我有以下字符串:
start = "07:00:00"
end = "17:00:00"如何在两次之间生成5分钟间隔的列表?
["07:00:00","07:05:00",...,"16:55:00","17:00:00"]发布于 2020-03-25 14:43:15
这对我来说是可行的,我相信你可以想办法把结果放到列表中,而不是打印出来:
>>> import datetime
>>> start = "07:00:00"
>>> end = "17:00:00"
>>> delta = datetime.timedelta(minutes=5)
>>> start = datetime.datetime.strptime( start, '%H:%M:%S' )
>>> end = datetime.datetime.strptime( end, '%H:%M:%S' )
>>> t = start
>>> while t <= end :
... print datetime.datetime.strftime( t, '%H:%M:%S')
... t += delta
...
07:00:00
07:05:00
07:10:00
07:15:00
07:20:00
07:25:00
07:30:00
07:35:00
07:40:00
07:45:00
07:50:00
07:55:00
08:00:00
08:05:00
08:10:00
08:15:00
08:20:00
08:25:00
08:30:00
08:35:00
08:40:00
08:45:00
08:50:00
08:55:00
09:00:00
09:05:00
09:10:00
09:15:00
09:20:00
09:25:00
09:30:00
09:35:00
09:40:00
09:45:00
09:50:00
09:55:00
10:00:00
10:05:00
10:10:00
10:15:00
10:20:00
10:25:00
10:30:00
10:35:00
10:40:00
10:45:00
10:50:00
10:55:00
11:00:00
11:05:00
11:10:00
11:15:00
11:20:00
11:25:00
11:30:00
11:35:00
11:40:00
11:45:00
11:50:00
11:55:00
12:00:00
12:05:00
12:10:00
12:15:00
12:20:00
12:25:00
12:30:00
12:35:00
12:40:00
12:45:00
12:50:00
12:55:00
13:00:00
13:05:00
13:10:00
13:15:00
13:20:00
13:25:00
13:30:00
13:35:00
13:40:00
13:45:00
13:50:00
13:55:00
14:00:00
14:05:00
14:10:00
14:15:00
14:20:00
14:25:00
14:30:00
14:35:00
14:40:00
14:45:00
14:50:00
14:55:00
15:00:00
15:05:00
15:10:00
15:15:00
15:20:00
15:25:00
15:30:00
15:35:00
15:40:00
15:45:00
15:50:00
15:55:00
16:00:00
16:05:00
16:10:00
16:15:00
16:20:00
16:25:00
16:30:00
16:35:00
16:40:00
16:45:00
16:50:00
16:55:00
17:00:00
>>>发布于 2020-03-25 14:44:18
Try
# import modules
from datetime import datetime, timedelta
# Create starting and end datetime object from string
start = datetime.strptime("07:00:00", "%H:%M:%S")
end = datetime.strptime("17:00:00", "%H:%M:%S")
# min_gap
min_gap = 5
# compute datetime interval
arr = [(start + timedelta(hours=min_gap*i/60)).strftime("%H:%M:%S")
for i in range(int((end-start).total_seconds() / 60.0 / min_gap))]
print(arr)
# ['07:00:00', '07:05:00', '07:10:00', '07:15:00', '07:20:00', '07:25:00', '07:30:00', ..., '16:55:00']解释
(end-start).total_seconds() / 60.0然而,在我们的例子中,我们只想迭代每一个n分钟。所以,在我们的loop中,我们需要用n除以它。
此外,由于我们将迭代这个时间数,我们需要将int转换为for循环。其结果是:
int((end-start).total_seconds() / 60.0 / min_gap)https://stackoverflow.com/questions/60850957
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