blocks|key|886289|text|对于位置参数，您必须传递相同数量的参数。您可以使用默认的参数概念，例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|886290|def+divide(num1=1,num2=1):
++++try:
++++++++return+num1/num2
++++except+TypeError:
++++++++return+"Please+provide+two+integers+or+floats"
++++except+ZeroDivisionError:
++++++++return+"Please+do+not+divide+by+zero"|code-block|syntax|javascript|886291|可以使用0、1或2个参数调用此函数。|886292|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

For positional parameters, you have to pass the same number of arguments. You can use the default argument concept, like : 

<pre><code>def divide(num1=1,num2=1):
 try:
 return num1/num2
 except TypeError:
 return "Please provide two integers or floats"
 except ZeroDivisionError:
 return "Please do not divide by zero"
</code></pre>

You can call this function using 0,1 or 2 arguments.

blocks|key|4645343|text|因为try/except语句捕获该异常并返回指定的消息。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4645344|试着做这样的事情：|4645345|try:
+++if+num1+and+num2:
++++++return+num1+/+num2
+++else:
++++++return+"Please+provide+two+numbers"
except+ZeroDivisionError:
+++return+"Please+do+not+divide+by+zero"
except+TypeError:
+++return+"Please+provide+two+integers+or+floats"|code-block|syntax|javascript|4645346|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Because your try/except statement is catching that exception and returning the designated message.

Try something like this:

<pre><code>try:
 if num1 and num2:
 return num1 / num2
 else:
 return "Please provide two numbers"
except ZeroDivisionError:
 return "Please do not divide by zero"
except TypeError:
 return "Please provide two integers or floats"
</code></pre>

blocks|key|886332|text|如果不提供所有所需的参数，则函数将永远不会输入，因此无法从函数内部捕获该TypeError。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|886333|为了举例说明，请考虑一个立即出错的函数：|886334|>>>+def+func(a,+b,+c):
...+++++raise+Exception("inside+the+function")
...|code-block|syntax|javascript|886335|现在，让我们用所需的参数调用它：|886336|>>>+func(1,+2,+3)
Traceback+(most+recent+call+last):
++File+"<stdin>",+line+1,+in+<module>
++File+"<stdin>",+line+2,+in+func
Exception:+inside+the+function|886337|在这里，您可以从跟踪(in+func)中看到输入了函数，并从那里抛出了错误。但是，如果我们在没有争论的情况下再次调用它：|886338|>>>+func()
Traceback+(most+recent+call+last):
++File+"<stdin>",+line+1,+in+<module>
TypeError:+func()+takes+exactly+3+arguments+(0+given)|886339|注意，追溯不包括in+func，错误发生在输入函数体之前。您只能在函数之外捕获它：|886340|>>>+try:
...+++++func()
...+except+TypeError:
...+++++print('oh+no!')
...
oh+no!|886341|entityMap^0|10|9|0|0|0|0|0|B|7|0|0|8|7|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|15|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|16|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|S|3|T|5|J|7|1A|8|@]|D|@]|E|$K|L]]|$1|U|3|V|5|6|7|1B|8|@$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|W|3|X|5|J|7|1E|8|@]|D|@]|E|$K|L]]|$1|Y|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|Z|$]]

If you don't supply all of the required arguments, the function is never entered, so there's no way to catch that <code>TypeError</code> from inside the function.

To illustrate, consider a function that immediately errors out:

<pre><code>&gt;&gt;&gt; def func(a, b, c):
... raise Exception("inside the function")
...
</code></pre>

Now let's call it with the required arguments:

<pre><code>&gt;&gt;&gt; func(1, 2, 3)
Traceback (most recent call last):
 File "&lt;stdin&gt;", line 1, in &lt;module&gt;
 File "&lt;stdin&gt;", line 2, in func
Exception: inside the function
</code></pre>

Here you can see from the traceback (<code>in func</code>) that the function was entered and the error thrown from there. However, if we call it again without the arguments:

<pre><code>&gt;&gt;&gt; func()
Traceback (most recent call last):
 File "&lt;stdin&gt;", line 1, in &lt;module&gt;
TypeError: func() takes exactly 3 arguments (0 given)
</code></pre>

Note that the traceback doesn't include <code>in func</code>, the error happens before entering the function body. You can only catch it outside the function:

<pre><code>&gt;&gt;&gt; try:
... func()
... except TypeError:
... print('oh no!')
...
oh no!
</code></pre>

<pre><code>def divide(num1,num2):
 try:
 return num1/num2
 except TypeError:
 return "Please provide two integers or floats"
 except ZeroDivisionError:
 return "Please do not divide by zero"
</code></pre>

Why do I get a TypeError if I pass only one argument?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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def divide(num1,num2):    try:        return num1/num2    except TypeError:        return "Please provide two integers or floats"    except ZeroDivisionError:  ...

问如果我只传递一个参数，为什么我会得到一个TypeError？
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问如果我只传递一个参数，为什么我会得到一个TypeError？EN