blocks|key|4753222|text|下面是一种快速而肮脏的方法来平平您的对象：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4753223|var+enrollment+=+{
++++user:+{
++++++++id:+'string',
++++++++name:+'string',
++++},
++++fineshed:+true,
++++path:+false,
};

var+user+=+Object.assign(enrollment.user);
user.fineshed+=+enrollment.fineshed;
user.path+=+enrollment.path;|code-block|syntax|javascript|4753224|4753225|对于一个泛型方法，有几个没有共享密钥名的警告，并且只有1级深度：|4753226|​|4753227|var+enrollment+=+{
	user:+{
		id:+'string',
		name:+'string',
	},
	fineshed:+true,
	path:+false,
};

const+flatten+=+(object)+=>+{
	let+value+=+{};
	for+(var+property+in+object)+{
		if+(typeof+object[property]+===+'object')+{
			for+(var+p+in+object[property])+{
				value[p]+=+object[property][p];
			}
		}+else+{
			value[property]+=+object[property];
		}
	}

	return+value;
};

let+user+=+flatten(enrollment);

console.log(user);|4753228|4753229|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|S|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|T|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|U|8|@]|9|@]|A|$]]|$1|L|3|M|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|N|3|K|5|6|7|W|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|P|$]]

<p>Here's a quick and dirty way to flatten your object:</p>

<pre class="lang-js prettyprint-override"><code>var enrollment = {
    user: {
        id: 'string',
        name: 'string',
    },
    fineshed: true,
    path: false,
};

var user = Object.assign(enrollment.user);
user.fineshed = enrollment.fineshed;
user.path = enrollment.path;
</code></pre>

<hr>

<p>For a generic method with a couple of caveats of no shared key names and only flattening 1 level of depth:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var enrollment = {
	user: {
		id: 'string',
		name: 'string',
	},
	fineshed: true,
	path: false,
};

const flatten = (object) =&gt; {
	let value = {};
	for (var property in object) {
		if (typeof object[property] === 'object') {
			for (var p in object[property]) {
				value[p] = object[property][p];
			}
		} else {
			value[property] = object[property];
		}
	}

	return value;
};

let user = flatten(enrollment);

console.log(user);</code></pre>
</div>
</div>
</p>


blocks|key|3517090|text|只想要一个对象：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3517091|​|3517092|const+enrollment+=+{
++user:+{
++++id:+'string',
++++name:+'string'
++},
++finished:+'boolean',
++path:+'boolean'
}
function+propsToUser(enrollObj){
++const+u+=+{...enrollObj.user};
++for(let+i+in+enrollObj){
++++if(i+!==+'user')u[i]+=+enrollObj[i];
++}
++return+u;
}
const+user+=+propsToUser(enrollment);
console.log(user);|code-block|syntax|javascript|3517093|3517094|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>Just want a single Object:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const enrollment = {
  user: {
    id: 'string',
    name: 'string'
  },
  finished: 'boolean',
  path: 'boolean'
}
function propsToUser(enrollObj){
  const u = {...enrollObj.user};
  for(let i in enrollObj){
    if(i !== 'user')u[i] = enrollObj[i];
  }
  return u;
}
const user = propsToUser(enrollment);
console.log(user);</code></pre>
</div>
</div>
</p>


blocks|key|3517135|text|您可以递归地构建对象，任意数量的嵌套对象。因此，这个函数不是依赖于情况的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3517136|​|3517137|var+enrollment+=+{
user:+{
++++id:+'string',
++++name:+'string'
},
finished:+'boolean',
path:+'boolean'
}

var+enrollment2+=+{
user:+{
++++id:+'string',
++++name:+'string'
},
test:+{
++++test1:+{
++++++++test2:+{
++++++++++++val0:'val0',
++++++++++++test4:+{+//3rd+level+nested+object+for+example
++++++++++++++++val1:+'val1',
++++++++++++++++val2:+'val2'
++++++++++++}
++++++++}
++++}
},
finished:+'boolean',
path:+'boolean'
}

const+flat+=+(obj,+out)+=>+{
++++Object.keys(obj).forEach(key+=>+{
++++++++if+(typeof+obj[key]+==+'object')+{
++++++++++++out+=+flat(obj[key],+out)+//recursively+call+for+nesteds
++++++++}+else+{
++++++++++++out[key]+=+obj[key]+//direct+assign+for+values
++++++++}

++++})
++++return+out
}

console.log(flat(enrollment,+{}))
console.log(flat(enrollment2,+{}))|code-block|syntax|javascript|3517138|3517139|entityMap^0|S|8|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|T|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|O|$]]

