Javascript数组获取子路径
Javascript数组获取子路径
提问于 2020-04-19 21:46:11
我有以下数组
{
"id": "parent",
"code": "parent",
"children": [
{
"id": "rtsp",
"code": "rtsp",
"children": [
{
"id": "001",
"code": "cam30",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "002",
"code": "cam31",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "003",
"code": "cam32",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "004",
"code": "cam10",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "005",
"code": "cam11",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "006",
"code": "cam12",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "007",
"code": "cam13",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "008",
"code": "cam14",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "009",
"code": "cam15",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "010",
"code": "cam16",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "011",
"code": "cam17",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "012",
"code": "cam18",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "013",
"code": "cam19",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "014",
"code": "cam9",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "015",
"code": "cam7",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "016",
"code": "cam8",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "017",
"code": "cam5",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
},
{
"id": "018",
"code": "cam6",
"source": "rtsp://192.168.43.29:8554/test",
"sourceFullScreen": "rtsp://192.168.43.29:8554/test"
}
]
},
{
"id": "test",
"code": "test",
"children": [
{
"id": "cam100",
"code": "cam100",
"source": "cam100",
"sourceFullScreen": "cam100"
},
{
"id": "zone-a",
"code": "zone-a",
"children": [
{
"id": "cam100a",
"code": "cam100a",
"source": "cam100a",
"sourceFullScreen": "cam100a"
}
]
},
{
"id": "cam101",
"code": "cam101",
"source": "changed",
"sourceFullScreen": "changed"
},
{
"id": "cam102",
"code": "cam102",
"source": "cam102",
"sourceFullScreen": "cam102"
},
{
"id": "cam103",
"code": "cam103",
"source": "cam102",
"sourceFullScreen": "cam102"
},
{
"id": "cam105",
"code": "cam105",
"source": "cam105",
"sourceFullScreen": "cam105"
}
]
},
{
"id": "entrepot",
"code": "entrepot",
"children": [
{
"id": "cam1100",
"code": "cam1100",
"source": "rtsp://125.122.15.12",
"sourceFullScreen": "rtsp://125.22.122.11"
},
{
"id": "safe zone",
"code": "safe zone",
"children": []
}
]
},
{
"id": "zsd",
"code": "sdf",
"children": []
},
{
"id": "za",
"code": "aze",
"children": []
},
{
"id": "qsd",
"code": "azeqsd",
"children": []
}
]
}我想要写一个函数，在这个函数中，给定一个代码值，它会给我返回完整的路径。是否有任何带有m de函数的数组包，为此目的，我尝试了npm数组工具，但是没有成功，a.where(json, { "id": idValue })给出了一个空数组，我希望递归地展示它。
我需要的东西看起来像
searchPath(array,"003") ==> "003,rtsp,parent"
回答 3
Stack Overflow用户
回答已采纳
发布于 2020-04-19 23:26:52
谢谢你的回答，它帮助我学到了一些东西，然而，这是我的解决方案，完全符合我的需要。
function getCamPath(idValue) {
console.log("++++++++++++++++" + idValue);
found_path = "";
var path = "zone -";
function search(path, obj, target) {
var found = false;
for (var k in obj) {
if (obj.hasOwnProperty(k))
if (obj[k] === target){
value = obj.code
if(value)
return path + "-" + value+ "-"
else return path;
}
else if (typeof obj[k] === "object") {
value = obj.code
var result
if(value)
result = search(path + "-" + obj.code + "-", obj[k], target);
else result = search(path , obj[k], target);
if (result)
return result;
}
}
return false;
}
var path = search(path,json,idValue);
console.log("++++++++++++++++" + path);
return path;
}Stack Overflow用户
发布于 2020-04-19 22:02:17
Very similar task。您应该保存所有路径，并在找到值(键)时返回此路径。
Stack Overflow用户
发布于 2020-04-19 22:17:05
1.扁平对象2.获取键3.查找键
const flatten = (obj, prefix = '', res = {}) =>
Object.entries(obj).reduce((r, [key, val]) => {
const k = `${prefix}${key}`
if(typeof val === 'object'){
flatten(val, `${k}.`, r)
} else {
res[k] = val
}
return r
}, res)
const flattendObj = flatten(obj);
const found_path = Object.keys(falttendObj).find(key => key === match)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/61312040
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