BGP route-map
bgp_route_map = confparse.find_all_children(r"^router bgp")
for routemap in bgp_route_map:
if 'route-map' in routemap:
bgp_routemap_slice1 = routemap.strip().split(' ')[0:2]
bgp_routemap_slice2 = routemap.strip().split(' ')[-2:]
bgp_routemap_combine = bgp_routemap_slice1 + bgp_routemap_slice2
bgp_route_map = bgp_routemap_combine[1:4]
print(bgp_route_map)
#bgp_as_ip.update({'route-map': bgp_route_map})
#print(bgp_as_ip)RESULT
{'remote_ip': '10.29.0.65', 'as_num': '1111', 'description': 'to ZZZ'}
{'remote_ip': '10.29.0.73', 'as_num': '2222', 'description': 'to AAA'}
{'remote_ip': '10.29.0.81', 'as_num': '3333', 'description': 'to BBB'}
{'remote_ip': '10.29.0.90', 'as_num': '4201', 'description': 'to ABC'}
{'remote_ip': '10.232.122.170', 'as_num': '64700', 'description': 'ABD'}
{'remote_ip': '10.237.34.2', 'as_num': '4209', 'description': 'to CCC'}>缺少的信息是邻居服务器
回答 1
Stack Overflow用户
发布于 2021-08-10 14:47:55
ciscoconfparse有一个名为re_match_typed()的方法，用于这种情况.
from pprint import pprint
from ciscoconfparse import CiscoConfParse
config_list = """router bgp 42098001
neighbor SERVER peer-group
neighbor SERVER remote-as 64700
neighbor 10.29.0.65 remote-as 1111
neighbor 10.29.0.65 description to ZZZ
neighbor 10.29.0.73 remote-as 2222
neighbor 10.29.0.73 description to AAA
neighbor 10.29.0.81 remote-as 3333
neighbor 10.29.0.81 description to BBB
neighbor 10.29.0.90 remote-as 4209800190
neighbor 10.29.0.90 description to ABC
neighbor 10.232.122.170 remote-as 64700
neighbor 10.232.122.170 description ABD
neighbor 10.237.34.2 remote-as 4209800192
neighbor 10.237.34.2 description to CCC
""".splitlines()
parse = CiscoConfParse(config_list)
nested_dict = dict()
for obj_cmd in parse.find_objects(r"^\s+neighbor"):
nei_ipv4 = obj_cmd.re_match_typed(r"^\s+neighbor\s+(\S+)", result_type=str)
nei_new_addr = nested_dict.get(nei_ipv4, False)
if nei_new_addr is False:
nested_dict[nei_ipv4] = dict()
if nested_dict[nei_ipv4].get("remote-as", None) is None:
nested_dict[nei_ipv4]["remote-as"] = obj_cmd.re_match_typed(
r"^\s*neighbor\s+{0}\s+remote-as\s+(\d+)\s*$".format(nei_ipv4),
untyped_default=True,
default=None,
)
if nested_dict[nei_ipv4].get("description", None) is None:
nested_dict[nei_ipv4]["description"] = obj_cmd.re_match_typed(
r"^\s*neighbor\s+{0}\s+description\s+(\S.*)\s*$".format(nei_ipv4),
untyped_default=True,
default=None,
)
pprint(nested_dict)运行这个输出是..。
{'10.232.122.170': {'description': 'ABD', 'remote-as': '64700'},
'10.237.34.2': {'description': 'to CCC', 'remote-as': '4209800192'},
'10.29.0.65': {'description': 'to ZZZ', 'remote-as': '1111'},
'10.29.0.73': {'description': 'to AAA', 'remote-as': '2222'},
'10.29.0.81': {'description': 'to BBB', 'remote-as': '3333'},
'10.29.0.90': {'description': 'to ABC ', 'remote-as': '4209800190'},
'SERVER': {'description': None, 'remote-as': '64700'}}我重新格式化了输出，但是更改示例以使用您的格式是很简单的.
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/62482245
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