<p>You can <strong>recursively</strong> build object any number of nested objects. So, this function <strong>is not your case dependent</strong>:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var enrollment = {
user: {
    id: 'string',
    name: 'string'
},
finished: 'boolean',
path: 'boolean'
}

var enrollment2 = {
user: {
    id: 'string',
    name: 'string'
},
test: {
    test1: {
        test2: {
            val0:'val0',
            test4: { //3rd level nested object for example
                val1: 'val1',
                val2: 'val2'
            }
        }
    }
},
finished: 'boolean',
path: 'boolean'
}

const flat = (obj, out) =&gt; {
    Object.keys(obj).forEach(key =&gt; {
        if (typeof obj[key] == 'object') {
            out = flat(obj[key], out) //recursively call for nesteds
        } else {
            out[key] = obj[key] //direct assign for values
        }

    })
    return out
}

console.log(flat(enrollment, {}))
console.log(flat(enrollment2, {}))</code></pre>
</div>
</div>
</p>


blocks|key|993420|text|我需要一些避免重写键的东西，的名称与原始对象中不同级别的名称相同。所以我写了如下：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|993421|​|993422|const+flattenObject+=+(obj,+parentKey+=+'')+=>+{
++++if+(parentKey+!==+'')+parentKey+%2B=+'.';
++++let+flattened+=+{};
++++Object.keys(obj).forEach((key)+=>+{
++++++++if+(typeof+obj[key]+===+'object'+&&+obj[key]+!==+null)+{
++++++++++++Object.assign(flattened,+flattenObject(obj[key],+parentKey+%2B+key))
++++++++}+else+{
++++++++++++flattened[parentKey+%2B+key]+=+obj[key]
++++++++}
++++})
++++return+flattened;
}

var+test+=+{
++++foo:+'bar',
++++some:+'thing',
++++father:+{
++++++++son1:+'son1+value',
++++++++son2:+{
++++++++++++grandchild:+'grandchild+value',
++++++++++++duplicatedKey:+'note+this+is+also+used+in+first+level',
++++++++},
++++},
++++duplicatedKey:+'note+this+is+also+used+inside+son2',
}

let+flat+=+flattenObject(test);
console.log(flat);

//+how+to+access+the+flattened+keys:
let+a+=+flat['father.son2.grandchild'];
console.log(a);|code-block|syntax|javascript|993423|993424|还检查对象是否为null，因为我在使用中遇到了一些问题。|993425|entityMap^0|5|9|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|V|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|W|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|X|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|Q|$]]

<p>I needed something that <strong>avoids rewriting keys</strong> with the same name that were in different levels in the original object. So I wrote the following:</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const flattenObject = (obj, parentKey = '') =&gt; {
    if (parentKey !== '') parentKey += '.';
    let flattened = {};
    Object.keys(obj).forEach((key) =&gt; {
        if (typeof obj[key] === 'object' &amp;&amp; obj[key] !== null) {
            Object.assign(flattened, flattenObject(obj[key], parentKey + key))
        } else {
            flattened[parentKey + key] = obj[key]
        }
    })
    return flattened;
}

var test = {
    foo: 'bar',
    some: 'thing',
    father: {
        son1: 'son1 value',
        son2: {
            grandchild: 'grandchild value',
            duplicatedKey: 'note this is also used in first level',
        },
    },
    duplicatedKey: 'note this is also used inside son2',
}

let flat = flattenObject(test);
console.log(flat);

// how to access the flattened keys:
let a = flat['father.son2.grandchild'];
console.log(a);</code></pre>
</div>
</div>
</p>
<p>Also checks if the object is null, as I was having some problems with that in my usage.</p>


blocks|key|993443|text|下面的代码片段接受嵌套的输入对象，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|993444|{
++++++++name:'Namig',
++++++++surname:'Hajiyev',
++++++++address:{
++++++++++++city:'Sumgait',
++++++++++++country:'Azerbaijan',
++++++++++++geo:+{
++++++++++++++++lat:'40.5897200',
++++++++++++++++long:'49.6686100'
++++++++++++}
++++++++}
++++}|code-block|syntax|javascript|993445|并返回结果扁平对象，如下所示：|993446|{
++"name":+"Namig",
++"surname":+"Hajiyev",
++"address.city":+"Sumgait",
++"address.country":+"Azerbaijan",
++"address.geo.lat":+"40.5897200",
++"address.geo.long":+"49.6686100"
}|993447|这是我的代码：|993448|​|993449|function+flattenObject(obj,+newObj,+prefix)+{
++++newObj+=+newObj+%7C%7C+{};
++++prefix+=+prefix+%7C%7C+"";
++++for+(var+key+in+obj)+{
++++++++if+(obj.hasOwnProperty(key))+{
++++++++++++const+type+=+typeof+obj[key];
++++++++++++const+newKey+=+!!prefix+?+prefix+%2B+"."+%2B+key+:+key;
++++++++++++if+(type+===+"string")+{
++++++++++++++++newObj[newKey]+=+obj[key];
++++++++++++}
++++++++++++else+if+(type+===+"object")+{
++++++++++++++++flattenObject(obj[key],+newObj,+newKey);
++++++++++++}
++++++++}
++++}
++++return+newObj;
}

