blocks|key|639076|text|R基解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|639077|lapply(obj_list,+function(x){if(length(grep("D\\d%2B",+names(x)))+>+0){round(x,+3)}else{x}})|code-block|syntax|javascript|639078|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Base R solution: 

<pre><code>lapply(obj_list, function(x){if(length(grep("D\\d+", names(x))) &gt; 0){round(x, 3)}else{x}})
</code></pre>

blocks|key|639080|text|根据您的屏幕截图，问题似乎在于您的对象并不在您可以轻松处理的列表中，而只是作为值存储在您的全局环境(或.GlobalEnv)中。下面是使用ls()和getElement的解决方案|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|639081|lapply(ls(),+function(x)+{
++new_value+<-+round(getElement(.GlobalEnv,+x))
++assign(x,+new_value,+pos+=+.GlobalEnv)+#+re-assign+its+value+to+the+rounded+value
})|code-block|syntax|javascript|639082|ls()将列出.GlobalEnv+(您的全局环境)中的值和对象(所有内容)的名称。您可能需要使用grep来选择您想要的，这取决于里面还有什么。|639083|使用getElement，您可以以字符串的形式提供对象的名称(这就是ls()将如何返回它们，并从它们存在的位置提取它们的值。因此，您对getElement的第一个参数是.GlobalEnv，对象所在的位置。第二个参数是对象的名称。如果然后要在全局环境中更改其值，则可以使用assign函数从本质上覆盖它，这类似地允许您将值的名称指定为字符串，如果对象只是驻留在全局环境中，则.GlobalEnv作为position参数。|639084|entityMap^0|1F|A|1X|4|22|A|0|0|0|4|7|A|1D|4|0|2|A|Y|4|1V|A|2C|A|3S|6|57|A|5J|8|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|15|8|@$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|1K|8|@]|D|@]|E|$]]]|P|$]]

Based on your screenshot it looks like the issue is your objects are not in a list that you can easily work with, but simply stored as values in your global environment (or <code>.GlobalEnv</code>). Here is a workaround using <code>ls()</code> and <code>getElement</code>:

<pre><code>lapply(ls(), function(x) {
 new_value &lt;- round(getElement(.GlobalEnv, x))
 assign(x, new_value, pos = .GlobalEnv) # re-assign its value to the rounded value
})
</code></pre>

<code>ls()</code> will list the names of the values and objects (everything) in <code>.GlobalEnv</code> (your global environment). You may need to use <code>grep</code> to select just the ones you want, it depends what else is in there. 

With <code>getElement</code> you can then supply the names of the objects as character strings (which is how <code>ls()</code> will return them, and extract their values from whence they exist. So your first argument to <code>getElement</code> is <code>.GlobalEnv</code>, the location where the objects live. And the second argument is the name of the object. If you then want to change its value in the global environment, then you can use the <code>assign</code> function to essentially overwrite it, which similarly allows you to specify the name of the value, as a character string, and then <code>.GlobalEnv</code> as the <code>position</code> argument if the object simply lives in your global environment.

blocks|key|825725|text|由于我无法获取您的数据结构，所以我构建了一个类似的结构：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|825726|dfD+<-+data.frame(D+=+paste0("D",+sample(14:64,+12)),
++++++++++++++Dval+=+rnorm(12,+mean+=+20))

R+>+dfD
+++++D+++++Dval
1++D25+20.90942
2++D53+21.51484
3++D59+18.11695
4++D44+20.29304
5++D57+19.51578
6++D22+21.72018
7++D16+20.62322
8++D31+21.97484
9++D18+19.26036
10+D61+22.08744
11+D37+19.36332
12+D55+20.67799|code-block|syntax|javascript|825727|然后，我将所有的Dval舍入三位数：|offset|length|style|CODE|825728|library(tidyverse)
dfd3+<-++dfD+%25>%25+
+mutate(L3+=+round(Dval,+digits+=+3))

dfd3
R>+dfD
+++++D+++++Dval+++++L3
1++D25+20.90942+20.909
2++D53+21.51484+21.515
3++D59+18.11695+18.117
4++D44+20.29304+20.293
5++D57+19.51578+19.516
6++D22+21.72018+21.720
7++D16+20.62322+20.623
8++D31+21.97484+21.975
9++D18+19.26036+19.260
10+D61+22.08744+22.087
11+D37+19.36332+19.363
12+D55+20.67799+20.678|825729|我想这就是你要找的。|825730|entityMap^0|0|0|8|4|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Since I couldn't grab your data structure, I built a similar one:
<pre><code>dfD &lt;- data.frame(D = paste0(&quot;D&quot;, sample(14:64, 12)),
 Dval = rnorm(12, mean = 20))

R &gt; dfD
 D Dval
1 D25 20.90942
2 D53 21.51484
3 D59 18.11695
4 D44 20.29304
5 D57 19.51578
6 D22 21.72018
7 D16 20.62322
8 D31 21.97484
9 D18 19.26036
10 D61 22.08744
11 D37 19.36332
12 D55 20.67799
</code></pre>
Then I rounded all the <code>Dval</code> to three digits:
<pre><code>library(tidyverse)
dfd3 &lt;- dfD %&gt;% 
 mutate(L3 = round(Dval, digits = 3))

dfd3
R&gt; dfD
 D Dval L3
1 D25 20.90942 20.909
2 D53 21.51484 21.515
3 D59 18.11695 18.117
4 D44 20.29304 20.293
5 D57 19.51578 19.516
6 D22 21.72018 21.720
7 D16 20.62322 20.623
8 D31 21.97484 21.975
9 D18 19.26036 19.260
10 D61 22.08744 22.087
11 D37 19.36332 19.363
12 D55 20.67799 20.678
</code></pre>
I think that's what you're looking for.

I have a list of objects containing different numbers of data, on which I want to globally execute the same <code>round</code> function. Is there a way to do it in one go whilst keeping the objects separate (so that each object corresponds to the data it should contain), without having to go do it manually as follows?

<a href="https://i.stack.imgur.com/dXvcZ.png" rel="nofollow noreferrer">my code when trying to manually iterate the same function for each object</a>

Thanks,
Katie

Edit1:

<pre><code>&gt; D41
[1] 1.366 1.223 1.223 2.703 1.205 2.053
&gt; d44
[1] 8.929 13.793
&gt; D41r &lt;- round(D41,2)
&gt; d44r &lt;- round(d44,2)
&gt; D41r
[1] 1.37 1.22 1.22 2.70 1.21 2.05
&gt; d44r
[1] 8.93 13.79
</code></pre>

Here I just showed two objects out of the many more objects each with a different number of data.

Is there any way to do create a data frame that has "different number of rows", or to execute one function for each object overwriting itself correspondingly?

Applying same function to multiple objects in R (for-loop?)

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个包含不同数量数据的对象列表，我希望在这些数据上全局执行相同的round函数。是否有办法一次执行，同时保持对象独立(因此每个对象对应于它应该包含的数据)，而不必手动执行，如下所示？谢谢，凯蒂Edit1:> D41[1] 1.366 1.223 1.223 2.703 1.205 2.053> d44[1] 8.9...

问对R中的多个对象应用相同的函数(for-循环？)
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问对R中的多个对象应用相同的函数(for-循环？)EN