var+obj+=+{
++++name:'Namig',
++++surname:'Hajiyev',
++++address:{
++++++++city:'Sumgait',
++++++++country:'Azerbaijan',
++++++++geo:+{
++++++++++++lat:'40.5897200',
++++++++++++long:'49.6686100'
++++++++}
++++}
}

console.log(flattenObject(obj));|993450|993451|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|V|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|X|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|Y|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|Q|3|N|5|6|7|10|8|@]|9|@]|A|$]]|$1|R|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|S|$]]

<p>Below code snippet takes nested input object like this :</p>
<pre><code>{
        name:'Namig',
        surname:'Hajiyev',
        address:{
            city:'Sumgait',
            country:'Azerbaijan',
            geo: {
                lat:'40.5897200',
                long:'49.6686100'
            }
        }
    }
</code></pre>
<p>and returns result flattened object like this:</p>
<pre><code>{
  &quot;name&quot;: &quot;Namig&quot;,
  &quot;surname&quot;: &quot;Hajiyev&quot;,
  &quot;address.city&quot;: &quot;Sumgait&quot;,
  &quot;address.country&quot;: &quot;Azerbaijan&quot;,
  &quot;address.geo.lat&quot;: &quot;40.5897200&quot;,
  &quot;address.geo.long&quot;: &quot;49.6686100&quot;
}
</code></pre>
<p>Here is my code :</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function flattenObject(obj, newObj, prefix) {
    newObj = newObj || {};
    prefix = prefix || "";
    for (var key in obj) {
        if (obj.hasOwnProperty(key)) {
            const type = typeof obj[key];
            const newKey = !!prefix ? prefix + "." + key : key;
            if (type === "string") {
                newObj[newKey] = obj[key];
            }
            else if (type === "object") {
                flattenObject(obj[key], newObj, newKey);
            }
        }
    }
    return newObj;
}

var obj = {
    name:'Namig',
    surname:'Hajiyev',
    address:{
        city:'Sumgait',
        country:'Azerbaijan',
        geo: {
            lat:'40.5897200',
            long:'49.6686100'
        }
    }
}

console.log(flattenObject(obj));</code></pre>
</div>
</div>
</p>


blocks|key|993492|text|使用递归和约简。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|993493|注意，如果值本身是一个包含对象的数组，则可能需要添加另一个检查，如!Array.isArray(value)，取决于您的情况。|offset|length|style|CODE|993494|function+flatObj(obj)+{
++return+Object.entries(obj).reduce(
++++(flatted,+[key,+value])+=>
++++++typeof+value+==+"object"
++++++++?+{+...flatted,+...flatObj(value)+}
++++++++:+{+...flatted,+[key]:+value+},
++++{}
++);
}|code-block|syntax|javascript|993495|entityMap^0|0|X|L|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|S|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<p>using recursion and reduce.</p>
<p>note that if value itself is an array containing objects, you might want add another check like <code>!Array.isArray(value)</code> depending on your case</p>
<pre><code>function flatObj(obj) {
  return Object.entries(obj).reduce(
    (flatted, [key, value]) =&gt;
      typeof value == &quot;object&quot;
        ? { ...flatted, ...flatObj(value) }
        : { ...flatted, [key]: value },
    {}
  );
}
</code></pre>


<p>I have some attributes from a nested object that is inside the parent object but I would like to merge nested object with the parent object to be flatten.</p>

<p>Original object:</p>

<pre class="lang-js prettyprint-override"><code>enrollment = {
  user: {
    id: 'string',
    name: 'string'
  },
  finished: 'boolean',
  path: 'string'
}
</code></pre>

<p>expected flatten object:</p>

<pre class="lang-js prettyprint-override"><code>user: {
  id: 'string',
  name: 'string',
  finished: 'boolean',
  path: 'string'
}
</code></pre>


How to flatten an object with nested objects in javascript

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有来自父对象内部的嵌套对象的一些属性，但我希望将嵌套对象与父对象合并为扁平对象。原始对象：enrollment = {  user: {    id: 'string',    name: 'string'  },  finished: 'boolean',  path: 'string'}预期扁平物体：user: ...

问如何使用javascript中的嵌套对象来平平对象
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问如何使用javascript中的嵌套对象来平平对象EN